Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

NCERT Exemplar for Class 6 Maths Solutions Chapter 4 Fractions & Decimals

ffImage
banner

Class 6 Maths NCERT Exemplar Solutions Chapter 4 Fractions & Decimals

Free PDF download of NCERT Exemplar for Class 6 Mathematics Chapter 4 - Fractions & Decimals solved by expert Mathematics teachers on Vedantu.com as per NCERT (CBSE) Book guidelines. All Chapter 4 - Fractions & Decimals exercise questions with solutions to help you to revise the complete syllabus and score more marks in your examinations.


You can also Download NCERT Solutions for Class 6 Mathematics to help you to revise the complete Syllabus and score more marks in your examinations.

Courses

Access NCERT Exemplar Solutions for Class 6 Mathematics Chapter 4 - Fraction and Decimals

In examples 1 and 2, write the correct answer from the given four options:

Example 1. Which of the following fractions is the smallest?

(A) 119

(B) 117

(C) 1110

(D) 116

Ans: Option (C) is correct

The following fraction of 119=1.22

For, 117=1.57

For, 1110=1.1

For, 116=1.83

In the following fractions 1110 have smallest value

So, the option (C) is correct.


Example 2: 0.7625 lies between

(A) 0.7 and 0.76

(B) 0.77 and 0.78

(C) 0.76 and 0.761

(D) 0.76 and 0.763

Ans:  Option (D) is correct.

By using the number line the 0.7625 is lies between 0.76 and 0.763


Example 3: Fill in the blanks so that the statement is true:

Decimal 8.125is equal to the fraction______

Ans:658 or 818 

fraction for the decimal point is 8.125=81251000


Example 4: Fill in the blanks so that the statement is true:

6.453.78=_____

Ans: 2.67

The subtract the numbers get 6.453.78=2.67


Example 5: State true or false:

The fraction 1425 is equal to 14.2.

Ans: The given statement is false.

For fraction is 14210=14.2 


Example 6: Fill in the blanks using > or <

845__1689

Ans: For the fraction 845=8×245×2=1690

Now, 1690<1689, 

Therefore,  845<1689


Example 7: Express 1225 as a decimal.

Ans: The fraction for 1225=12×425×4

=48100=0.48

Decimal for the fraction 1225 is 0.48


Example 8: Convert 5809g to kg.

Ans: Since 1000g=1kg,

So, 5809g=58091000kg

=5.809kg. 


Example 9: Round off 87.952 to tenths place

Ans: For rounding off to tenths place, we look at the hundredths place. 

Here the digit is 5. So, the digit at the tenths place will be increased by 1

Hence, rounding off 87.952 to tenths place, we get 88.0


Example 10: Add the fractions 538 and 516

Ans: For the addition of fraction 

Rewrite the mixed fraction

538+516 =438+516

=43×28×2+516=8616+516

=86+516=9116=51116


Example 11: What should be added to 37.28 to obtain 46.8?

Ans:  Let the missing number is x

So, 37.28+x=46.8

x=46.837.28

=9.52

Hence, the required number to be added to 37.28 is 9.52


Example 12: Arrange the following in ascending order.

2.2,2.023,2.0226,22.1,20.42

Ans: To arrange them from the smallest to the greatest number. 

We arrange them as follows 

using the idea of place value and comparing their digits at different places

2.0226<2.023<2.2<20.42<22.1.


Example 13: Gorang purchased 2kg280g apples, 3kg375g bananas, 225g grapes and 5kg385g oranges. Find the total weight of the fruits purchased by Gorang in kg.

Ans: Since 1kg=1000g

Weight of apples =2kg280g=2280g 

Weight of bananas =3kg375g=3375g

Weight of grapes =225g

Weight of oranges =5kg385g=5385g

Total weight =2280g+3375g+225g+5385g = 11265g

Thus, total weight =11265g=112651000kg

=11.265kg


Example 14: What is wrong in the following?

74+52=7+54+2=126=2

Ans: Writing 74+52=7+54+2 is wrong. It should be as follows:

Converting into like fractions

74+52=74+104 

Only numerators are added

7+104=174 


In Questions 1 to 20, out of the four Options, only one Answer is Correct Choose the correct answer

1. The fraction which is not equal to 45 is

(A) 4050

(B) 1215

(C) 1620

(D) 915

Ans: Option D is right

Check option A40÷1050÷10=45

Check option B1215=45

Check option C1620=45

Check option D915=35


2. The two consecutive integers between which the fraction 57 lies are

(A) 5 and 6

(B) 0 and 1

(C) 5 and 7

(D) 6 and 7

Ans: Option B is right

Fundamental from fraction, if the value of a numerator of each fraction implies less than this value of denominator, ever lies between and 0 and 1.

Hence, 57 are lies between 0 and 1.


3. When 14 is written with denominator as 12, its numerator is

(A) 3

(B) 8

(C) 24

(D) 12

Ans: Option A is right

Since, 14×33=312


4. Which of the following is not in the lowest form?

(A) 75

(B) 1520

(C) 1333

(D) 2728

Ans: Option B is right

In case of 57, the common factor of 7 and 5 is 1.

Hence, already given in the simplest form.

In case of 1520, the common factor of 15 and 20 is 4.

In case of 1333, the common factor of 13 and 33 is 1.

Hence, already given in the simplest form.

In case of 2728, the common factor of 27 and 28 is 1.

Hence, already given in the simplest form.

Hence, 1520 not given in the simplest form.


