Important Formulas for JEE Advanced 2025: Mathematics, Physics and Chemistry Formulas
JEE Advanced is a highly difficult engineering admission exam in India that requires extensive preparation as well as mastery of a variety of topics and formulas. Formulas are used to solve difficult problems and equations in physics, chemistry, and mathematics. Candidates taking JEE Advanced must extensively learn and practise formulas in order to perform well in the exam. Students must understand JEE Advanced formulas in this context in order to pass this extremely tough exam. In this article, we'll go over some of the most important JEE Advanced formulas that students need to know in order to do well on the exam.
Circle, 3-D Geometry, Vectors, Trigonometry, Limits, and Application of Derivatives are some of the significant formulas for JEE Advanced in Mathematics. Alternating current, simple harmonic motion, thermodynamics, waves, and wave optics are all significant formulas in physics. Chemical equations, stoichiometry, and gas laws are all significant formulas in chemistry.
Because the JEE syllabus is so wide and comprehensive, it can be difficult to retain all of the concepts and formulas as you progress through your preparation. In this essay, we'll look at some techniques for remembering JEE formulas for a long period, at least till you finish JEE Main and Advanced.
How Can JEE Advanced Formulas Assist?
Before you begin your preparations, gather your study materials.
As you prepare for the exam, make separate notes for the relevant formulas for each subject.
These useful notes aid with focusing on the concepts.
It aids in the management of exam time.
It improves in calculation.
Reduces the possibility of errors.
Differences Between Topics For JEE Advanced and JEE Main
The syllabus for these assessments varies as well. The JEE Main syllabus contains topics from grades 11 and 12 in Mathematics, Physics, and Chemistry. The JEE Advanced test will cover a few extra topics.
Subject | Topics in Advanced but Not in Main | Topics in Mains but not in Advanced |
Mathematics | - | Sets, Relations and Functions, Statistics and Probability, Trigonometry, Mathematical Reasoning |
Physics | Thermal Physics | Electronic Devices, Electromagnetic Waves, Communication Systems |
Chemistry | Electrochemistry: Equivalent Conductivity, Nuclear Chemistry | Biomolecules, Chemistry in Everyday Life |
These are the key differences between JEE Mains and JEE Advanced that you should be aware of before beginning your preparations.
Important Physics Formulas for JEE Advanced 2025
The JEE Advanced Physics section is regarded as Moderate to Difficult due to lengthy derivations and a wide range of topics. The Mechanics, Electricity and Magnetism, Thermodynamics, Optics, and Modern Physics sections of the JEE Advanced 2025 test cover a wide range of topics. Let us look at some crucial list of formulas for JEE Advanced 2025.
Kinematics Formulas:
Average speed = Total distance/Total time
Average velocity = Total displacement/Total time
Acceleration = (Final velocity - Initial velocity) / Time taken
Final velocity = (Initial velocity + Acceleration) × Time taken
Displacement = (Initial velocity + Final velocity) / 2 × Time taken
Newton's Laws of Motion:
$F = m \times a$ (Newton's Second Law of Motion)
Force of friction $= \mu \times N$ (where $\mu$ is the coefficient of friction and N is the normal force)
Weight $= m \times g$ (where g is the acceleration due to gravity)
Impulse = force $\times$ time
Law of Conservation of Momentum: Momentum before collision = Momentum after collision
Work, Energy, and Power Formulas:
