Answer
Verified
456.6k+ views
Hint: Collision is short-duration interaction between two bodies or more than two bodies simultaneously causing a change in motion of bodies. Collision is of three types:
(i) Perfectly elastic collision.
(ii) Inelastic collision.
(iii) Perfectly inelastic collision.
To solve this type of question we use the law of conservation of momentum.
Complete step by step answer:
Given, ${m_1} = 100g,{m_2} = 200g,{u_1} = 2m/s,{u_2} = 1m/s,{v_2} = 1.67m/s$
We have to find the velocity of the first object $v_1$.
Flowing is the diagram showing the situation.
Now let us use the concept of conservation of linear momentum which states that the total initial momentum is equal to the total final momentum.
Initial momentum = Final momentum
Let us write the linear momentum of the system before the collision.
${P_{initial}} = {m_1}{u_1} + {m_2}{u_2}$
Let us now substitute the values.
$\Rightarrow {P_{initial}} = 0.1 \times 2 + 0.2 \times 1$
Let us simplify it.
$\Rightarrow {P_{initial}} = 0.4kgm/s$ ………...(1)
Let us write the linear momentum of the system after the collision.
$ {P_{final}} = {m_1}{v_1} + {m_2}{v_2}$
Let us now substitute the values.
$\Rightarrow {P_{final}} = 0.1{v_1} + 0.2 \times 1.67$
Let us simplify it.
$\Rightarrow {P_{final}} = 0.1{v_1} + 0.334$ …………..(2)
Now using linear momentum conservation, let us equate equation (1) and (2).
$\Rightarrow 0.4 = 0.1{v_1} + 0.334$
Let us simplify it.
$\Rightarrow 0.4 - 0.334 = 0.2{v_1} \Rightarrow {v_1} = \dfrac{{0.066}}{{0.2}}$
$\Rightarrow {v_1} = 0.33m/s$
$\therefore $ The velocity of the first object is 0.33m/sec. Hence, option (D) correct.
Note:
There are two types of collisions between two bodies as given below:
1) Head-on collisions (also known as one-dimensional collisions) – In this type of collision, the velocity of each body just before impact is along the line of impact after collision also.
2) Non-head-on collisions, (also known as two-dimensional collisions) – In this type of collision, the velocity of each body just before impact is not along the line of impact after the collision.
(i) Perfectly elastic collision.
(ii) Inelastic collision.
(iii) Perfectly inelastic collision.
To solve this type of question we use the law of conservation of momentum.
Complete step by step answer:
Given, ${m_1} = 100g,{m_2} = 200g,{u_1} = 2m/s,{u_2} = 1m/s,{v_2} = 1.67m/s$
We have to find the velocity of the first object $v_1$.
Flowing is the diagram showing the situation.
Now let us use the concept of conservation of linear momentum which states that the total initial momentum is equal to the total final momentum.
Initial momentum = Final momentum
Let us write the linear momentum of the system before the collision.
${P_{initial}} = {m_1}{u_1} + {m_2}{u_2}$
Let us now substitute the values.
$\Rightarrow {P_{initial}} = 0.1 \times 2 + 0.2 \times 1$
Let us simplify it.
$\Rightarrow {P_{initial}} = 0.4kgm/s$ ………...(1)
Let us write the linear momentum of the system after the collision.
$ {P_{final}} = {m_1}{v_1} + {m_2}{v_2}$
Let us now substitute the values.
$\Rightarrow {P_{final}} = 0.1{v_1} + 0.2 \times 1.67$
Let us simplify it.
$\Rightarrow {P_{final}} = 0.1{v_1} + 0.334$ …………..(2)
Now using linear momentum conservation, let us equate equation (1) and (2).
$\Rightarrow 0.4 = 0.1{v_1} + 0.334$
Let us simplify it.
$\Rightarrow 0.4 - 0.334 = 0.2{v_1} \Rightarrow {v_1} = \dfrac{{0.066}}{{0.2}}$
$\Rightarrow {v_1} = 0.33m/s$
$\therefore $ The velocity of the first object is 0.33m/sec. Hence, option (D) correct.
Note:
There are two types of collisions between two bodies as given below:
1) Head-on collisions (also known as one-dimensional collisions) – In this type of collision, the velocity of each body just before impact is along the line of impact after collision also.
2) Non-head-on collisions, (also known as two-dimensional collisions) – In this type of collision, the velocity of each body just before impact is not along the line of impact after the collision.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Who gave the slogan Jai Hind ALal Bahadur Shastri BJawaharlal class 11 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE