
What are the raw materials used in Solvay's process?
(A) \[NaCl,N{H_3},CaC{O_3}\]
(B) \[{\text{NaOH,C}}{{\text{O}}_{\text{2}}}\]
(C) \[NaCl,CuC{O_3},C,{H_2}S{O_4}\]
(D) \[N{H_3},{H_2}O,NaCl\]
Answer
133.8k+ views
Hint: To solve this question we must know about Solvay’s process. Solvay’s process is industrially used to manufacture sodium carbonate. The major ingredients or reactants used in this process are salt brine and limestone.
Complete step by step solution:
In Solvay’s process, first carbon dioxide and ammonia gas is passed over a cold and saturated solution of sodium chloride. This leads to the formation of sodium hydrogen carbonate that is soluble in sodium ions and is precipitated that can be removed by filtration. Sodium chloride is then reacted with sodium hydrogen carbonate to give sodium bicarbonate with on heating gives sodium carbonate.
Step 1: Ammonia, water and carbon dioxide react to form ammonium carbonate, which on further reaction with water and carbon dioxide forms ammonium bicarbonate.
\[
2N{H_3} + {H_2}O + C{O_2}\xrightarrow{{}}{(N{H_4})_2}C{O_3} \\
{(N{H_4})_2}C{O_3} + {H_2}O + C{O_2}\xrightarrow{{}}2N{H_4}HC{O_3} \\
\]
Step 2: Ammonium bicarbonate is then added to sodium chloride, which results in the formation of ammonium chloride and sodium bicarbonate.
\[N{H_4}HC{O_3} + NaCl\xrightarrow{{}}N{H_4}Cl + NaHC{O_3}\]
Step 3: Sodium bicarbonate on further heating results in the formation of sodium carbonate and carbon dioxide gas is evolved which can be reused in the process again
\[2NaHC{O_3}\xrightarrow{{}}N{a_2}C{O_3} + {H_2}O + C{O_2}\]
So the raw materials used in this process are sodium chloride, ammonia and limestone.
Hence the correct option is (A).
Note: Sodium carbonate can also be prepared from trona ore. Trona ore has a formula of \[N{a_2}C{O_3}.NaHC{O_3}.2{H_2}O\]. That on heating results in the formation of sodium carbonate.\[2N{a_2}C{O_3}.NaHC{O_3}.2{H_2}O\xrightarrow{{}}3N{a_2}C{O_3} + 5{H_2}O + C{O_2}\]. The structure of this Trona Ore consists of units of 3 edge-sharing sodium polyhedral (a central octahedron flanked by septahedra), cross-linked by carbonate groups and hydrogen bonds.
Complete step by step solution:
In Solvay’s process, first carbon dioxide and ammonia gas is passed over a cold and saturated solution of sodium chloride. This leads to the formation of sodium hydrogen carbonate that is soluble in sodium ions and is precipitated that can be removed by filtration. Sodium chloride is then reacted with sodium hydrogen carbonate to give sodium bicarbonate with on heating gives sodium carbonate.
Step 1: Ammonia, water and carbon dioxide react to form ammonium carbonate, which on further reaction with water and carbon dioxide forms ammonium bicarbonate.
\[
2N{H_3} + {H_2}O + C{O_2}\xrightarrow{{}}{(N{H_4})_2}C{O_3} \\
{(N{H_4})_2}C{O_3} + {H_2}O + C{O_2}\xrightarrow{{}}2N{H_4}HC{O_3} \\
\]
Step 2: Ammonium bicarbonate is then added to sodium chloride, which results in the formation of ammonium chloride and sodium bicarbonate.
\[N{H_4}HC{O_3} + NaCl\xrightarrow{{}}N{H_4}Cl + NaHC{O_3}\]
Step 3: Sodium bicarbonate on further heating results in the formation of sodium carbonate and carbon dioxide gas is evolved which can be reused in the process again
\[2NaHC{O_3}\xrightarrow{{}}N{a_2}C{O_3} + {H_2}O + C{O_2}\]
So the raw materials used in this process are sodium chloride, ammonia and limestone.
Hence the correct option is (A).
Note: Sodium carbonate can also be prepared from trona ore. Trona ore has a formula of \[N{a_2}C{O_3}.NaHC{O_3}.2{H_2}O\]. That on heating results in the formation of sodium carbonate.\[2N{a_2}C{O_3}.NaHC{O_3}.2{H_2}O\xrightarrow{{}}3N{a_2}C{O_3} + 5{H_2}O + C{O_2}\]. The structure of this Trona Ore consists of units of 3 edge-sharing sodium polyhedral (a central octahedron flanked by septahedra), cross-linked by carbonate groups and hydrogen bonds.
Recently Updated Pages
JEE Main 2025 Session 2 Form Correction (Closed) – What Can Be Edited

Sign up for JEE Main 2025 Live Classes - Vedantu

JEE Main Books 2023-24: Best JEE Main Books for Physics, Chemistry and Maths

JEE Main 2023 April 13 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 11 Shift 2 Question Paper with Answer Key

JEE Main 2023 April 10 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Current Loop as Magnetic Dipole and Its Derivation for JEE

Inertial and Non-Inertial Frame of Reference - JEE Important Topic

Other Pages
NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics

Hydrocarbons Class 11 Notes: CBSE Chemistry Chapter 9

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

Thermodynamics Class 11 Notes: CBSE Chapter 5
