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Two concentric coils each of radius equal to 2πcm are placed at right angles to each other. 3 ampere and 4 ampere are the currents flowing in each coil respectively. The magnetic induction in weber/m2 at the center of coils will be (μ=4π×107Wb/A.m)
 A. 105
 B. 12×105
 C. 5×105
 D. 7×105

Answer
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Hint – For these types of questions, we must know the basic formulae of the magnetic chapter and how to apply in different situations of the coils i.e. if they are parallel or perpendicular.
Formula used – 1)Bnet=B12+B22
2) Bnet=μ04π(2πr)i12+i22

Complete step-by-step solution -
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Given that,
i1=3A, i2=4A and radius of coil = 2π
We know that, Bnet=B12+B22 (here we have used Pythagoras formula because both the fields are perpendicular to each other and their resultant will be calculated only like this)
And Bnet=μ04π(2πr)i12+i22
B1 is the magnetic field in ring 1 and B2 is magnetic field in ring 2.
i1is the current flowing in ring 1 and i2 is current flowing in ring 2.
According to the flow of current, the magnetic fields will be perpendicular to the plane of the respective rings.
The value of μ04π is 107.
On putting the value of radius and
Therefore, Bnet=107×(2π2π)(3)2+(4)2
Bnet=5×107Wb/m2
Hence the correct answer to this question is 5×107Wb/m2.
Hence the correct option is C.

Note – In solving this question we must know the application of formula according to the configuration of the two coils and the calculation mistake should be avoided. Since students generally make calculation mistakes in these questions. We advise the students to remember the formula of the magnetic field for rings at the axis and at the center. Remembering derivation will give you a brief knowledge to calculate the magnetic field for any other shape regarding a ring.