Answer
Verified
361.2k+ views
Hint: Whenever a dielectric is inserted between a parallel plate of a capacitor then the new value of the capacitor increases by k time the original capacitor. And if more than one dietetic material is inserted in between the parallel plated then each medium will act as a separate capacitor. Now using this concept first convert each dielectric into a separate capacitor so as to analyze their connection that they are in series or parallel. Now find the equivalent capacitor of the three dielectric materials and equate it with the original capacitance.
Complete answer:
We know that capacitance of a capacitor is given by,
$ C = \dfrac{{\varepsilon 0A}}{d} $
Where,
A is the area between the two parallel plates.
Distance between the two parallel plates is represented as d.
And $ \varepsilon 0 $ is the permittivity of the space between the two parallel plates.
This is the case when it is between the two parallel plates.
But in this case three dielectric constants are inserted and in total let the dielectric constant be K which is always greater than one.
Therefore the new capacitance will become,
$ C' = \dfrac{{K\varepsilon 0A}}{d} $
Which is K time greater $ C $ .
Now from the above figure we can divide the capacitor into three different capacitors having different dielectric constant.
Case i:
$ K = 3 $
$ C_3 = \dfrac{{3\varepsilon 0\dfrac{A}{2}}}{{\dfrac{d}{2}}} $
Now on simplifying we will get,
$ C_3 = \dfrac{{3\varepsilon 0A}}{d} $
Case II:
In series with $ K = 3 $
$ K = 6 $
$ C_6 = \dfrac{{6\varepsilon 0\dfrac{A}{2}}}{{\dfrac{d}{2}}} $
Now on simplifying we will get,
$ C_6 = \dfrac{{6\varepsilon 0A}}{d} $
Case III:
In parallel with $ K = 3 $ and $ K = 6 $
$ K = 6 $
$ C_6 = \dfrac{{6\varepsilon 0\dfrac{A}{2}}}{d} $
Now on simplifying we will get,
$ C_6 = \dfrac{{3\varepsilon 0A}}{d} $
Now we can draw,
Now the equivalent capacitance from the above diagram will be,
$ C_{eq} = C_6||\dfrac{{\left( {C_3\, \times C_6} \right)}}{{C_3 + C_6}} $
Putting the values we will get,
$ C_{eq} = \dfrac{{3\varepsilon 0A}}{d}||\dfrac{{\left( {\dfrac{{3\varepsilon 0A}}{d} \times \dfrac{{6\varepsilon 0A}}{d}} \right)}}{{\dfrac{{3\varepsilon 0A}}{d} + \dfrac{{6\varepsilon 0A}}{d}}} $
Cancelling the common terms qe will get,
$ C_{eq} = \dfrac{{3\varepsilon 0A}}{d}||\dfrac{{\left( {\dfrac{{18\varepsilon 0A}}{d}} \right)}}{9} $
Parallel capacitance are added,
$ C_{eq} = \dfrac{{3\varepsilon 0A}}{d} + \dfrac{{2\varepsilon 0A}}{d} $
$ \Rightarrow C_{eq} = \dfrac{{5\varepsilon 0A}}{d} $
As per the problem now equating this equivalent capacitance with $ C' $ we will get,
$ C' = C_{eq} $
Putting the respective values we will get,
$ \dfrac{{K\varepsilon 0A}}{d} = \dfrac{{5\varepsilon 0A}}{d} $
Cancelling the given terms we will get,
$ K = 5 $
Therefore the correct option is $ \left( C \right) $ .
Note:
Remember that different materials have different dielectric constants like a perfectly conducting material has a dielectric constant of infinity while a perfectly insulating parallel has dielectric constant as zero. And note that while solving this type of problem first convert the dielectric into a separate category to solve the problem easily.
Complete answer:
We know that capacitance of a capacitor is given by,
$ C = \dfrac{{\varepsilon 0A}}{d} $
Where,
A is the area between the two parallel plates.
Distance between the two parallel plates is represented as d.
And $ \varepsilon 0 $ is the permittivity of the space between the two parallel plates.
This is the case when it is between the two parallel plates.
But in this case three dielectric constants are inserted and in total let the dielectric constant be K which is always greater than one.
Therefore the new capacitance will become,
$ C' = \dfrac{{K\varepsilon 0A}}{d} $
Which is K time greater $ C $ .
Now from the above figure we can divide the capacitor into three different capacitors having different dielectric constant.
Case i:
$ K = 3 $
$ C_3 = \dfrac{{3\varepsilon 0\dfrac{A}{2}}}{{\dfrac{d}{2}}} $
Now on simplifying we will get,
$ C_3 = \dfrac{{3\varepsilon 0A}}{d} $
Case II:
In series with $ K = 3 $
$ K = 6 $
$ C_6 = \dfrac{{6\varepsilon 0\dfrac{A}{2}}}{{\dfrac{d}{2}}} $
Now on simplifying we will get,
$ C_6 = \dfrac{{6\varepsilon 0A}}{d} $
Case III:
In parallel with $ K = 3 $ and $ K = 6 $
$ K = 6 $
$ C_6 = \dfrac{{6\varepsilon 0\dfrac{A}{2}}}{d} $
Now on simplifying we will get,
$ C_6 = \dfrac{{3\varepsilon 0A}}{d} $
Now we can draw,
Now the equivalent capacitance from the above diagram will be,
$ C_{eq} = C_6||\dfrac{{\left( {C_3\, \times C_6} \right)}}{{C_3 + C_6}} $
Putting the values we will get,
$ C_{eq} = \dfrac{{3\varepsilon 0A}}{d}||\dfrac{{\left( {\dfrac{{3\varepsilon 0A}}{d} \times \dfrac{{6\varepsilon 0A}}{d}} \right)}}{{\dfrac{{3\varepsilon 0A}}{d} + \dfrac{{6\varepsilon 0A}}{d}}} $
Cancelling the common terms qe will get,
$ C_{eq} = \dfrac{{3\varepsilon 0A}}{d}||\dfrac{{\left( {\dfrac{{18\varepsilon 0A}}{d}} \right)}}{9} $
Parallel capacitance are added,
$ C_{eq} = \dfrac{{3\varepsilon 0A}}{d} + \dfrac{{2\varepsilon 0A}}{d} $
$ \Rightarrow C_{eq} = \dfrac{{5\varepsilon 0A}}{d} $
As per the problem now equating this equivalent capacitance with $ C' $ we will get,
$ C' = C_{eq} $
Putting the respective values we will get,
$ \dfrac{{K\varepsilon 0A}}{d} = \dfrac{{5\varepsilon 0A}}{d} $
Cancelling the given terms we will get,
$ K = 5 $
Therefore the correct option is $ \left( C \right) $ .
Note:
Remember that different materials have different dielectric constants like a perfectly conducting material has a dielectric constant of infinity while a perfectly insulating parallel has dielectric constant as zero. And note that while solving this type of problem first convert the dielectric into a separate category to solve the problem easily.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Give 10 examples for herbs , shrubs , climbers , creepers
Change the following sentences into negative and interrogative class 10 english CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE