Answer
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Hint: According, Kirchhoff’s voltage law (KVL), the algebraic sum of voltages across each element is zero. Kirchhoff’s voltage law is used to calculate the value of potential difference across the cell. From KVL, We get the value of current flowing through the circuit. Then we calculate potential difference across B by substituting the value of current in the KVL equation.
Formula used:
We apply Kirchhoff’s voltage law (KVL) in circuit. Then we calculate potential differences across B.
Complete step by step solution:
Given: Resistances are \[0.1\Omega \], \[0.3\Omega \] and \[0.2\Omega \]. Voltages are \[2V\] each.
Let us suppose that the current flowing through the circuit is I.
On applying: Kirchhoff’s voltage law (KVL) in given circuit , we get following equation
\[ - (0.2)I - (0.3)I + 2V - (0.1)I + 2V = 0\]
\[ \Rightarrow 0.6I = 4\]
\[ \Rightarrow I = \dfrac{4}{{0.6}} = \dfrac{{40}}{6}A\]
\[\therefore I = \dfrac{{20}}{3}A\]
Hence, current flows through the circuit, \[I = \dfrac{{20}}{3}A\]
Now, potential difference across B is calculated by
\[{V_1} - (0.3)\dfrac{{20}}{3} + 2V = {V_2}\]
\[ \Rightarrow {V_1} - 2V + 2V = {V_2}\]
\[ \Rightarrow {V_1} = {V_2}\]
\[\therefore\] Potential difference across \[B = {V_1} - {V_2} = 0\]
Hence, Potential difference across B is zero.
Therefore, the correct option is (D).
Additional information: Kirchhoff’s voltage law (KVL) is also known as the second rule of Kirchhoff’s. According to this rule, the algebraic sum of voltages in a closed circuit is zero. Kirchhoff’s voltage law is applicable for both AC and DC circuits. Voltage across passive elements in a closed circuit is always equivalent. The value of voltage is reverse to source voltage.
To measure the unknown standards such as current (I), Voltage (V) we use, Kirchhoff's laws are used, KVL is also used to find the direction of moving current in the circuit. This rule is very useful to solve complicated circuitries. To observe the transferal of power in the circuit, we use KVL in circuits.
Note: Students be careful to apply Kirchhoff’s voltage law (KVL) in circuit. Direction of current is mandatory to apply Kirchhoff’s voltage law.
Formula used:
We apply Kirchhoff’s voltage law (KVL) in circuit. Then we calculate potential differences across B.
Complete step by step solution:
Given: Resistances are \[0.1\Omega \], \[0.3\Omega \] and \[0.2\Omega \]. Voltages are \[2V\] each.
Let us suppose that the current flowing through the circuit is I.
On applying: Kirchhoff’s voltage law (KVL) in given circuit , we get following equation
\[ - (0.2)I - (0.3)I + 2V - (0.1)I + 2V = 0\]
\[ \Rightarrow 0.6I = 4\]
\[ \Rightarrow I = \dfrac{4}{{0.6}} = \dfrac{{40}}{6}A\]
\[\therefore I = \dfrac{{20}}{3}A\]
Hence, current flows through the circuit, \[I = \dfrac{{20}}{3}A\]
Now, potential difference across B is calculated by
\[{V_1} - (0.3)\dfrac{{20}}{3} + 2V = {V_2}\]
\[ \Rightarrow {V_1} - 2V + 2V = {V_2}\]
\[ \Rightarrow {V_1} = {V_2}\]
\[\therefore\] Potential difference across \[B = {V_1} - {V_2} = 0\]
Hence, Potential difference across B is zero.
Therefore, the correct option is (D).
Additional information: Kirchhoff’s voltage law (KVL) is also known as the second rule of Kirchhoff’s. According to this rule, the algebraic sum of voltages in a closed circuit is zero. Kirchhoff’s voltage law is applicable for both AC and DC circuits. Voltage across passive elements in a closed circuit is always equivalent. The value of voltage is reverse to source voltage.
To measure the unknown standards such as current (I), Voltage (V) we use, Kirchhoff's laws are used, KVL is also used to find the direction of moving current in the circuit. This rule is very useful to solve complicated circuitries. To observe the transferal of power in the circuit, we use KVL in circuits.
Note: Students be careful to apply Kirchhoff’s voltage law (KVL) in circuit. Direction of current is mandatory to apply Kirchhoff’s voltage law.
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