5. If 58=20p, then value of p is

(A) 23

(B) 2

(C) 32

(D) 16

Ans: Option C is right

58=20p

5×p=20×8

p=20×85

p=4×8=32

Hence, Value of p is 32


6. Which of the following is not equal to the others?

(A) 68

(B) 1216

(C) 1525

(D) 1824

Ans: Option C is right

Check option A68=34

Check option B12÷416÷4=34

Check option C15÷525÷5=35

Check option D 18÷624÷6=34

Thus, Option C is not equal to the other option.


7. Which of the following fractions is the greatest?

(A) 57

(B) 56

(C) 59

(D) 58

Ans: Option B is right

In the above option given that, among the entire fraction with same numerator, the one with smaller denominator will be greatest.

Thus, required fraction is 56.


8. Which of the following fractions is the smallest?

(A) 78

(B) 98

(C) 38

(D) 58

Ans: Option C is right

In the above option given that, among the entire fraction with same denominator, the one with smaller numerator will be smallest.

Thus, required fraction is 38.


9. Sum of 417 and 1517 is

(A) 1917

(B) 1117

(C) 1934

(D) 217

Ans: Option A is right 

417 and 1517

Take the LCM of denominators

417+1517=4+1517

=1917

Thus, required fraction is 1917.


10. On subtracting 59 from 199, the result is

(A) 249

(B) 149

(C) 1418

(D) 140

Ans: Option B is right 

59 from 199

Take the LCM of denominators


   19959=1959

   =149 

Thus, required fraction is 149.


11. 0.7499lies between

(A) 0.7and 0.74

(B)0.75 and 0.79

(C) 0.749 and 0.75

(D) 0.74992 and 0.75

Ans: Option C is right

0.7499 is successor of 0.749and predecessor of 0.75

Thus, 0.749lies between 0.749and 0.75


12. 0.023lies between

(A) 0.2and0.3

(B)0.02 and 0.03

(C)0.03 and 0.029

(D)0.026 and 0.024

Ans: Option B is right

Thus, 0.023lies between 0.02and 0.03


13. 117 can be expressed in the form

(A) 714

(B) 417

(C) 147

(D) 1117

Ans: Option C is right

The mix fraction of 117 is 147


14. The mixed fraction 547 can be expressed as

(A) 337

(B) 397

(C) 334

(D) 394

Ans: Option B is right

  547=(7×5)+47

   =35+47

   =395 


15. 0.07+0.008 is equal to

(A) 0.15

(B)0.015

(C)0.078

(D)0.78

Ans: Option C is right

Sum of 0.07+0.008 is 0.078


16. Which of the following decimals is the greatest?

(A) 0.182

(B)0.0925

(C)0.29

(D)0.038

Ans: Option C is right

Convert the above option into like decimal as 0.1820,0.0925,0.2900and 0.0380.

Thus, comparing the value of like decimal value, 0.2900 is the greatest among the given option.


17. Which of the following decimals is the smallest?

(A) 0.27

(B)1.5

(C)0.082

(D)0.103

Ans: Option C is right

Convert the above option into like decimal as 0.270,1.500,0.082 and 0.103.

Thus, comparing the value of like decimal value, 0.082is the smallest among the given option.


18. 13.572correct to the tenths place is

(A) 10

(B)13.57

(C)14.5

(D)13.6

Ans: Option D is right

Round off the number 13.572is 13.6


19. 15.86.73 is equal to

(A) 8.07

(B)9.07

(C)9.13

(D)9.25

Ans: Option B is right

Subtraction of 15.86.73is 9.07


20. The decimal 0.238 is equal to the fraction

  (A) 119500

  (B) 23825

  (C) 19925

  (D) 11950 

Ans: Option A is right

Thus, 0.238

fraction for 0.238

   2381000=238÷21000÷2

   =119500 

Thus, required option 119500.


In Questions 21 to 44, fill in the blanks to make the Statements True

21. A number representing a part of a_____is called a fraction.

Ans: A number representing a part of a whole is called a fraction.


22. A fraction with denominator greater than the numerator is called a ____fraction.

Ans: A fraction with denominator greater than the numerator is called a proper fraction


23. fractions with the same denominator are called ____ fractions.

Ans: fractions with the same denominator are called like fractions.


24. 13518 Is a ____ fraction.

Ans: 1358 Is a mix fraction.


25. 188 Is a______ fraction.

Ans: 185 Is a improper fraction


26. 719 Is a_____ fraction.

Ans: 719 Is a proper fraction.


27. 58 and 38 Are _____ proper fractions.

Ans: 58 and 38 Are like proper fractions.


28. 611 and 613 Are____ proper fractions.

Ans: 611 and 613 are unlike proper fractions.


29. The fraction 615 in simplest form is______

Ans: Given fraction is 615=6÷315÷3=25

The fraction 615 in simplest form is 25


30. The fraction 1734 in simplest forms is_____

Ans: Given fraction is 1734=17÷1734÷17=12

The fraction 1734 in simplest form is 12


31. 18135 and 90675 Are proper, unlike and _____ fractions.

Ans: 18135 and 90675 Are proper, unlike and equivalent fractions.


32. 827 Is equal to the improper fraction_____

Ans: Given fraction is 

  872=(8×7)+72

  =56+27

   =587 

827 Is equal to the improper fraction 587


33. 877 Is equal to the mixed fraction _____

Ans: By long division the quotient and reminder will be 12and3

 877 Is equal to the mixed fraction 1237


34. 9+210+6100 Is equal to the decimal number_____

Ans: The LCM of 10 and 100 is100.

