Answer
Verified
468.6k+ views
Hint: Let us assume the radius and height of the cylinder as ‘r’ and h respectively. We have given the volume and curved surface area of the cylinder. We know that the formula for the volume of the cylinder is $\pi {{r}^{2}}h$ and the formula for the curved surface area is $2\pi rh$. Now, equating the volume and curved surface area that we have just mentioned to 1650 and 660. Now, we have two equations and two unknowns so we can find the value of r and h.
Complete step-by-step solution:
We have given the volume and curved surface area of the cylinder as 1650 cubic cm and 660 sq. cm respectively.
Let us assume that the radius and height of the cylinder are r and h respectively.
In the below diagram, we have shown a cylinder with radius (r) and height (h).
We know the formula for volume of the cylinder is equal to:
$\pi {{r}^{2}}h$
Equating the above volume to 1650 we get,
$\pi {{r}^{2}}h=1650$……… Eq. (1)
We know the formula for curved surface area of the cylinder is:
$2\pi rh$
Equating the above curved surface area to 660 we get,
$2\pi rh=660$…………. Eq. (2)
Now, we have two equations and two unknowns r and h which we are going to solve by dividing eq. (1) by eq. (2).
$\dfrac{\pi {{r}^{2}}h}{2\pi rh}=\dfrac{1650}{660}$
In the above equation, $\pi ,r,h$ will be cancelled out from the numerator and the denominator we get,
$\dfrac{r}{2}=\dfrac{165}{66}$
Multiplying 2 on both the sides we get
$\begin{align}
& r=\dfrac{165\times 2}{66}=\dfrac{330}{66} \\
& \Rightarrow r=5cm \\
\end{align}$
Substituting the above value of r in eq. (2) we get,
$2\pi \left( 5 \right)h=660$
Substituting the value of $\pi $ as $\dfrac{22}{7}$ in the above equation we get,
$\begin{align}
& 2\left( \dfrac{22}{7} \right)\left( 5 \right)h=660 \\
& \Rightarrow \dfrac{220}{7}h=660 \\
\end{align}$
Cross multiplying the above equation we get,
$\begin{align}
& 220h=660\left( 7 \right) \\
& \Rightarrow 220h=4620 \\
& \Rightarrow h=\dfrac{4620}{220} \\
& \Rightarrow h=21cm \\
\end{align}$
Hence, we have got the value of radius (r) as 5 cm and height (h) as 21 cm.
Note: You can verify that the value of the radius and height of the cylinder that you solved above is correct or not by substituting these values in the formula of the curved surface area of the cylinder.
The formula of curved surface area for cylinder is equal to:
$2\pi rh$
Substituting the value of r and h as 5 cm and 21 cm respectively in the above equation we get,
$2\left( \dfrac{22}{7} \right)\left( 5 \right)\left( 21 \right)$
21 will be cancelled out 3 times by 7 in the above expression and we get,
$\begin{align}
& 2\left( 22 \right)\left( 5 \right)\left( 3 \right) \\
& =660c{{m}^{2}} \\
\end{align}$
Now, as you can see in the question given above, the curved surface area of the cylinder is $660c{{m}^{2}}$ which is matching with the value of curved surface area that we have just calculated by putting r and h as 5cm and 21 cm respectively.
Hence, the value of the radius and height of the cylinder that we are getting is correct.
Complete step-by-step solution:
We have given the volume and curved surface area of the cylinder as 1650 cubic cm and 660 sq. cm respectively.
Let us assume that the radius and height of the cylinder are r and h respectively.
In the below diagram, we have shown a cylinder with radius (r) and height (h).
We know the formula for volume of the cylinder is equal to:
$\pi {{r}^{2}}h$
Equating the above volume to 1650 we get,
$\pi {{r}^{2}}h=1650$……… Eq. (1)
We know the formula for curved surface area of the cylinder is:
$2\pi rh$
Equating the above curved surface area to 660 we get,
$2\pi rh=660$…………. Eq. (2)
Now, we have two equations and two unknowns r and h which we are going to solve by dividing eq. (1) by eq. (2).
$\dfrac{\pi {{r}^{2}}h}{2\pi rh}=\dfrac{1650}{660}$
In the above equation, $\pi ,r,h$ will be cancelled out from the numerator and the denominator we get,
$\dfrac{r}{2}=\dfrac{165}{66}$
Multiplying 2 on both the sides we get
$\begin{align}
& r=\dfrac{165\times 2}{66}=\dfrac{330}{66} \\
& \Rightarrow r=5cm \\
\end{align}$
Substituting the above value of r in eq. (2) we get,
$2\pi \left( 5 \right)h=660$
Substituting the value of $\pi $ as $\dfrac{22}{7}$ in the above equation we get,
$\begin{align}
& 2\left( \dfrac{22}{7} \right)\left( 5 \right)h=660 \\
& \Rightarrow \dfrac{220}{7}h=660 \\
\end{align}$
Cross multiplying the above equation we get,
$\begin{align}
& 220h=660\left( 7 \right) \\
& \Rightarrow 220h=4620 \\
& \Rightarrow h=\dfrac{4620}{220} \\
& \Rightarrow h=21cm \\
\end{align}$
Hence, we have got the value of radius (r) as 5 cm and height (h) as 21 cm.
Note: You can verify that the value of the radius and height of the cylinder that you solved above is correct or not by substituting these values in the formula of the curved surface area of the cylinder.
The formula of curved surface area for cylinder is equal to:
$2\pi rh$
Substituting the value of r and h as 5 cm and 21 cm respectively in the above equation we get,
$2\left( \dfrac{22}{7} \right)\left( 5 \right)\left( 21 \right)$
21 will be cancelled out 3 times by 7 in the above expression and we get,
$\begin{align}
& 2\left( 22 \right)\left( 5 \right)\left( 3 \right) \\
& =660c{{m}^{2}} \\
\end{align}$
Now, as you can see in the question given above, the curved surface area of the cylinder is $660c{{m}^{2}}$ which is matching with the value of curved surface area that we have just calculated by putting r and h as 5cm and 21 cm respectively.
Hence, the value of the radius and height of the cylinder that we are getting is correct.
Recently Updated Pages
10 Examples of Evaporation in Daily Life with Explanations
10 Examples of Diffusion in Everyday Life
1 g of dry green algae absorb 47 times 10 3 moles of class 11 chemistry CBSE
If x be real then the maximum value of 5 + 4x 4x2 will class 10 maths JEE_Main
If the coordinates of the points A B and C be 443 23 class 10 maths JEE_Main
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Why is there a time difference of about 5 hours between class 10 social science CBSE
Give 10 examples for herbs , shrubs , climbers , creepers