Write down, if possible, the largest natural number.
Answer
Verified
468.6k+ views
Hint: We will first understand the set of Natural Numbers and which elements does it consist of. After that, we will assume that it has some largest element and then prove by contradiction that it is
not possible.
Complete step-by-step answer:
We know that the set of Natural Numbers is given by {1, 2, 3, 4, ……………….. }.
We can clearly observe that 1 < 2 < 3 < 4 < ……….
\[\therefore \] 1 is the least element.
But, we need the greatest of Natural Numbers.
Let us assume that it has a largest number which is say a.
Now, since a is the largest among all the Natural Numbers.
\[\therefore n < a,\forall n \in \mathbb{N}\] ……………..(1)
Now, we know that the successor of a natural number is also a natural number.
\[\therefore \] a + 1 is also a natural number.
So, by using (1), we will get:
$ \Rightarrow a + 1 < a$
This implies that:
$ \Rightarrow 1 < 0$, which is absolutely absurd.
Therefore, our assumption is wrong.
Hence, the set of Natural numbers do not have any largest number.
Note: The students must note that “This property of Natural Numbers that it does not have any maximum is known as the “Archimedean Property” which is going to be extremely handy to you in future. Archimedean property states that “the set of Natural Numbers are unbounded above”. But the students must also note that the set of Natural Numbers have the “Well Ordering Property” which states that it always has a least element. Like in natural numbers 1 is the least element.
The students must note that we used the fact: successor of natural numbers is also a natural number. But we could also have used the fact that “The set of Natural Numbers are closed under addition”.
not possible.
Complete step-by-step answer:
We know that the set of Natural Numbers is given by {1, 2, 3, 4, ……………….. }.
We can clearly observe that 1 < 2 < 3 < 4 < ……….
\[\therefore \] 1 is the least element.
But, we need the greatest of Natural Numbers.
Let us assume that it has a largest number which is say a.
Now, since a is the largest among all the Natural Numbers.
\[\therefore n < a,\forall n \in \mathbb{N}\] ……………..(1)
Now, we know that the successor of a natural number is also a natural number.
\[\therefore \] a + 1 is also a natural number.
So, by using (1), we will get:
$ \Rightarrow a + 1 < a$
This implies that:
$ \Rightarrow 1 < 0$, which is absolutely absurd.
Therefore, our assumption is wrong.
Hence, the set of Natural numbers do not have any largest number.
Note: The students must note that “This property of Natural Numbers that it does not have any maximum is known as the “Archimedean Property” which is going to be extremely handy to you in future. Archimedean property states that “the set of Natural Numbers are unbounded above”. But the students must also note that the set of Natural Numbers have the “Well Ordering Property” which states that it always has a least element. Like in natural numbers 1 is the least element.
The students must note that we used the fact: successor of natural numbers is also a natural number. But we could also have used the fact that “The set of Natural Numbers are closed under addition”.
Recently Updated Pages
Express the following as a fraction and simplify a class 7 maths CBSE
The length and width of a rectangle are in ratio of class 7 maths CBSE
The ratio of the income to the expenditure of a family class 7 maths CBSE
How do you write 025 million in scientific notatio class 7 maths CBSE
How do you convert 295 meters per second to kilometers class 7 maths CBSE
Write the following in Roman numerals 25819 class 7 maths CBSE
Trending doubts
The southernmost point of the Indian mainland is known class 7 social studies CBSE
List of coprime numbers from 1 to 100 class 7 maths CBSE
In his early days shivaji moved with AJat leaders BMawali class 7 social science CBSE
Write a summary of the poem the quality of mercy by class 7 english CBSE
How did Douglas overcome his fear of water class 7 english CBSE
Find HCF and LCM of 510 and 92 by applying the prime class 7 maths CBSE