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Write the equations for the preparation of 1iodobutane from:
(i) 1butanol
(ii)1chlorobutane
(iii)but1ene

Answer
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Hint: In 1iodobutane, we can understand that there is presence of an aliphatic four carbon chain and an Iodo group. From the given options we need to find out the main functional group and understand what can convert them.

Complete answer:
In the first point, (i) 1butanol we observe that it has an alcoholic group.
If any alkyl alcohol is reacted with red phosphorus and in the presence of I2, it gives out alkyl iodide.
In this first question we react (i) 1butanol reacted with red phosphorus and in presence of I2
, it gives 1iodobutane.
Reaction of the following:
ROHRed P, I2RI
CH3CH2CH2OHRed P, I2CH3CH2CH2I
(ii) In second, 1chlorobutane we observe that it has a halogen group.
If any alkyl chloride is reacted in the presence of NaI, there is exchange of weaker nucleophile in presence of stronger nucleophile.
In this part we react, 1chlorobutanereacts in the presence of NaI, it gives 1iodobutane.
The following reaction:
R2CH=CHHIR2CH2I
RClNaIRI
CH3CH2CH2ClNaICH3CH2CH2I
(iii) In third, but1ene we observe that it has one unsaturated group. If any alkene is reacted with HI it undergoes markovnikov’s addition, and forms alkyl iodide.
In this part we react but1ene we react with HI and then it undergoes Markovnikov's addition reaction. It gives out 1iodobutane.
The reaction is as follows: R2CH=CHHIR2CH2I
CH3CH2CH=CHHICH3CH2CH2I

Note:
Do not forget to add reagents when and where required. They act as catalytic agents or sometimes help in getting the end product with ease. They are very important because they can accelerate the reaction. Always find the correct functional group attached, otherwise the whole procedure of finding the product can lead to formation of something else.