Hence, 9+210+6100

=9×100+2×10+6100

962100=9.26


35. Decimal 16.25are equal to the fraction _____

Ans: Now, 16.25

1625100=1625÷25100÷25=654

Decimal 16.25are equal to the fraction 654.


36. fraction 725 is equal to the decimal number

Ans: Given fraction is 

  725=7×425×4

   =28100

   =0.28 

fraction 725 is equal to the decimal number 0.28


37. 179+419=

Ans: Explanation,

For the fractions denominator is same so add only numerator

179+419=17+419=589

So,

179+419=589


38. 67141414=

Ans: Explanation,

For the fractions denominator is same so subtract only numerator

67142414=672414=4314

Hence,

67142414=4314


39. 172+312=

Ans: Explanation,

Rewrite the mixed fraction and add the numerator

172+312=172+72=17+72

242=24÷22÷2=12

Hence, 172+312=12


40. 91454=

Ans: Explanation,

Rewrite the mixed fraction and subtract the numerator

   91454=37454

   =3754=324

   32÷44÷4=8 

Therefore, 91454=8


41. 4.55+9.73=

Ans: Add the numbers

4.55+9.73=14.28


42. 8.762.68=

Ans: Subtract the numbers

8.762.68=6.08


43. The value of 50 coins of 50 paisa = Rs____

Ans: 50×50=2500 paisa

    Rs2500100= Rs.2500÷100100÷100

   = Rs25 

The value of 50 coins of 50 paisa = Rs. 25


44. 3 Hundredths +3tenths =

Ans: 3 Hundredths =0.03

3 tenths=0.3

3 Hundredths +3 tenths =0.33


In Each of the Questions 45 to 65, state Whether the Statement is True or False

45. fractions with the same numerator are called like fractions. 

Ans: The given statement is False 

The correct statement is fractions with the same denominator are called like fractions.


46. fraction 1839 is in its lowest form.

Ans: The statement is False

Because the fraction is in lowest form is

183918÷339÷3=613


47. fractions 1539 and 45117 are equivalent fractions.

Ans: The statement is True

It is divide by same number

4511745÷3117÷3=1539

So, Both are equivalent.


48. The sum of two fractions is always a fraction.

Ans: The statement is True

Let, two fraction 179 and 419

179+419=589

Explanation,

179+419=17+419=589

This is a fraction.


49. The result obtained by subtracting a fraction from another fraction is necessarily a fraction.

Ans: The statement is False

Let, two fraction 2414 and 6714

24146714=4314

Explanation, 

24146714=246714=4314

which is not a fraction.


50. If a whole or an object is divided into a number of equal parts, then each part represents a fraction.

Ans: The statement is True


51. The place value of a digit at the tenths place is 10 times the same digit at the one's place.

Ans: The given statement is False

The place value of a digit at the tenths place is 110 times the same digit at the one's place.

x10=10x, it is not possible.


52. The place value of a digit at the hundredths place is 110 times the same digit at the tenths place.

Ans: The given statement is True


53. The decimal 3.725is equal to 3.72 correct to two decimal places.

Ans: The given statement is False

Since, 5are at thousandths place.

3.725is written as 3.73,correct two decimal place.


54. In the decimal form, fraction 258=3.125.

Ans: The statement is True

258=25×1258×125

=31251000=3.125 


55. The decimal 23.2=2325.

Ans: The given statement is False

23.2=23210

=232÷210÷2=1165 

By Long division method the quotient and reminder is 23and1.

The correct statement 

The decimal 23.2=2315.


56. The fraction represented by the shaded portion in the adjoining figure is 38.


seo images


Ans: The given explanation is true.

The figure shows that, number of total part is8 and out of these3parts is shaded.

The required fraction is 38


57. The fraction represented by the un-shaded portion in the adjoining figure is 59.


seo images


Ans: The given statement for the figure is false.

The figure shows that, number of total part is 9 and out of these 4 parts is un-shaded.

The required fraction is 49.


58. 2519+619=3138

Ans: The addition of the fraction is False

Denominator is same for the fractions so by adding the numerator 

2519+619=25+619=3119

31193138 


59. 818815=83

Ans: The subtract of the fraction is False

Cross multiply the both fraction with each other.

818815=8×158×1818×15

=120144270=24270

=445 

44583


60. 712+1112=32

Ans: The addition of the fraction is True

712+1112=7+1112

=18÷612÷6=32 


61. 3.03+0.016=3.019

Ans: The addition of the numbers is False

3.030+0.016=3.046

3.0463.019 


62. 42.283.19=39.09.

Ans: The subtraction of the two numbers is True


63. 1625>1325

Ans: The statement is True

Given fraction are like fraction. 

Comparing the numerator, we get 1625>1325


64. 19.25<19.053

Ans: The given fraction type is False

Since, convert the 19.25and 19.053 in like decimal. It's become 19.250 and 19.053.

