Answer
Verified
452.7k+ views
Hint
The Relation between $g$ that is gravitational acceleration and the height which is distance from Centre of the earth $(R + h)$ where $R$ is radius of earth. Compare $2$ gravitational values to obtain for height $h$.
Complete Step By Step Solution
Let’s first begin with, what is the relation between the gravitational acceleration and the radius of the earth. the gravitational acceleration is given by ${\text{g}} = \dfrac{{{\text{GM}}}}{{{{\text{R}}^{\text{2}}}}},$ where $G$ is Gravitational constant equals $6.67 \times {10^{ - 11}} \dfrac{N}{{kg^2}{m^2}}$.
Whereas, $M$ is mass and $R$ is the distance of an object from core Centre, here it’s Radius as the height is termed as negligible. If we have a height $h$, the near gravitational acceleration for that body will act as-
${{\text{g}}_1} = \dfrac{{{\text{GM}}}}{{{{\left( {{\text{R}} + {\text{h}}} \right)}^{\text{2}}}}}$
If we compare both the value, we get-
$\dfrac{{\text{g}}}{{{\text{g1}}}} = \dfrac{{{\text{GM}}}}{{{{\text{R}}^{\text{2}}}}} \times \dfrac{{{{\left( {{\text{R}} + {\text{h}}} \right)}^{\text{2}}}}}{{{\text{GM}}}} = {\left[ {{\text{1}} + \dfrac{{\text{h}}}{{\text{R}}}} \right]^2}$
We can say, ${{\text{g}}_{\text{1}}} = {\text{g}}{\left( {1 + \dfrac{{\text{h}}}{{\text{g}}}} \right)^{ - 2}}$
By cross multiplication, as we can see the value of $R$ that is radius of the earth is large to get $\dfrac{{\text{h}}}{{\text{R}}}$ a small value enough. So the binomial expansion of ${\left( {1 + y} \right)^{ - 2}}$ for small y is $\left( {1 - 2y} \right)$ Similarly, here it would be equal to-
${{\text{g}}_{\text{1}}} = {\text{g}}\left( {1 - \dfrac{{{\text{2h}}}}{{\text{R}}}} \right)$
Hence the value of gravitational acceleration will decrease with the increase in height of the object.
Note
We should know the relation between gravitational acceleration, Mass, Radius and it’s Constant which is $6.67 \times {10^{ - 11}} N {kg}^{−2} {m}^{−2}$. The binomial expansion for small value tending to zero is mainly used in many forms to get a reduced form equation.
The Relation between $g$ that is gravitational acceleration and the height which is distance from Centre of the earth $(R + h)$ where $R$ is radius of earth. Compare $2$ gravitational values to obtain for height $h$.
Complete Step By Step Solution
Let’s first begin with, what is the relation between the gravitational acceleration and the radius of the earth. the gravitational acceleration is given by ${\text{g}} = \dfrac{{{\text{GM}}}}{{{{\text{R}}^{\text{2}}}}},$ where $G$ is Gravitational constant equals $6.67 \times {10^{ - 11}} \dfrac{N}{{kg^2}{m^2}}$.
Whereas, $M$ is mass and $R$ is the distance of an object from core Centre, here it’s Radius as the height is termed as negligible. If we have a height $h$, the near gravitational acceleration for that body will act as-
${{\text{g}}_1} = \dfrac{{{\text{GM}}}}{{{{\left( {{\text{R}} + {\text{h}}} \right)}^{\text{2}}}}}$
If we compare both the value, we get-
$\dfrac{{\text{g}}}{{{\text{g1}}}} = \dfrac{{{\text{GM}}}}{{{{\text{R}}^{\text{2}}}}} \times \dfrac{{{{\left( {{\text{R}} + {\text{h}}} \right)}^{\text{2}}}}}{{{\text{GM}}}} = {\left[ {{\text{1}} + \dfrac{{\text{h}}}{{\text{R}}}} \right]^2}$
We can say, ${{\text{g}}_{\text{1}}} = {\text{g}}{\left( {1 + \dfrac{{\text{h}}}{{\text{g}}}} \right)^{ - 2}}$
By cross multiplication, as we can see the value of $R$ that is radius of the earth is large to get $\dfrac{{\text{h}}}{{\text{R}}}$ a small value enough. So the binomial expansion of ${\left( {1 + y} \right)^{ - 2}}$ for small y is $\left( {1 - 2y} \right)$ Similarly, here it would be equal to-
${{\text{g}}_{\text{1}}} = {\text{g}}\left( {1 - \dfrac{{{\text{2h}}}}{{\text{R}}}} \right)$
Hence the value of gravitational acceleration will decrease with the increase in height of the object.
Note
We should know the relation between gravitational acceleration, Mass, Radius and it’s Constant which is $6.67 \times {10^{ - 11}} N {kg}^{−2} {m}^{−2}$. The binomial expansion for small value tending to zero is mainly used in many forms to get a reduced form equation.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
Derive an expression for drift velocity of free electrons class 12 physics CBSE
Which are the Top 10 Largest Countries of the World?
Write down 5 differences between Ntype and Ptype s class 11 physics CBSE
The energy of a charged conductor is given by the expression class 12 physics CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Derive an expression for electric field intensity due class 12 physics CBSE
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Derive an expression for electric potential at point class 12 physics CBSE