Work = force $\times$ displacement $\times$ $\cos \theta$
Kinetic Energy $= 0.5 \times m \times v^2$
Potential Energy $= m \times g \times h$
Total Mechanical Energy = Kinetic Energy + Potential Energy
Power = work done/time taken
Electric Charge and Fields Formulas:
Electric Field = force per unit charge $= \dfrac{F}{Q}$
Coulomb's Law: $F = \dfrac{k \times (q_1 \times q_2)}{r^2}$
Electric Potential Energy $= q \times V$
Electric Potential $= \dfrac{V}{d}$
Energy of electric dipole:
$U = – \rho E$
Energy of a magnetic dipole:
$U = – \mu B C$
Electric Charge:
$Q = \pm ne$ (where $e = 1.60218 \times 10^{-29} C$), SI unit of Electric Charge is Coulomb ©
Coulomb’s Law:
Electrostatic Force (F) $= k\left[\dfrac{q_1q_2}{r_2}\right]$ and,
In Vector Form :
$\vec{F} = k(q_1q_2) \times \dfrac{\vec{r}}{r^3}$,
Where $q_1$ and $q_2$ are Charges on the Particle,
r = Separation between them,
$\vec {r}$ = Position Vector,
$k$ = Constant $= \dfrac{1}{4}\pi \epsilon_0 = 8.98755 \times 10^9Nm^2C^2$
Electric Current :
The current at Time $t : i = \underset{\Delta t \to 0}{lim} \dfrac{\Delta Q}{\Delta t} = \dfrac{dQ}{dT}$
Where $\Delta Q$ and $\Delta T$ = Charges crosses an Area in time $\Delta T$
SI unit of Current is Ampere (A) and 1A = 1 C/s
Average current density:
$\vec{j} = \dfrac{\Delta i}{\Delta s}$
$j = \underset{\Delta s \to 0}{lim}\dfrac{\Delta i}{\Delta s} = \dfrac{di}{dS}$
$j = \dfrac{\Delta i}{\Delta S \cos \theta}$
Where, $\Delta S$ = Small Area,
$\Delta i$ = Current through the Area $\Delta S$,
P = Perpendicular to the flow of Charges,
$\theta$ = Angle Between the normal to the Area and the direction of the current.
Kirchhoff’s Law:
Law of Conservation of Charge: $I_3 = I_1 + I_2$
Resistance:
Resistivity : $\rho (T) = \rho (T_0)\left[1 + \alpha (T − T_0)\right]$
$R (T) = R (T_0) \left[1 + \alpha (T−T_0)\right]$
Where, $\rho (T)$ and $\rho (T_0)$ are Resistivity at Temperature $T$ and $T_0$ respectively,
$\alpha$ = Constant for given material.
Lorentz Force :
$\vec F = q\left[\vec E + (\vec v \times \vec B)\right]$
Where, E = Electric Field,
B = Magnetic Field,
q = Charge of Particle,
v = Velocity of Particle.
Magnetic Flux:
Magnetic Flux through Area $dS = \varphi = \vec{B} \cdot d\vec{S} = B \cdot dS \cos \theta$
Where, $d\vec{S}$ = Perpendicular vector to the surface and has a magnitude equal to are Ds,
$\vec{B}$ = Magnetic Field at an element,
$\theta$ = Angle Between $\vec{B}$ and $d\vec{S}$,
SI unit of Magnetic Flux is Weber (Wb).
Straight line Equation of Motion (Constant Acceleration):
$v = u + at$
$s = ut + \dfrac{1}{2at^2}$
$2as = v^2 − u^2$
Gravitational Acceleration Equation of Motion:
Motion in Upward Direction:
$v = u - gt$
$y = ut − \dfrac{1}{2gt^2}$
$−2gy = v^2 − u^2$
Motion in Downward Direction:
$v = u + gt$
$y = ut + \dfrac{1}{2gt^2}$
$2gy = v^2 − u^2$
Projectile Equation of Motion:
Horizontal Range $(R) = \dfrac{u^2 \sin2θ}{g}$
Time of Flight $(T) = \dfrac {2u \sin \theta}{g}$
Maximum Height $(H) = \dfrac{u^2 \sin 2\theta}{2}$
Where, u = initial velocity,
v = final velocity,
a = constant acceleration,
t = time,
x = position of particle.
Laws of Gravity
Universal Law of Gravitation:
Gravitational force $\vec{F} = G\left[\dfrac{Mm}{r^2}\right]^r$
Where, M and m = Mass of two Objects,
r = separation between the objects,
$\cap{r}$ = unit vector joining two objects,
G = Universal Gravitational Constant, $\left[G = 6.67 \times 10^{−11}Nm^2Kg^{-2}\right]$
Work Done by Constant Force:
Work Done $W = \vec{F} \cdot \vec{S} = \left|\vec{F}\right| \left|\vec{S}\right| \cos \theta$,
Where, S = Displacement along a straight line,
F = applied force,
$\theta$ = Angle between S & F.