Compare the place value 19.250<19.053, we get hundred place of 19.250 is 2 and the hundred place of 19.053 is 0

Hence, the statement is 19.25>19.053


65. 13.730=13.73

Ans: The given number is True

Since, convert the 13.730 and 13.73in like decimal. It's become 13.730 and 13.730

So,13.730=13.73


In Each of the Questions 66 to 71, fill in the Blanks Using '>', '<' or '=':

66. 11161415

Ans: The L.C.M. of 16 and 15 is 2×2×2×2×3×5=240

Make it as like a fraction, multiply in numerator and denominator with the same digit

1116×1515=165240

1415×1616=224240

224240>165240 So, 1116<1415


67. 859514

Ans: The L.C.M of 15 and 14 is 2×3×5×7=210

Make it as like a fraction, multiply in numerator and denominator with the same digit

815×1414=112210

9514×1515=1425210

1425210>112210

Therefore,  815<9514


68. 127532200

Ans: The L.C.M of 75 and 200is 2×2×2×3×5×5=600

Make it as like a fraction, multiply in numerator and denominator with the same digit

1275×88=96600

32200×33=96600

96600=96600 

Hence, 1275=32200


69. 3.253.4

Ans: Since, convert the 3.25and 3.4in like decimal. It's become 3.25 and 3.40

Compare the place value of 3.25and 3.40,we get tenth place of 3.25 is 2 and the tenth place of 3.40is 4

Hence,3.25<3.4


70. 18151.3

Ans: Since, convert 1.3 into fraction from, we get 1310

1815..1310

The L.C.M. of 15 and 10 is 2×3×5=30

Make it as like a fraction, multiply in numerator and denominator with the same digit

1815×1010=180150 and 1310×1515=195150

180150<195150 So, 1815<1.3


71. 6.25254

Ans: Since, convert 1.3into fraction from, we get 625100

625100=625÷25100÷25=254

254.254

254=254

Therefore, 6.25=254


72. Write the fraction represented by the shaded portion of the adjoining figure:


seo images


Ans: In the given figure, total parts in the figure is divided into 8 parts and 7 parts are shaded. 

Total parts =8

Total shaded parts =7

Therefore,

fraction of unshaded portion = Total shaded parts  Total parts 

=78

The required fraction is 78.


73. Write the fraction represented by the un-shaded portion of the adjoining figure:


seo images


Ans: In the given figure, total parts in which figure has been divided into 15 and out of which 4 parts are unshaded.

Total parts =15

Total unshaded parts =4

Therefore,

fraction of unshaded portion = Total unshaded parts  Total parts =415

The required fraction is 415.


74. Ali divided one fruit cake equally among six persons. What part of the cake he gave to each person?

Ans: Given data 

Number of cake =1

Total no. of persons =6

Since,

Ali has to divide one fruit cake among 6 people,

Each person will get= No. of cake  Total no. of person 

=16 part


75. Arrange 12.142, 12.124, 12.104, 12.401 and 12.214in ascending order.

Ans: Given number12.142,12.124,12.104,12.401and 12.214 in like decimal.

So, compare the place value of the digit and arrange them, 12.104<12.124<12.142<12.214<12.401


76. Write the largest four-digit decimal number less than1 using the digits 1,5,3 and 8 once.

Ans: Given whole numbers are1,5,3, and 8.

Arrange them in descending order to make them large, after arranging the number will be 8531.

To make it a decimal number we will keep the whole number  8531 in the decimal point.

The required number is 0.8531, which is the largest four  -  digit decimal number less than 1.


77. Using the digits 2,4,5 and 3 once, write the smallest four-digit decimal number. 

Ans: For converting 2,4,5,and 3 into smallest four digit decimal number, arrange them in ascending order and then making the numbers decimal, we have to keep the whole numbers in decimal point.

After arranging whole numbers in ascending form it will be 2345.

To make the number decimal we will keep the numbers in decimal point.

So, the required number is0.2345, which is the smallest four digit decimal number.


78. Express 1120 as a decimal.

Ans: 1120 is an improper fraction.

To get the denominator as whole number we will multiply denominator by5,

1120=11×520×5=55100=0.55

0.55 is in decimal form


79. Express 623 as an improper fraction.

Ans: We will convert the mixed fraction 623 into improper fraction. 

We have,

623=(6×3)+23=18+23=203

Now we got 203.

203 is an improper fraction.


80. Express 325 as a decimal.

Ans: We will convert the mixed fraction 325 into an improper fraction. 

We have, 325=(3×5)+25=15+25=175

Now,

175=17×25×2=3410=3.4


81. Express 0.041as a fraction. 

Ans: We can write 0.041 as 0.0411.

So, 0.041=0.0411

Multiply numerator and denominator by 1000 we have,

0.041=0.041×10001×1000

=411000 

fraction for the decimal is 411000


82. Express 6.03as a mixed fraction.

Ans: We have, 6.03

6.03=603100=63100

The fraction for the decimal is 63100


83. Convert 5201g to kg.

Ans: We know that,

1Kg=1000g

1g=11000kg

5201g=11000×5201kg

5201g=52011000=5.201kg


84. Convert 2009 paisa to rupees and express the result as a mixed fraction.

Ans: We know that,

1 rupee =100 paisa

1 paisa =1100 rupees

2009 paisa =1100×2009 rupees

2009 paisa =2009100=20.09 rupees

The mixed fraction is Rs. 209100.


85. Convert 1537cm to m and express the result as an improper fraction.

Ans: We know that,

1 meter =100centimeters

1 centimeter =1100 meter

1537cm=1100×1537m

1537cm=1537100m


86. Convert 2435m to km and express the result as a mixed fraction.

Ans: We know that

1km=1000m

1m=11000km

2435m=11000×2435km

2435m=24351000km=2.435km

Dividing numerator and denominator by 5 we have,

2435÷51000÷5km=487200km

By long division method quotient and reminder is 2and87

The mixed fraction is 287200


87. Arrange the fractions 23,34,12 and 56 in ascending order.

Ans: Given fraction is 23,34,12 and 56

Take the LCM of 3,4,2and 6

The LCM of 3,4,2and 6 is 2×2×3=12

Now ,2×43×4=812,

3×34×3=912

1×62×6=612,

5×26×2=1012 

Now, arrange the following the ascending order

612<812<912<1012

The ascending order of the function is 12<23<34<56.


