![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
Which of the following solutions have the same concentration?
A. 20g of NaOH in 200 mL of solution
B. 0.5 mole of KCl in 200 mL of solution
C. 40g of NaOH in 100 mL of solution
D. 20g of KOH in 200 mL of solution
Answer
450.3k+ views
Hint: Molarity of the solution is defined as the amount of number of moles which have been dissolved in 1 litre of the solution. So we represent the concentration in terms of molarity with the symbol of M. The molarity of the solution changes with the change in physical properties such as pressure and temperature.
Complete step by step answer:
Now to calculate the concentration of the substance we will use the formula of molarity. The formula is the following:
Molarity = $$\dfrac{{{ {mass \;of \;solute \times 1000}}}}{{{ {molar\; mass \;of \;solute \times volume \;of \;solution}}}}$$
Now for option (a)the mass of solute is 20g, the molar mass of NaOH will be = 23+16+1 = 40$${ {gmo}}{{ {l}}^{{ { - 1}}}}$$and volume of solution is 200 mL. Now substituting the value in formula we get,
Molarity = $$\dfrac{{20 \times 1000}}{{40 \times 200}}$$ = 2.5M
Now for option (b) the moles of the solute is given which is 0.5 moles, the volume of solution is 200 mL. The formula which we will be using here is :
Molarity = $$$$
Molarity = $$\dfrac{{{ {0}}{ {.5 \times 1000}}}}{{200}}$$ = 2.5M
Now for option (c) the value for mass of solute is 40g and the molar mass of NaOH is 40g and volume of solution is 100 mL. Now substituting the value:
Molarity = $$\dfrac{{{ {40 \times 1000}}}}{{40 \times 100}}$$ = 10M
Now for option (d) the value for mass of solute is 20g and the molar mass for
KOH = 39+16+1 = 56$${ = {gmo}}{{ {l}}^{{ { - 1}}}}$$ and volume of solution is 200 mL.
Now substituting the values in formula we get,
Molarity = $$\dfrac{{{ {20 \times 1000}}}}{{20 \times 200}}$$ = 5M
So, the correct answer is Option A,B.
Note: The one molar of the substance means the molarity of solution in which the 1 g of the solute has been dissolved in one litre of the solution. We take the complete volume of the solution because the solute as well as solvent is used to blend the solution. The molarity is the ratio of moles of solute to the volume of solution.
Complete step by step answer:
Now to calculate the concentration of the substance we will use the formula of molarity. The formula is the following:
Molarity = $$\dfrac{{{ {mass \;of \;solute \times 1000}}}}{{{ {molar\; mass \;of \;solute \times volume \;of \;solution}}}}$$
Now for option (a)the mass of solute is 20g, the molar mass of NaOH will be = 23+16+1 = 40$${ {gmo}}{{ {l}}^{{ { - 1}}}}$$and volume of solution is 200 mL. Now substituting the value in formula we get,
Molarity = $$\dfrac{{20 \times 1000}}{{40 \times 200}}$$ = 2.5M
Now for option (b) the moles of the solute is given which is 0.5 moles, the volume of solution is 200 mL. The formula which we will be using here is :
Molarity = $$$$
Molarity = $$\dfrac{{{ {0}}{ {.5 \times 1000}}}}{{200}}$$ = 2.5M
Now for option (c) the value for mass of solute is 40g and the molar mass of NaOH is 40g and volume of solution is 100 mL. Now substituting the value:
Molarity = $$\dfrac{{{ {40 \times 1000}}}}{{40 \times 100}}$$ = 10M
Now for option (d) the value for mass of solute is 20g and the molar mass for
KOH = 39+16+1 = 56$${ = {gmo}}{{ {l}}^{{ { - 1}}}}$$ and volume of solution is 200 mL.
Now substituting the values in formula we get,
Molarity = $$\dfrac{{{ {20 \times 1000}}}}{{20 \times 200}}$$ = 5M
So, the correct answer is Option A,B.
Note: The one molar of the substance means the molarity of solution in which the 1 g of the solute has been dissolved in one litre of the solution. We take the complete volume of the solution because the solute as well as solvent is used to blend the solution. The molarity is the ratio of moles of solute to the volume of solution.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the value of x if the mode of the following data class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
10 examples of friction in our daily life
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Prokaryotic Cells and Eukaryotic Cells
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
State and prove Bernoullis theorem class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What organs are located on the left side of your body class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The combining capacity of an element is known as i class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)