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Cannizzaro Reaction

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What is Cannizzaro Reaction?

Named after Stanislao Cannizzaro, it is a disproportionation reaction. When two molecules of an aldehyde are disproportionated by a base, leading to the formation of a carboxylic acid and primary alcohol, the reaction is termed the Cannizzaro reaction.


It is only possible in aldehydes that lack a Hydrogen atom on their $\alpha$ Carbon. When such aldehydes are treated with concentrated bases like $50% \ NaOH, \ KOH, \ Na_2CO_3$, they are disproportionated, one molecule is reduced to an alcohol, and one is oxidised to carboxylic acid.


Since the rate-determining step of the Cannizzaro reaction is hydride transfer towards the Carbonyl, a concentrated base is necessary because a dilute base cannot make hydride transfer.


Carbonyl Bond

The double bond between carbon and oxygen is known as the carbonyl bond, which can be represented as $(C=O)$. Multiple groups, like aldehydes, ketones, carboxylic acids, etc., are some groups containing the carbonyl bond. Usually, a weak nucleophile is attached to the carbonyl carbon, which can easily be removed. Since oxygen is more electronegative than carbon, the bond is polar.


The carbon, thus, has a partial positive charge on it. This makes the carbonyl carbon a very good centre for nucleophiles to attack. As nucleophiles, $Nu^-$ attack, the stronger one replaces the weaker one through an addition-elimination mechanism.


Representation of Strong nucleophile replaces the weaker nucleophile



Strong nucleophile replaces the weaker nucleophile


Nucleophiles

Nucleophiles are positive charge-seeking species. These may be negatively charged species with a super-octet or species with lone pairs. These attack the positive centres and bond with them. In the presence of a weak nucleophile, these perform substitution elimination reactions, wherein the elimination of a weaker nucleophile follows the addition of a stronger nucleophile. Examples of nucleophiles include $R-S^- , CN^- , OH^- ,$ etc.


Cannizzaro Reaction Mechanism 

To understand a reaction- estimate the possible products, the factors that affect it and how they affect it, we need to understand how a chemical reaction occurs. This is done by understanding its mechanism. The Cannizzaro reaction occurs in three steps, wherein the second step is the slowest and, thus, the rate-determining step. It is overall a substitution reaction, i.e., one group replaces the other in the broad sense. However, when understood in steps, it is an addition reaction followed by elimination. But, by addition-elimination only carboxylic acid is prepared. Nucleophilic addition whereas prepares the alcohol.


Step 1: Attack of the nucleophile.

A base ionises and disintegrates to give a cation and $OH^-$ . The hydroxide ion acts as a nucleophile and attacks the carbonyl carbon, which has positive polarity. Due to this, one bond between carbon and oxygen breaks and a negative charge appears on the oxygen atom. Here, disproportionation takes place.


Representation of equation where Nucleophile OH- is attached on a carbonyl Carbon


Attack of Nucleophile $(OH^-)$ on a carbonyl Carbon


Step 2: Addition elimination to form carboxylic acid.

Although hydroxide ion is a better leaving group than hydride ion, the bond between Hydrogen and carbonyl carbon breaks, giving out a hydride. This is because the solution already has an excess of hydroxide ions, which makes it easier for a hydride ion to be added to the solution. This leads to the formation of carboxylic acid. This step is the slowest step and the rate-determining step of the reaction.


Release of Hydride ion and formation of carboxylic acid


Release of Hydride ion and formation of carboxylic acid


Step 3: Attack of hydride and formation of alcohol.

Hydride acts as a nucleophile and attacks the other carbonyl carbon, forming alkoxide ion.


Attack of Hydride ion on another Carbonyl carbon to give alcohol


Attack of Hydride ion on another Carbonyl carbon to give alcohol


Since alkoxide ion is a strong base, it makes the carboxylic acid lose its Hydrogen, finally forming carboxylate ion and alcohol. This exchange occurs rather quickly.


Equation representing the Formation of salt of carboxylic acid


Formation of salt of carboxylic acid


Thus, from two moles of aldehyde, one mole of carboxylic acid and one mole of alcohol are produced.


Types of Cannizzaro reaction

  1. Cross Cannizzaro Reaction

Under ideal circumstances, just half of the necessary amounts of alcohol and carboxylic acid are produced by the crossed Cannizzaro reaction. The needed product can be made entirely from 2 distinct carbonyl compounds, increasing the output of the important molecule. The more reactive aldehyde, i.e., the one with more positive polarity on its carbonyl carbon, oxidises to acid, whereas the one with the less reactive carbonyl carbon converts to alcohol. The cross-Cannizzaro reaction may help increase desirable output.


Formation of formic acid and benzoic acid by Cross Cannizzaro Reaction


Cross Cannizzaro Reaction


  1. Intramolecular Cannizzaro Reaction

It is possible in such chemical substances with at least two carbonyl carbons lacking an $\alpha$ hydrogen.


Equation showing Intramolecular Cannizzaro Reaction


Intramolecular Cannizzaro Reaction


Summary

A quick and effective method for performing the Cannizzaro reaction was developed. A non-enolizable aldehyde can be made disproportionate using the Cannizzaro reaction. The cross-Cannizzaro reaction is used to boost the yield of the valuable chemical. The advantages of the current approach over earlier ones are its environmental friendliness, superior yield to those of earlier methods discussed, lack of need for specialised equipment, ease of operation, non-hazardous nature, and simplicity.


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FAQs on Cannizzaro Reaction

1. What are the conditions required for the Cannizzaro reaction?

In the Cannizzaro reaction, two molecules of an aldehyde mix with a hydroxide base to produce a primary alcohol and a carboxylic acid. This is demonstrated by the example of benzaldehyde, which produces benzyl alcohol to produce benzoic acid. Two molecules of an aldehyde and a hydroxide base are combined in the Cannizzaro reaction, a disproportionation reaction that yields primary alcohol and carboxylic acid. This is seen by how benzaldehyde and benzyl alcohol react to form benzoic acid.

2. Why does the Cannizzaro reaction require strong bases?

It's crucial to remember that the Cannizzaro reaction is only possible with non-enolizable aldehydes. This reaction's strong base would also start aldol and other enolate anion-based reactions. When benzaldehyde C6H5CHO is treated with KOH, the appropriate alcohol and acid are produced. In this process, benzaldehyde contains no alpha hydrogen atoms. As a result, it experiences the Cannizzaro reaction, whereby one of its molecules is oxidised to benzoic acid while the other is reduced to benzyl alcohol.

3. Where may one use the Cannizzaro reaction?

Applications and Uses of the Cannizzaro Reaction in Industry: Neopentyl glycol is used in polyesters to make resins for varnish coatings, synthetic lubricants, plasticisers, and resins for building boats and aeroplanes. The neopentyl structure offers excellent resistance to heat, light, and hydrolysis. Given that neither the yield of the produced acid nor alcohol is greater than 50%, the Cannizzaro reaction has a limited application in chemical synthesis.


The aldol condensation reaction occurs preferentially for aldehydes that do include hydrogens. A non-enolizable aldehyde can be disproportionate under the control of the Cannizzaro reaction. The cross-Cannizzaro reaction is used to boost the yield of the valuable chemical.