88. Arrange the fractions 67,78,45 and 34 in descending order

Ans: The given fraction is 67,78,45 and 34

Take the LCM of 7,8,5and 4

The LCM of 7,8,5and 4=2×2×2×5×9=280

Now, 67=6×407×40=240280,

78=7×358×35=245280

45=4×565×56=224280 and 34=3×704×70=210280

Now, arrange the following the descending order

245280>240280>224280>210280

The descending order of the fraction is 78>67>45>34.



89. Write 34 as a fraction with denominator 44.

Ans: Given fraction 34

If multiply 4 by 11 it become 44

Now,

34×1111=3×114×11=3344

34 is equivalent to 3344


90. Write 56 as a fraction with numerator 60.

Ans: Given fraction 56

If multiply 5 by 12 it become 60

Now,

56=5×126×12 

56=6072 

56 is equivalent to 6072.


91. Write 1298 as a mixed fraction

Ans: Given fraction is 1298

Now divide the numbers and quotient and reminder of the numbers is 16and1

So, the mixed fraction of the 1298=1618


92. Round off 20.83to nearest tenths

Ans: 20.8is the nearest round off 20.83


93. Round off 75.195 to nearest hundredths.

Ans: 75.20is the nearest round off 75.195


94. Round off 27.981to nearest tenths.

Solution:

28.0is the nearest round off 27.981


95. Add the fractions 38 and 23.

Ans: Given fraction 38 and 23

Denominator is different so need to cross multiply

Cross multiply the both fraction with each other.

38+23=3×3+8×28×3

=9+1624=2524

The addition of fraction 38 and 23 is 2524.


96. Add the fractions 38 and 634.

Ans: Given fraction is 38 and 634

Now, rewrite the mixed fraction

634=(6×4)+34=24+34=274

Add the following fraction 38 and 274

Cross multiply the both fraction with each other.

3×4+27×88×4=12+21632

=22832=228÷432÷4

=578=718 

The addition of fractions 38 and 634 is 718


97. Subtract 16 from 12.

Ans: Given fraction 16 and 12

Cross multiply the both fraction with each other.

1216=1×61×22×6

=6212

=412=4÷412÷4

=13 

The subtraction of 16 and 12 is 16.


98. Subtract 813 from 1009.

Ans: Given fraction 813 and 1009

Now, rewrite the mixed fraction

813=(8×3)+13=24+13=253

Subtract the following fraction, 253 from 1009

Cross multiply the both fraction with each other.

=1009253

=100925×33×3

=1009759

=100759

=259=279

The subtraction of 1009813=279.


99. Subtract 114 from 12.

Ans: Given fraction 114 and 612

 Now, rewrite the mixed fraction

Now, 114 and 612

(4×1)+14=4+14

=54 

Now, 612

(6×2)+12=12+12

=132

Subtract the following fraction, 54 from 136

13254=13×22×254

=26454

=2654

=214=514

The subtraction of the 13254=514.


100. Add 114 and 612

Ans: The given fraction 112 and 612

Now, rewrite the mixed fraction

114=4+14=54 

612=12+12=132 

Now, 54+132=54+13×22×2 

=54+264 

=5+264 

=314=734

 The addition of the 54+132=734.


101. Katrina rode her bicycle 612km in the morning and 834km in the evening. Find the distance traveled by her altogether on that day.

Ans: The distance covers by Katrina in the morning

=834=(8×3)+34=24+34=274

The distance covers by Katrina in the evening

=834=(8×3)+34=32+34=354

Total distance travelled by her

=132km+354km

=13×22×2km+354km

L.C.M of 2 and 4=4

=264km+354km=(26+35)km4

=614km=1514km

Distance travelled altogether by Katrina in a day is 1514km.


102. A rectangle is divided into a certain number of equal parts. If 16 of the parts so formed represent the fraction 14, find the number of parts in which the rectangle has been divided.

Ans: Let, the number of parts in which the rectangle has been divided be x

According to the question, 16x=14

Cross- multiplication, 16×4=1×x

x=64

64 are the parts in which the rectangle has been divided.


103. Grip size of a tennis racquet is 11980cm. Express the size as an improper fraction.

Ans: Given, Grip size of a tennis racquet is 11980cm

Now, rewrite the mixed fraction

11980=(11×80)+980

=880+980

=88980 

88980 this is a improper fraction.


104. On an average 110 of the food eaten is turned into organism's own body and is available for the next level of the consumer in a food chain. What fraction of the food eaten is not available for the next level?

Let that total food for the eaten is 1 and out of these, 110 of the food eaten is turned into organism's own body.

Now, available for the next level of the consumer in a food chain is 

1110=10110=910

The fraction of food eaten is not available for next level is 910


105. Mr. Rajan got a job at the age of 24 years and he got retired from the job at the age of 60 years. What fraction of his age till retirement was he in the job?