It is a scalar quantity and the Dimension of work is $\left[M^1 L^2 T^{-2}\right]$, SI unit of Work is the joule (J) and $1J = 1N \cdot m = Kgm^2s^{-2}$
Kinetic Friction:
$f_k = \mu_k \cdot N$
Maximum Static Friction (Limiting Friction): $f_{\text{max}} = \mu_s \cdot N$,
Where, N = Normal Force,
$\mu_k$ = Coefficient of Kinetic Friction,
$µ_s$ = Coefficient of Static Friction.
Simple Harmonic Motion:
Force $(F) = – k x$ and $k = \omega^2 m$
Where, k = Force Constant,
m = Mass of the Particle,
x = Displacement and $\omega^2$ = Positive Constant.
Torque:
The torque or vector moment or moment vector (M) of a force (F) about a point (P) is defined as:
$M = r \times F$
Where, r is the vector from the point P to any point A on the line of action L of F.
These are few of the key formulas for JEE Advanced 2025 Physics. To gain confidence and perform well in the exam, it is important to grasp their applications and practice various types of questions based on them.
Important Chemistry Formulas for JEE Advanced 2025
Chemistry is considered as a simple subject in comparison. Maximum marks can be obtained from this section with proper preparation. Let us look at some crucial list of formulas for JEE Advanced 2025.
Ideal Gas Law:
$PV = nRT$
Kinetic Energy of Gas Molecules:
$KE = \left(\dfrac{3}{2}\right)RT$
$T(K) = T^\circ C + 273.15$
Molarity:
$(M) = \dfrac{\text{No. of Moles of Solutes}}{\text{Volume of Solution in Liters}}$
Unit: $\text{mole}/{L}$
Molality:
$(m)= \dfrac{\text{No. of Moles of Solutes}}{\text{Mass of solvent in kg}}$
Molecular Mass $= 2 \times$ vapor density
Atomic number = No. of protons in the nucleus = No. of electrons in the nucleus
Mass number = No. of protons + No. of neutrons C $= v \lambda$
Boyle’s Law:
$P_1V_1 = P_2V_2$ (at constant T and n)
Charles’s Law:
$\dfrac{V_1}{T_1} = \dfrac{V_2}{T_2}$ (at constant P and n)
Avogadro's Law:
$\dfrac{V}{n}$ = constant, where V is the volume and n is the number of moles.
Dalton's Law of Partial Pressures:
$P(\text{total}) = P_1 + P_2 + P_3 + …$, where P(total) is the total pressure and $P_1, P_2, P_3$ etc. are the partial pressures of individual gases in the mixture.
Enthalpy:
$H = U + pV$
First Law of Thermodynamics:
$\Delta U = q + W$
Ohm’s Law:
$V = RI$
Faraday’s Laws:
Faraday’s First Law of Electrolysis:
$M = Zit$
Z = Atomic Mass / n $\times$ F
Faraday’s Second Law of Electrolysis:
$\dfrac{M_1}{M_2} = \dfrac{E_1}{E_2}$
Freundlich Adsorption Isotherm:
$\left[\dfrac{x}{m}\right] - Kp^{\left(\dfrac{1}{n}\right)}; n \geq 1$
Henry's Law:
$S = kH \times P$,
Where S is the solubility of a gas in a liquid, P is the partial pressure of the gas above the liquid, and kH is the Henry's law constant.
Nernst Equation:
$E = E^\circ - \left(\dfrac{RT}{nF}\right)lnQ$,
Where E is the cell potential, $E^\circ$ is the standard cell potential, R is the gas constant, T is the temperature, n is the number of electrons transferred, F is the Faraday constant, and Q is the reaction quotient.
Henderson-Hasselbalch Equation:
$pH = pKa + log\left(\dfrac{[A^{-}]}{[HA]}\right)$
Where pH is the negative logarithm of the hydrogen ion concentration, pKa is the acid dissociation constant, $[A^{-}]$ is the concentration of the conjugate base, and $[HA]$ is the concentration of the acid.
Beer-Lambert Law:
$A = \epsilon bc$
Where A is the absorbance, $\epsilon$ is the molar absorptivity, b is the path length, and c is the concentration.
Important Maths Formulas for JEE Advanced 2025
If you focus well in your board exams, you will breeze through your Mathematics course. Formulas are extremely important in the preparation of the mathematics portion. Below mentioned are a crucial list of formulas for JEE Advanced 2025.
