
A low-loss transformer has 230V applied to the primary and gives 4.6V in the secondary. The secondary is connected to a load, which draws 50A of current. The current (in ampere) in the primary is:
A) 0.1
B) 1.0
C) 10
D) 250
Answer
232.8k+ views
Hint: An electric current is defined as the net flow rate of the electric charge. The unit of current is Ampere. It is a stream of charged particles like ions or electrons that are moving through an electrical conductor.
Complete step by step solution:
Given data:
The primary voltage in the transformer, ${V_1} = 230V$
The secondary voltage in the transformer, ${V_2} = 4.6V$
The secondary current, ${I_2} = 50A$
The primary current, ${I_1} = ?$
We know that power must be the same in the primary and the secondary transformers.
Also, power is given by the formula, $P = VI$
$ \Rightarrow {V_1}{I_1} = {V_2}{I_2}$
Substituting the values, we get
$ \Rightarrow 230 \times {I_1} = 4.6 \times 50$
$ \Rightarrow {I_1} = \dfrac{{4.6 \times 50}}{{230}} = 1A$
Thus the primary current, ${I_1} = 1A$
Hence the correct option is B.
Additional Information:
1. The voltage that is applied to the terminals of the primary winding is called a primary voltage transformer. In general, it is the side that takes the power and the side that delivers the power is the secondary.
2. In the case of a single-phase voltage transformer, the side with the higher voltage is considered as the primary.
Note: 1. An electrical device that transfers the electrical energy from one electrical circuit to another electrical circuit is called a transformer.
2. There are two types of current, Direct current and Alternating current. The electrons will flow in one direction with the direct current and the electrons will flow in both the direction with the alternating current.
3. Power is defined as the amount of energy transferred per unit of time. It is a scalar quantity. The unit of power is the watt. Power depends on the amount of work done and the time taken.
Complete step by step solution:
Given data:
The primary voltage in the transformer, ${V_1} = 230V$
The secondary voltage in the transformer, ${V_2} = 4.6V$
The secondary current, ${I_2} = 50A$
The primary current, ${I_1} = ?$
We know that power must be the same in the primary and the secondary transformers.
Also, power is given by the formula, $P = VI$
$ \Rightarrow {V_1}{I_1} = {V_2}{I_2}$
Substituting the values, we get
$ \Rightarrow 230 \times {I_1} = 4.6 \times 50$
$ \Rightarrow {I_1} = \dfrac{{4.6 \times 50}}{{230}} = 1A$
Thus the primary current, ${I_1} = 1A$
Hence the correct option is B.
Additional Information:
1. The voltage that is applied to the terminals of the primary winding is called a primary voltage transformer. In general, it is the side that takes the power and the side that delivers the power is the secondary.
2. In the case of a single-phase voltage transformer, the side with the higher voltage is considered as the primary.
Note: 1. An electrical device that transfers the electrical energy from one electrical circuit to another electrical circuit is called a transformer.
2. There are two types of current, Direct current and Alternating current. The electrons will flow in one direction with the direct current and the electrons will flow in both the direction with the alternating current.
3. Power is defined as the amount of energy transferred per unit of time. It is a scalar quantity. The unit of power is the watt. Power depends on the amount of work done and the time taken.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

