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KCET 2014 Previous Year Question Paper for Maths, Physics, Chemistry & Biology

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Karnataka CET Question Paper - Year 2014

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  • Our subject matter experts have solved CET Exam 2014 Question Papers that are at par with the latest KCET exam pattern. Kindly go through the solutions provided below.

Karnataka CET Question Paper - Year 2014

KCET 2014 Maths Question Paper

Q1: in a Class With a Strength of 60 Students, There is the Following Data:

  1. 25 students play cricket

  2. 30 students play tennis

  3. 10 students play both cricket and tennis

Find the number of students who don’t play either of the games.

Options: 

  1. 0

  2. 35

  3. 45

  4. 25

Objective Answer: (d)

Explanation: By Venn Diagram, we get our answer as 25.


Q2: Determine the area of the region bounded by two parabolas y = x2 and x = y2.

Options

  1. ⅓ 

  2. 4

  3. ¼ 

  4. 3

Objective Answer: (a)

Explanation: Referring to the following figure, we get the area of the region covered by two parabolas as ⅓ sq unit.

(Image to be added soon)


KCET 2014 Physics Question Paper

Q1: What Will Be the Revolution of Earth’s Satellite If We Ignore Its Height Above the Surface of the Earth?

Options:

  1. 85 minutes

  2. 156 minutes

  3. 90 minutes

  4. 87.73 minutes

Objective Answer: (d)


Q2: on Attaching a 10 Kg Metal Block to a Spring (having K = 1000n/m), it Is Displaced from Its Equilibrium Position by 10 cm and Released. Determine It’s Maximum Acceleration.

Options: 

  1. 10 ms-2

  2. 200 ms-2

  3. 0.1 ms-2

  4. 100 ms-2

Objective Answer: (a)

Explanation: We know that angular velocity,  ω =\[\sqrt{ \frac{k}{m} }\] = \[\sqrt{ \frac{1000}{10} }\] = 10 rad/s, and

Block’s maximum acceleration, aMAX = - ω2A = - (10)2* 0.1= - 10 ms-2


KCET 2014 Chemistry Question Paper 

Q1: If 25 cm3 Oxalic Acid Completely Neutralizes 0.064g of NaOH,  Then Find the Molarity of the Oxalic Acid.

Options:

  1. 0.045

  2. 0.0642

  3. 0.032

  4. 0.015

Objective Answer: (c)

Explanation: We know that Molarity, M = ( no of moles of solute)/(Volume of solution (in L))

=>  Molarity = (0.064  x 1000)/(40 x 25)= 0.032


Q2: When is the density of Carbon Monoxide (CO) maximum?

Options: 

  1. At 2 atm, & 600 K

  2. At 4 atm, & 500 K

  3. At 0.5 atm, & 273 K

  4. At 6 atm, &1092 K

Objective Answer: (b)


KCET 2014 Biology Question Paper

Q1: Which One is True for the Eutrophicated Water Body?

Options: 

  1. High Mineral Content

  2. Low Organic Content

  3. High Oxygen Content

  4. Rich Species Diversity

Objective Answer: (a)

Explanation: Eutrophication is the process in which the water body becomes excessively rich in nutrients, leading to the abundant growth of plant life.


Q2: Which Among the Following Hormones Produce Anti-Inflammatory Reactions in Man and Inhibit the Immune Response Besides Its Primary Functions?

Options: 

  1. Thymosin

  2. Erythropoietin

  3. Thyrocalcitonin

  4. Cortisol

Objective Answer: (d)

Explanation: Cortisol is a type of Glucocorticoids. It is an anti-inflammatory hormone that generates anti-inflammatory reactions and oppresses the immune response.


Download KCET 2014 PYQP Answer Keys

KCET 2014 Previous Year Question Paper is available here along with Answer Keys for all the versions of PCMB Papers. Click on the link specified below:


Download KCET 2014 Question Papers with Solutions PDF

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  1. Concise Solutions to the KCET PYQP.

  2. Easily downloadable Answer keys for all the versions of PCMB Question Papers are available on our website. 

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  4. Free Guess Papers, Sample Papers, Set of highlighted/Repetitive Questions, Answer keys and solutions are available at the bottom of these papers.

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FAQs on KCET 2014 Previous Year Question Paper for Maths, Physics, Chemistry & Biology

1. What is the difficulty level of the KCET Exam?

KCET Exam is a state-level exam; it is less difficult than the JEE Main Exam. However, subjects like Physics and Chemistry have high difficulty in this exam.

2. Are 12th marks important for deciding your rank in the KCET exam?

The eligibility criteria for the KCET exam is the students must have passed 12th or 2nd PUC. 

The procedure for determining the candidate’s rank in the KCET Exam is listed below:

  1. 50% score is taken from the marks obtained in the board exam subjects including Physics, Chemistry and Mathematics/Biology.

  2. 50% score is taken from the score you gained in the KCET examination.

Hence, 50% + 50% score determines your rank in the KCET Exam.

3. What rank will I get if I score 105 in the KCET Exam and have scored 95% in board exams through PCM?

As per the latest data on the Expected cut-off in the KCET Exam 2020, if the candidate’s KCET marks lie between 100 and 110 marks range (out of 180), he/she may hold the rank between 2001-2500.

4. How can I achieve a rank below 5000 in the KCET Exam?

For achieving a rank below 5000, the following are the marks a candidate must have scored:

  1. Above 90% in the 2nd PUC, and

  2. 120+ in the KCET Exam.