Complex Number:
General form of Complex numbers: $x + i$, where ‘x’ is Real part and ‘i’ is an Imaginary part.
Sum of nth root of unity = zero
Product of nth root of unity $= (–1)n–1$
Cube roots of unity: $1, \omega, \omega^2$
$|z_1 + z_2| \leq |z_1|+|z_2|; |z_1 + z_2| \geq |z_1| - |z_2|; |z_1 - z_2| \geq |z_1| - |z_2|$
If three complex numbers $z_1, z_2, z_3$ are collinear then,
$\begin{vmatrix} z_1& \bar{z_1} & 1 \\ z_2 & \bar{z_2} & 1 \\ z_3 & \bar{z_3} & 1 \end{vmatrix} = 0$
If $\arg \cos\alpha = \arg \sin\alpha = 0, \arg \cos 2\alpha = \arg \sin 2\alpha = 0$,
$\arg \cos 2n\alpha = \arg \sin 2n\alpha = 0$
$\arg \cos 2\alpha = \arg \sin 2\alpha = \dfrac{3}{2}$
$\arg \cos 3\alpha = 3 \cos (\alpha + \beta + \gamma)$
$\arg \sin 3\alpha = 3\sin (\alpha + \beta + \gamma)$
$\arg \cos (2\alpha – \beta – \gamma) = 3$
$\arg \sin (2\alpha – \beta – \gamma) = 0$
$a^3 + b^3 + c^3 – 3abc = (a + b + c) (a + b\omega + c\omega^2) (a + b\omega^2 + c\omega)$
Quadratic Equation:
Standard form of Quadratic equation: $ax^2 + bx + c = 0$
General equation: $x = \dfrac{-b \pm \sqrt{(b^2 - 4ac)}}{2a}$
Sum of roots $= -\dfrac{b}{a}$
Product of roots discriminate $= b^2 – 4ac$
If $\alpha, \beta$ are roots then Quadratic equation is $x^2 – x(\alpha + \beta) + \alpha \beta = 0$
Number of terms in the expansion: $(x+a)^n$ is $n+1$
Any three non coplanar vectors are linearly independent
A system of vectors $\bar{a_1}, \bar{a_2},….\bar{a_n}$ are said to be linearly dependent, If there exist, $x_1\bar{a_1} + x_2\bar{a_2} + …. + x_na_n=0$ at least one of $x_i \neq 0$, where $i = 1, 2, 3….n$ and determinant $= 0$
a, b, c are coplanar then $\left[abc\right]=0$
If i, j, k are unit vectors then $\left[i j k\right] = 1$
If a, b, c are vectors then $\left[a+b, b+c, c+a\right] = 2\left[abc\right]$
$(1 + x)^{n – 1}$ is divisible by $x$ and $(1 + x)^n – nx –1$ is divisible by $x^2$
If ${}^{n}C_{r} - 1, {}^{n}C_{r}, {}^{n}C_{r}+1$ are in A.P, then $(n–2r)^2 = n + 2$
Trigonometric Identities:
$\sin^2(x) + \cos^2(x) = 1$
$1 + \tan^2(x) = \sec^2(x)$
$1 + \cot^2(x) = \text{cosec}^2(x)$
Limits:
Limit of a constant function: $\lim c = c$
Limit of a sum or difference: $\lim (f(x) \pm g(x)) = \lim f(x) \pm \lim g(x)$
Limit of a product: $\lim (f(x)g(x)) = \lim f(x) \times \lim g(x)$
Limit of a quotient: $\lim \left(\dfrac{f(x)}{g(x)}\right) = \dfrac{\lim f(x)}{\lim g(x)}$ if $\lim g(x) \neq 0$
Derivatives:
Power Rule: $\dfrac{d}{dx}(x^n) = nx^{(n-1)}$
Sum/difference Rule: $\dfrac{d}{dx}\left(f(x) \pm g(x)\right) = f'(x) \pm g'(x)$
Product Rule: $\dfrac{d}{dx}\left(f(x)g(x)\right) = f'(x)g(x) + f(x)g'(x)$
Quotient Rule: $\dfrac{d}{dx}\left(\dfrac{f(x)}{g(x)}\right) = \dfrac{\left[g(x)f'(x) - f(x)g'(x)\right]}{g^2(x)}$
Integration:
$\int{x^n }dx = \dfrac{x^{n+1}}{n+1} + c$ where $n \neq -1$
$\int \dfrac{1}{x} dx = \log_{e}\left | x \right | + c$
$\int e^x dx = e^x + c$
$\int a^x dx = \dfrac{a^{x}}{\log_{e}a} + c$
$\int \sin x dx = - \cos x + c$
$\int \cos x dx = \sin x + c$
$\int \sec^2x dx = \tan x + c$
$\int \text{cosec}^2x dx = - \cot x + c$
$\int \sec x tan x dx = \sec x + c$
$\int \text{cosec }x \cot x dx = – \text{cosec }x + c$
$\int \cot x dx = \log |\sin x|+c$
$\int \tan x dx = -\log ∣\cos x∣ + c$
$\int \sec x dx = log ∣\sec x + \tan x∣ + c$
