Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

Which of the following expressions are polynomials in one variable and which are not? State your reason.
A) \[3{{x}^{2}}-4x+15\]
B) \[{{y}^{2}}+2\sqrt{3}\]
C) \[3\sqrt{x}+\sqrt{2x}\]
D) \[x-\dfrac{4}{x}\]
E) \[{{x}^{12}}+{{y}^{3}}+{{t}^{50}}\]

seo-qna
SearchIcon
Answer
VerifiedVerified
462.9k+ views
Hint: To find the one variable polynomial, the equation must contain only one variable in terms of \[a{{x}^{n}}\] where \[n\] is the power as \[n\] is real, positive and non-fractional.

Complete step-by-step answer:
Let find one variable polynomial using the above criteria:
1. \[3{{x}^{2}}-4x+15\]
It’s a one variable polynomial as it contains a single \[a{{x}^{n}}\] term as \[3{{x}^{2}}\] in the equation.
2. \[{{y}^{2}}+2\sqrt{3}\]
It’s a one variable polynomial as it contains a single \[a{{x}^{n}}\] term as \[{{y}^{2}}\] in the equation.
3. \[3\sqrt{x}+\sqrt{2x}\]
It is not a one variable polynomial as the power of \[n\] in \[a{{x}^{n}}\] is \[\dfrac{1}{2},\left( 3{{x}^{\dfrac{1}{2}}} \right)\] which is fractional hence again not a one variable polynomial.
4. \[x-\dfrac{4}{x}\]
It is not a one variable polynomial as the variable \[\dfrac{4}{x}\] is negative in nature hence, contradicting the conditions.
5. \[{{x}^{12}}+{{y}^{3}}+{{t}^{50}}\]
It is not a one variable polynomial; it’s a three variable polynomial as there are three variables in form of \[a{{x}^{n}}\] as \[x,y,t\] and the value \[n\] follows all the conditions.

Note: Students may go wrong while solving the part number (4) as the first variable \[x\] can be placed as \[1.{{x}^{1}}\] but when finding one variable polynomial one must ensure that all the variables in the polynomial follow the condition for the power as \[n\] is real, positive and non-fractional.