Answer
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Hint: We will use the formula for critical angle, i.e., $\sin C = \dfrac{1}{{{\mu _1}}} = \dfrac{{{\mu _2}}}{{{\mu _1}}}$. refractive index of the first medium with respect to the second medium; \[{\mu _1} = \] refractive index of denser medium and \[{\mu _2} = \] refractive index of rarer medium.
Complete step by step answer:
We know the formula for finding the critical angle is $\sin C = \dfrac{1}{{{\mu _1}}} = \dfrac{{{\mu _2}}}{{{\mu _1}}}$ …………………. (i)
The value of the refractive index of the liquid w.r.t the prism is given as \[\sqrt 2 \].
\[\sin C = \dfrac{1}{{\sqrt 2 }}\] (on substituting the value of \[_2{\mu _1}\] in Eq., (i)
\[ \Rightarrow C = {\sin ^{ - 1}}\left( {\dfrac{1}{{\sqrt 2 }}} \right)\]
\[ \Rightarrow C = 45^\circ \]
This means that both assertion and reason are true and the reason is the correct explanation for assertion.
Hence, option (a.) is the correct answer.
Note: The assertion and reason both hold true only for the given values of refractive index and critical angle. So, we will always have to calculate and check the answer.
Complete step by step answer:
We know the formula for finding the critical angle is $\sin C = \dfrac{1}{{{\mu _1}}} = \dfrac{{{\mu _2}}}{{{\mu _1}}}$ …………………. (i)
The value of the refractive index of the liquid w.r.t the prism is given as \[\sqrt 2 \].
\[\sin C = \dfrac{1}{{\sqrt 2 }}\] (on substituting the value of \[_2{\mu _1}\] in Eq., (i)
\[ \Rightarrow C = {\sin ^{ - 1}}\left( {\dfrac{1}{{\sqrt 2 }}} \right)\]
\[ \Rightarrow C = 45^\circ \]
This means that both assertion and reason are true and the reason is the correct explanation for assertion.
Hence, option (a.) is the correct answer.
Note: The assertion and reason both hold true only for the given values of refractive index and critical angle. So, we will always have to calculate and check the answer.
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