
The C-C bond length of the following molecules is in the order:
\[
{\text{(A)}}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}{\text{ > }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ > }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ > }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}} \\
{\text{(B)}}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}} \\
{\text{(C) }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}} \\
{\text{(D) }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}} \\
\]
Answer
216k+ views
Hint: The carbon-carbon bond lengths are dependent upon the type of bonds namely single bond, double bond, or triple bond. The single bond has more bond length compared to double bond which in turn is more than triple bond.
Complete step by step answer:
Bond lengths decrease with increase in s-character. In other words, multiple bonds have a shorter bond length as compared to a single bond.
In the case of single bond only sigma bonds are present whereas in double bond a sigma and a pi bond are present. Sigma bonds are weaker bonds but have high bond length compared to a pi bond. In triple bonds there are two pi bonds which makes it a shorter bond.
A typical carbon-carbon single bond has a length of 154 pm, while a typical double bond and triple bonds are 134 pm and 120 pm, respectively.

We can see that
Ethane has a single bond between carbon and carbon.
In benzene, the carbon-carbon bond lengths are in resonance due to its aromatic nature, so they have bond length between single bond and double bond as it exhibits partial double bond character.
In ethene, there is a double bond between carbon and carbon.
In ethyne, there is a triple bond between carbon and carbon.
Thus, Single bond > Partial double bond > Double bond > Triple bond.
Therefore, we get the correct following order:
\[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}\]
So, the correct option is B.
Note: Partial double bond character is exhibited by molecules having resonance structures where both single bonds and double bonds are exhibited by the molecule. These molecules have bond lengths more than single bonds but less than double bonds.
Complete step by step answer:
Bond lengths decrease with increase in s-character. In other words, multiple bonds have a shorter bond length as compared to a single bond.
In the case of single bond only sigma bonds are present whereas in double bond a sigma and a pi bond are present. Sigma bonds are weaker bonds but have high bond length compared to a pi bond. In triple bonds there are two pi bonds which makes it a shorter bond.
A typical carbon-carbon single bond has a length of 154 pm, while a typical double bond and triple bonds are 134 pm and 120 pm, respectively.

We can see that
Ethane has a single bond between carbon and carbon.
In benzene, the carbon-carbon bond lengths are in resonance due to its aromatic nature, so they have bond length between single bond and double bond as it exhibits partial double bond character.
In ethene, there is a double bond between carbon and carbon.
In ethyne, there is a triple bond between carbon and carbon.
Thus, Single bond > Partial double bond > Double bond > Triple bond.
Therefore, we get the correct following order:
\[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}\]
So, the correct option is B.
Note: Partial double bond character is exhibited by molecules having resonance structures where both single bonds and double bonds are exhibited by the molecule. These molecules have bond lengths more than single bonds but less than double bonds.
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

