Summary of HC Verma Solutions Part 1 Chapter 9: Centre of Mass, Linear Momentum, and Collision
FAQs on HC Verma Solutions Class 11 Chapter 9 - Centre of Mass, Linear Momentum, and Collision
1. What are the topics covered in HC Verma solutions for class 11 physics part 1 chapter 9 center of mass linear momentum collision concepts?
The topics covered in HC Verma solutions for class 11 physics part 1 chapter 9 center of mass linear momentum collision concepts.
Centre of Mass
Centre of Mass of Continuous Bodies
The motion of the Centre of Mass
Linear Momentum and its Conservation Principle
Rocket Propulsion
Collision
Elastic Collision in One Dimension
Perfectly Inelastic Collision in One Dimension
Coefficient of Restitution
Elastic Collision in Two Dimensions
Impulse and Impulsive Force
All the above concepts and the related problems and solutions are provided here in detail for the benefit of the students. The solutions are made available as a free PDF download for easy access for students.
2. A uranium-238 nucleus, initially at rest, emits an alpha particle with a speed of 1.4 × 107 m/s. Calculate the recoil speed of the residual nucleus thorium-234. Assume that the mass of a nucleus is proportional to the mass number.
Mass of the uranium-238 nucleus, m = 238 (Given)
The initial speed of the nucleus = u = 0 m/s
The final speed of the nucleus = v
The final speed of the alpha particle = v2 = 1.4 × 107 m/s
Mass of the nucleus after emission, m1 = 234
Mass of the alpha particle, m2 = 4
Applying conservation of momentum, mu = m1v1 + m2v2
238×0 = 234 v + 4 × 1.4 × 107
v = –2.39 × 105 m/s or –2.4 × 105 m/s (approx.)
3. During heavy rain, hailstones of the average size of 1.0 cm in diameter fall with an average speed of 20 m/s. Suppose 2000 hailstones strike every square meter of a 10 m × 10 m roof perpendicularly in one second and assume that the hailstones do not rebound. Calculate the average force exerted by the falling hailstones on the roof. The density of a hailstone is 900 kg/m3.
Here d = 1 cm, v = 20 m/s and u = 0, and density = 900 kg/m3
Mass of a hailstone, m = Density × Volume
= 900 × 4/3 × π × (Radius)3
= 900×4/3× π×(0.5×10-2)3
= 0.471×10-3kg
Mass of 2000 hailstones, M = 2000×m = 0.942 kg
Rate of change in momentum per unit area = Rate of change of momentum
= M× (20 – 0)
= 18.84 N or 19 N (approx.)
The total force exerted on the roof = 19 × area of the roof
= 19 × 10 × 10 = 1900 N
4. Why must students refer to the HC Verma books and solutions?
HC Verma is considered the father of Class 12 physics. It has problems and solutions for all difficulty levels. One must refer to HC Verma to learn the various important concepts in depth and with a proper foundation. The HC Verma books ensure it teaches the students all the basic concepts along with guiding them. Vedantu helps you to get the best study material that has all the important topics and is designed in an organised manner by the best teachers. You can score more marks by practising on the worksheet provided on the site and you can get one-on-one guidance to clear all your doubts.
5. What are the advantages of practising worksheets for class 11 physics chapter 9?
Worksheets are made by expert teachers and it has all the important questions that can come in exams. The pattern of worksheets is just like an exam paper and it allows you to practice time management so that you can attempt all the questions within the stipulated time limit. By practising the worksheet you get to know the different patterns in which questions can be asked and so you can get deep knowledge of the topic. By practicing more worksheets you get more of an idea of step to step answering a question. It helps you to score more in exams.