Ans: Given,

Mr. Rajan got a job at the age of 24 years

He got retired from the job at the age of 60 years

Total working year =(60(24))=36year

The required fraction 3660=36÷1260÷12=35

The fraction of his age till retirement was he in the job is 35


106. The food we eat remains in the stomach for a maximum of 4 hours. For what fraction of a day, does it remain there?

Ans: Given, 

The food we eat remains in the stomach for a maximum of 4 hours

Total number of hours in a day is 24.

The required fraction 

424=4÷424÷4=16

The fraction of the day food remains in the stomach is 16


107. What should be added to 25.5to get 50 ?

Ans: Let x should be added to 25.5 to get 50

Now,

25.5+x=50

x=5025.5=24.5 

The required number is 24.5

The number that should be added to 25.5 to get 50 is 24.5


108. Alok purchased 1kg200g potatoes, 250g dhania, 5kg300g onion, 500g palak, and 2kg600g tomatoes. Find the total weight of his purchases in kilograms.

Ans: Convert all the data in a signal unit, kg

1kg=11000g

Given,

Alok purchased 1kg200g potatoes, 

250g dhania, 

5kg300g onion, 

500g palak,

2kg600g tomatoes 

=1kg200g=1kg+2001000kg=1.200kg of potatoes

=0kg250g=0kg+2501000kg=0.250kg of dhania

=5kg300g=5kg+3001000kg=5.300kg of onion

=0kg500g=0kg+5001000kg=0.500kg Of palak

=2kg600g=2kg+6001000kg=2.600kg Of tomatoes

Total weight is 1.200+0.25+5.300+0.500+2.600=9.850

Total weight of the purchase is 9.850kg

The total weight of purchase of Alok in kilograms is 9.850kg.


109. Arrange in ascending order: 0.011,1.001,0.101, and 0.110

Ans: Since, all the decimals are already given in like fractions, 

0.011,1.001,0.101,0.110

Arranging them in ascending order, we get 0.011,0.101,0.110,1.001


110. Add the following: 20.02 and 2.002

Ans: We have, 20.02 and 2.002

To add the above decimals, we must convert them into like decimals first. 

Writing 20.020 and 2.002 in a column

So,

20.020+2.002=22.022

Addition of 20.020 and 2.002 is 22.022


111. It was estimated that because of people switching to Metro trains, about 33000 tonnes of CNG, 3300tonnes of diesel and 21000 tonnes of petrol was saved by the end of the year 2007. Find the fraction of:

(i) The quantity of diesel saved to the quantity of petrol saved.

Ans: Given,

By the end of the year 2007 Metro trains was saved

33000  tonnes of CNG

3300 tonnes of diesel

21000 tonnes of petrol

 The quantity of diesel saved  The quantity of petrol saved =330021000

=3300÷30021000÷300

=1170


(ii) The quantity of diesel saved to the quantity of CNG saved.

Ans:   The quantity of diesel saved  The quantity of CNG saved =330033000

=3300÷330033000÷3300

=110

The quantity of diesel saved to quantity of petrol is 1170 

The quantity of diesel saved to the quantity of CNG is 110


112. The energy content of different foods are as follows

Food

Energy Content per kg

Wheat 

3.2 Joules

Rice

5.3 Joules

Potatoes (Cooked)

3.7 Joules

Milk

3.0 Joules


Which food provides the least energy and which provides the maximum?

Express the least energy as a fraction of the maximum energy

Ans: From the given table it is clear that Milk provides the least energy and Rice provides the maximum

Ratio of the least energy to the maximum energy

 The least energy  The maximum energy =35.3=3×105.3×10=3053

The least energy as a fraction of maximum energy is 3053.


113. A cup is 13 full of milk. What part of the cup is still to be filled by milk to make it full?

Ans: Total fill required of a cup of milk is 1

Given that Cup is 13 full of milk

The remaining part of the cup which is still to be filled by milk 

=113=313

=23

The part of cup is still to be filled by milk to make it full is 23.


114. Mary bought 312m of lace. She used 134m of lace for her new dress. How much lace is left with her?

Ans: Mary bought 312m of lace

She used 134m of lace for her new dress

Left lace = bought 312m of lace used 134m of lace

Rewrite the fraction in same denominator

=7×22×2m74m=14m7m4

=74m=134m of lace

The lace left with her is 74m.


115. When Sunita weighed herself on Monday, she found that she had gained 114kg. Earlier her weight was 4638kg. What was her weight on Monday?

Ans: Sunita had gained =114g=54kg

Earlier her weight was 4638kg=3718kg

Her total weight on Monday

=3718kg+54kg

=3718kg+5×24×2kg

=3718kg+108kg

=(371+10)8kg=3818kg

=4758kg

Her weight on Monday was 4758


116. Sunil purchased 1212 litres of juice on Monday and 1434 litres of juice on Tuesday. How many litres of juice did he purchase together in two days?

Ans: Monday Sunil purchased 1212 liters of juice =252 liters

Tuesday Sunil purchased 1434 liters of juice =594 liters

Total quantity of juice Sunil purchased in two days =(252+594) litres

=(25×22×2+594) litres 

=(504+594) litres

=(50+594) litres 

=1094 litres

=2714 litres

Litres of juice he purchased in two days is 2714


117. Nazima gave 234 litres out of the 512 litres of juice she purchased to her friends. How many litres of juice is left with her?

Ans: Total quantity of juice =512 litres =112 litres

Nazima gave to her friends =234 litres =114 litres

The required quantity of juice she is left with 

=(112114) litres 

=(11×22×2114) litres

=(22114) litres

 =114 litres

=234 litres

The litre of juice left with her is 234 litres


118. Roma gave a wooden board of length 15014cm to a carpenter for making a shelf. The Carpenter sawed off a piece of 4015cm from it. What is the length of the remaining piece?

