Assertion: The volume of 1 mole of an ideal gas at 1 bar pressure at $\text{25}{}^\circ \text{C}$ is 24.78 litre.
Reason: 1 bar = 0.987 atm.
(A) Both Assertion and Reason are correct and Reason is the correct explanation for Assertion.
(B) Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion.
(C) Assertion is correct but Reason is incorrect.
(D) Both Assertion and Reason are incorrect.
Answer
Verified
116.4k+ views
Hint: Pressure and volume are always directly proportional to the gas constant as well as to the temperature. A bar is a unit of pressure and it differs for different units such as atm, kPa, Ba, etc. and has a fixed value for each unit.
Complete step by step answer:
-To find out the correct answer we will calculate the given parameters of Assertion by the formula Ideal Gas Formula.
-The formula of Ideal Gas is PV = nRT, the value of pressure, no. of moles, Gas constant and temperature is given in the question.
-So, by putting all the values in the formula we will get,
$\begin{align}
& V\text{= }\dfrac{nRT}{P} \\
& V\text{= }\dfrac{\text{1 }\cdot \text{ 0}\text{.0821 }\cdot \text{ 298}}{0.987} \\
& V=\text{ 24}\text{.78 litre } \\
\end{align}$
-So, the given value of volume in the question is correct, that is 24.78 litre.
-Also, we know that the value of 1 bar is 0.987 atm but it is not the explanation of the assertion.
-The given reason is just a part of a solution and not the explanation.
Therefore, option (B) is correct that is both assertion and reason are correct but the reason is not the correct explanation for the assertion.
Note: The value of 1 bar is 0.987 in standard atmosphere, 100000 Pascal and 750 Torr. The value of temperature is always taken in the Kelvin. One should do all the calculations twice to get the correct result.
Complete step by step answer:
-To find out the correct answer we will calculate the given parameters of Assertion by the formula Ideal Gas Formula.
-The formula of Ideal Gas is PV = nRT, the value of pressure, no. of moles, Gas constant and temperature is given in the question.
-So, by putting all the values in the formula we will get,
$\begin{align}
& V\text{= }\dfrac{nRT}{P} \\
& V\text{= }\dfrac{\text{1 }\cdot \text{ 0}\text{.0821 }\cdot \text{ 298}}{0.987} \\
& V=\text{ 24}\text{.78 litre } \\
\end{align}$
-So, the given value of volume in the question is correct, that is 24.78 litre.
-Also, we know that the value of 1 bar is 0.987 atm but it is not the explanation of the assertion.
-The given reason is just a part of a solution and not the explanation.
Therefore, option (B) is correct that is both assertion and reason are correct but the reason is not the correct explanation for the assertion.
Note: The value of 1 bar is 0.987 in standard atmosphere, 100000 Pascal and 750 Torr. The value of temperature is always taken in the Kelvin. One should do all the calculations twice to get the correct result.
Recently Updated Pages
How to find Oxidation Number - Important Concepts for JEE
How Electromagnetic Waves are Formed - Important Concepts for JEE
Electrical Resistance - Important Concepts and Tips for JEE
Average Atomic Mass - Important Concepts and Tips for JEE
Chemical Equation - Important Concepts and Tips for JEE
Concept of CP and CV of Gas - Important Concepts and Tips for JEE
Trending doubts
JEE Main 2025: Application Form (Out), Exam Dates (Released), Eligibility & More
JEE Main Chemistry Question Paper with Answer Keys and Solutions
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main Login 2045: Step-by-Step Instructions and Details
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
Physics Average Value and RMS Value JEE Main 2025
Other Pages
NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction
NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics
NCERT Solutions for Class 11 Chemistry Chapter 8 Organic Chemistry
NCERT Solutions for Class 11 Chemistry Chapter 6 Equilibrium
NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons
Equilibrium Class 11 Notes: CBSE Chemistry Chapter 6