Answer
Verified
465.3k+ views
Hint: Use the Doppler effect concept and find the value of the apparent frequencies of the two sources found by the observer and find the difference of the apparent frequencies which is equal to the number of beats heard by the observer
Complete step-by-step answer:
The observer hears a different frequency from what the source produces as explained by the doppler effect. Here we need to find the apparent frequencies of both the sources found by the person as he moves with the speed u
The apparent frequency of source 1 heard when the person is moving towards Source 2 is given by
$n_1 = (\dfrac{v-v_o}{v-v_s})n$ where the n is the true frequency and the $v_o$ is the velocity of the observer and the $v_s$ is the velocity of the source moving.
So we get the apparent frequency of the source 1 as heard by the man is
$n_1 = (\dfrac{v-v_o}{v-v_s})n = (\dfrac{330-u}{330+0})660 = (330-u)(2)$
The apparent frequency of source 2 heard when the person is moving towards Source 2 is given by
$n_1 = (\dfrac{v-v_o}{v-v_s})n$
So we get the apparent frequency of the source 2 as heard by the man is
$n_2 = (\dfrac{v-v_o}{v-v_s})n = (\dfrac{330+u}{330+0})660 = (330+u)(2)$
Now the number of beats is the difference in the apparent frequency heard by the man
So we get that
$n_2 - n_1 =10 = 2u +2u = 4u$
So we get $u = \dfrac{10}{4} = 2.5 \dfrac{m}{s}$
Note: The most common mistake that one tends to make in the problems related to the doppler effect the sign convention to be taken for the two sources depending on the direction of the movement of the observer. The sign is negative when the observer is moving away and the sign is positive when the observer is moving towards the source.
Complete step-by-step answer:
The observer hears a different frequency from what the source produces as explained by the doppler effect. Here we need to find the apparent frequencies of both the sources found by the person as he moves with the speed u
The apparent frequency of source 1 heard when the person is moving towards Source 2 is given by
$n_1 = (\dfrac{v-v_o}{v-v_s})n$ where the n is the true frequency and the $v_o$ is the velocity of the observer and the $v_s$ is the velocity of the source moving.
So we get the apparent frequency of the source 1 as heard by the man is
$n_1 = (\dfrac{v-v_o}{v-v_s})n = (\dfrac{330-u}{330+0})660 = (330-u)(2)$
The apparent frequency of source 2 heard when the person is moving towards Source 2 is given by
$n_1 = (\dfrac{v-v_o}{v-v_s})n$
So we get the apparent frequency of the source 2 as heard by the man is
$n_2 = (\dfrac{v-v_o}{v-v_s})n = (\dfrac{330+u}{330+0})660 = (330+u)(2)$
Now the number of beats is the difference in the apparent frequency heard by the man
So we get that
$n_2 - n_1 =10 = 2u +2u = 4u$
So we get $u = \dfrac{10}{4} = 2.5 \dfrac{m}{s}$
Note: The most common mistake that one tends to make in the problems related to the doppler effect the sign convention to be taken for the two sources depending on the direction of the movement of the observer. The sign is negative when the observer is moving away and the sign is positive when the observer is moving towards the source.
Recently Updated Pages
How is abiogenesis theory disproved experimentally class 12 biology CBSE
What is Biological Magnification
Which of the following reagents cannot distinguish class 12 chemistry CBSE
Which of the following reagents cannot distinguish class 12 chemistry CBSE
Which of the following reagents cannot distinguish class 12 chemistry CBSE
Which of the following reagents cannot distinguish class 12 chemistry CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
What are the major means of transport Explain each class 12 social science CBSE
Explain sex determination in humans with the help of class 12 biology CBSE
How much time does it take to bleed after eating p class 12 biology CBSE