Ans: Total length of wood 15014cm=6014cm

Wood used by carpenter 4015cm=2015cm

Remaining piece of wood length

=(60142015)cm=(601×54×5201×45×4)cm

=(30052080420)cm

=220120cm or 110120cm

The length of the remaining piece is 110120cm


119. Nasir travelled 312km in a bus and then walked 118km to reach a town. How much did he travel to reach the town?

Ans: Nasir travel 312km in a bus =72km

Walked 118km to reach a town =98km

Total distance covered by Nasir

  (72+98)km

   =(7×8)+(9×2)2×8km

   =56+1816km 

   =7416km

   =74÷216÷2km

   =378km

   =458km 

The distance he travelled to reach the town is 378km or 458km


120. The fish caught by Neetu was of weight 334kg and the fish caught by Narendra was of weight 212kg. How much more did Neetu's fish weigh than that of Narendra

Ans: The weight of fish caught by Neetu 334kg=154kg

The weight of fish caught by Narendra 212kg=52kg

Neetus fish weigh more than that of Narendra by

  154kg52kg=154kg5×22×2kg

   =154kg104kg 

   =(1510)4kg

   =54kg or 114kg 

Neetu fish weighed 54kg or 114kg more than Narendra.


121. Neelam's father needs 134m of cloth for the skirt of Neelam's new dress and 12m for the scarf. How much cloth must he buy in all?

Ans: Neelam's father needs 134m(74m) of cloth for the skirt of Neelam's new dress  

12m for the scarf.

Total cloths buy by her father

 =74m+12m

   =74m+1×22×2m

   =74m+24m 

=(7+2)4m

=94m or 213m

The total cloth Neelam should buy is 94m or 213m


122. What is wrong in the following additions?


seo images


Ans: Equal denominators added.


seo images


Ans: Numerator and denominator are added.


123. Which one is greater?

1 meters 40 centimeters +60 centimeters or 2.6 meters.

Ans: Know that 1m=100cm

1cm=1100m

Now,

1 meters 40 centimeters +60 centimeters.

=1m+40100m+60100m

1m+0.40m+0.60m=2.00m

So, 2.6m>2.0m


124. Match the fractions of Column I with the shaded or marked portion of figures of Column II:

Column I

Column II

(i) 64

(A)

seo images

(ii) 610

(B)

seo images

(iii) 66

(C)

seo images

(iv) 616

(D)

seo images


(E)

seo images


Ans:

Match the correct following

Column I

Column II

(i) 64

(D)

seo images

(ii) 610

(A)

seo images

(iii) 66

(E)

seo images

(iv) 616

(B)

seo images


125. Find the fraction that represents the number of natural numbers to total numbers in the collection 0,1,2,3,4,5. What fraction will it be for whole numbers?

Ans: From the of collection 0,1,2,3,4,51,2,3,4,5 is natural numbers

The fraction that represents the number of natural numbers to the total numbers =56 

The whole numbers are 0,1,2,3,4and 5.

The fraction that represents the number of whole numbers to the total numbers =66


126. Write the fraction representing the total number of natural numbers in the collection of numbers 3,2,1,0,1,2,3.  What fraction will it be for whole numbers? What fraction will it be for integers?

Ans: Total collection of numbers 3,2,1,0,1,2,3 and out of these 1,2 and 3 is natural number and 0,1,2 and 3 are whole number and 3,2,1,0,1,2,3 are integers.


127. Write a pair of fractions whose sum is 711 and difference is 211

Ans: Let one fraction be x

Another fraction be 711x Now, according to question, 

x(711x)=211

x711+x=211

11x11711+11x11=211

11x7+11x11=211

22x7=211×11

22x7=2

22x=2+7=9

x=922

Thus, the fraction is 922 and another fraction is

711922=7×211×2922

=14922

=522 

Pair of fractions are 922 and 522.


128. What fraction of a straight angle is a right angle?

Ans: Since, we know that the measurement of a straight angle is 180 and a right angle is 90. The required fraction is 90180=12.

The fraction of straight angle is a right angle is 12.


129. Put the right card in the right bag

Cards 

Bags

(i) 37

(ii) 44

(iii) 98

(iv) 89

(v) 56

(vi) 611

(vii) 1818

(viii) 1925

(ix) 23

(x) 1317

seo images

seo images

seo images


Ans: 

fractions whose numerators are less than the denominators are called proper fractions. (Numerator < denominator) and fraction is less than one.

fractions with the numerator either equal to or greater than the denominator are called improper fractions. (Numerator = denominator or, Numerator > denominator) and the fraction is greater and equal than one.

Now, cards in Bag -I

(i) 37

(iv) 89

(v) 56

(vi) 611

(viii) 1925

(ix) 23and (x) 1317

Cards in Bag-II

(ii) 44 and (vii) 1818

Cards in Bag -III

(iii) 98


What do we Learn in NCERT Exemplar Solutions for Class 6 Mathematics Chapter 4 Fractions and Decimals?

NCERT Exemplar solutions for Class 6 Mathematics Chapter 4 Fractions and Decimals consists of a fraction which is a number that represents a fraction of a total. This complete may be a single item or a set of items. Fractions with 10, 100 denominators, etc. can be written in the correct order, using a decimal point, called decimal or decimal numbers. Let us now consider some of the concepts discussed in this Chapter.