$\int \text{cosec }x dx = log ∣\text{cosec }x – \cot x∣ + c$
$\int \dfrac{1}{\sqrt{a^{2} - x^{2}}} dx = \sin^{-1} \left(\dfrac{x}{a}\right) + c$
$\int - \dfrac{1}{\sqrt{a^{2} - x^{2}}} dx = \cos^{-1} \left(\dfrac{x}{a}\right) + c$
$\int \dfrac{1}{{a^{2} + x^{2}}} dx = \dfrac{1}{a} \tan^{-1} \left(\dfrac{x}{a}\right) + c$
$\int - \dfrac{1}{{a^{2} + x^{2}}} dx = \dfrac{1}{a} \cot^{-1} \left(\dfrac{x}{a}\right) + c$
$\int \dfrac{1}{x\sqrt{x^{2} - a^{2}}} dx = \dfrac{1}{a} \sec^{-1} \left(\dfrac{x}{a}\right) + c$
$\int - \dfrac{1}{x\sqrt{x^{2} - a^{2}}} dx = \dfrac{1}{a} \text{cosec}^{-1} \left(\dfrac{x}{a}\right) + c$
How to Remember Formulas for JEE?
Solve problems that require the use of formulas. The more you use each formula in a test, the better you'll remember it.
Revise the formulas on a daily basis. It will help you in remembering them permanently.
Each formula that is difficult to remember on a sticky note. Paste them in locations where you will see them frequently, such as your study desk, laptop screen (desktop), textbooks, and so on.
In Chemistry, use symbols and flashcards to help you remember chemical reactions and formulas.
On a single page, write out all of the formulas for a chapter. Read it on your way to class, between courses, at school, or before going to bed.
Always try to memorise the formula in a calm environment. So that it can be easily remembered.
Conclusion
To solve problems efficiently, it is important to memorise and understand these formulas and their applications. Practicing different types of questions and problems based on these formulas will also help you acquire confidence and perform well on the JEE Advanced Exam. You can also download important formulas for JEE Advanced pdf and a separate list of all trigonometry formulas for JEE Advanced pdf are available on our Vedantu website, along with maths formulas for JEE advanced pdf.
FAQs on JEE Advanced Important Formulas 2025
1. How do I remember all the important formulas for JEE Advanced 2025?
Practice is the best way to remember formulas. Use the formulas to solve as many questions as possible, and make sure you revise them on a regular basis.
2. Are all these formulas important for JEE Advanced 2025?
While all of the above mentioned formulas are important, it is just as important to understand the underlying concept and their applications. Also engage in Vedantu JEE coaching sessions online on youtube, also courses are available which will also be beneficial.
3. Is it possible to pass JEE Advanced 2025 without memorising any formulas?
While memorising formulas is not the only factor that affects performance on JEE Advanced 2025, it is important to understand formulas and their applications.
4. Can I derive the formulas during the exam?
Yes, you can derive the formulas during the exam, but it can be time-consuming, and it's always better to memorize as many formulas as possible.
5. Suggest the easiest way to remember all the JEE Advanced important formulas?
Have you forgotten the letters a, b, c, d, or 1,2,3,4? Certainly not. Why? Because you revised and wrote them so many times as a child that you don't forget them. So, for remembering formulas, a basic method is "Revision and Practice."