  • Multiplication and division of fractions and other concepts, such as types of fractions.

  •  How to change different fractions to like fractions

  •  How to compare more than two fractions.

  •  How to turn a decimal into a fraction.

  •  Converting a fraction into a decimal, adding, and subtracting decimal.

  •  Decimal multiplication by 10, 100, 100, etc.

  •  Decimal multiplication by a whole number, decimal multiplication by the decimal.


Key Topics for NCERT Exemplar Class 6th Mathematics Solutions Chapter 4: Components and Decimals

Introduction:

A fraction is a number that represents a fraction of a sum. A theme can be a single object or a set of objects. The parts are equal in quantity.


Proper Fraction:

In the right fraction, the number indicates the number of parts considered and the denominator indicates the number of parts in which the total is divided. Therefore, the denominator is always greater than the number in the correct fraction.


Improper Fraction:

Fractions where the number is greater than the denominator, are known as Improper fractions.


Mixed Fraction:

The component numbers that consist of both, part and total, are known as Mixed Fractions. The mixed part can be shown as the wrong part.


Equivalent Fraction:

Equivalent fractions represent the same part of the whole. To find the equal part of a given fraction, you can multiply or divide the number and the denominator of a given fraction by the same number.


Simplest Form of Fraction:

If there are no common features between a number and a denominator, the component should be the simplest.


Like and Unlike Fractions:

Like fractions with the same denominator while different fractions have different denominators. Fractions can be compared by turning them into parallel pieces and arranging them in an ascending or descending order.


Adding and Subtraction:

  • Adding and subtracting similar fractions is done by adding their numbers.

  • Adding and subtracting different fractions is done by translating them into the same fractions.


Decimals:

  • One-tenth of a block is divided into 10 parts and 100 parts can be written as 0.1 and 0.01 by the decimal point, where the dot is the decimal point and reaches the tenth place respectively.

  • All decimals can also be represented on a number line.

  • All decimals can be written as fractions.

  • When decimals are compared, every part is first compared, then tens and so on.

  • Addition and subtraction of decimals can be done in the same way as whole numbers by adding/subtracting one hundredth from one hundred and one-tenth out of ten, one in one and so on.

  • Decimals have many applications in our daily lives such as representing different units of measurement or representing parts of every business.

WhatsApp Banner

FAQs on NCERT Exemplar for Class 6 Maths Solutions Chapter 4 Fractions & Decimals

1. Why should I follow NCERT Exemplar solutions for Class 6 Mathematics Chapter 4 Fractions and Decimals?

NCERT Exemplar Solutions for Class 6 Mathematics Chapter 4 Fractions and Decimals PDF is available for download on the Vedantu website. Our professional teachers formulate these exemplar questions to help you prepare for the exams, to get good marks in Mathematics. Students who wish to get good marks in Mathematics actively practice NCERT Exemplar Solutions for Grade 6 Mathematics. This book is one of the best when it comes to giving a quiz bank to practice. Therefore, to acquire good marks a student should never ignore practicing Exemplar questions.

2. Why will a student choose Vedantu among all other websites for downloading Exemplar questions?

The NCERT Exemplar Class 6 mathematical solutions for Chapter 4 are designed to help you make the most of your time and make the best use of your time with Vedantu. NCERT Exemplar solutions were created following the latest CBSE pattern. It is free of cost and is available for the students for free download. We have been constructing the most important question bank set for the students regularly so that the students of Class 6 are not deceived and they do the correct preparation. This is the sole reason the students should choose Vedantu among all other websites for downloading NCERT Exemplar Class 6 mathematical solutions for Chapter 4 Fractions and Decimals.

3. What are the important topics for NCERT Exemplar Class 6 Mathematics solutions Chapter 4 Fractions and Decimals?

Chapter 4 of the NCERT Exemplar contains a variety of tests such as multiple-choice questions, fill in the blanks, true or false and other very dependent questions.

  • Examples of NCERT exercise solutions are professionally prepared in such a way that these questions will be easily understood and will help you to practice firmly.

  • There are optional questions where you have to do addition, subtraction and multiplication of fractions and decimals.

  • For other questions, you must indicate whether the given pieces are right or wrong. You should also find the area value and the face value of the digits.

4. What are the benefits of solving NCERT Class 6 Mathematics Exemplar solutions Chapter 4?

The NCERT Class 6 Mathematics Exemplar Solutions Chapter 4 prepared by Vedantu is a very important resource for your 6th-grade exams.

  • Vedantu provides you with simple language solutions and easy to understand Chapter concepts.

  • The solutions provided by Vedantu’s subject matter experts will also help you prepare for advanced ideas in the upper Classes.

  • These exemplary 6th-grade math solutions will provide you with a solid foundation for completing tests at an advanced level such as the NTSE exams.

5. What are some of the main concepts to be remembered from NCERT Exemplar Class 6 Chapter 4 Fractions and Decimals?

Fractions can be compared by turning them into equal parts and arranging them in an ascending or descending order.

  • Addition (or subtraction) of the same fractions can be done by adding (or deleting) their numbers.

  • Fractions with 10,100 denominators, etc. can be written in the correct order, using a decimal point, called decimal or decimal numbers.

  • Decimal numbers can be compared using the concept of place value and can then be arranged in an ascending or descending order.

  • Decimals can be added (or removed) by writing them in equal numbers of decimal places.

  • Many problems of daily life can be solved by changing the units of various measurements such as amount, length, weight, etc. in the form of decimal and then adding (or subtracting).