Answer
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Hint: We will find the no. of favourable cases in each case and divide it by the total number of outcomes which is 12. We will use the definition that an even number is divisible by 2 and then all the multiples of it until 12 will be the favourable outcomes for part d, like that we will find the probability.
Complete step-by-step answer:
This is the required figure in which OP is the spinning arrow.
10 is only one number from 1 to 12.
Hence, the number of favourable cases is 1 and the total number of cases is 12.
Therefore,
$\begin{align}
& P=\dfrac{\text{number of favourable case}}{\text{total number of case}} \\
& =\dfrac{1}{12} \\
\end{align}$
Hence, the answer is $\dfrac{1}{12}$
Let’s solve part (b),
The odd numbers from 1 to 12 are: 1, 3, 5, 7, 9, 11.
Hence, the number of favourable cases is 6 and total number of cases is 12.
Therefore,
$\begin{align}
& P=\dfrac{\text{number of favourable case}}{\text{total number of case}} \\
& =\dfrac{6}{12} \\
& =\dfrac{1}{2} \\
\end{align}$
Hence, the answer is $\dfrac{1}{2}$
Let’s solve part (c),
The numbers which are multiple of 3 from 1 to 12 are: 3, 6, 9, 12.
Hence, the number of favourable cases is 4 and total number of cases is 12.
Therefore,
$\begin{align}
& P=\dfrac{\text{number of favourable case}}{\text{total number of case}} \\
& =\dfrac{4}{12} \\
& =\dfrac{1}{3} \\
\end{align}$
Hence, the answer is $\dfrac{1}{3}$
Let’s solve part (d),
The even numbers from 1 to 12 are: 2, 4, 6, 8, 10, 12.
Hence, the number of favourable cases is 6 and total number of cases is 12.
Therefore,
$\begin{align}
& P=\dfrac{\text{number of favourable case}}{\text{total number of case}} \\
& =\dfrac{6}{12} \\
& =\dfrac{1}{2} \\
\end{align}$
Hence, the answer is $\dfrac{1}{2}$
Note: The formula $P=\dfrac{\text{number of favourable case}}{\text{total number of case}}$ for finding probability can be used in any case. One should know the meaning of even and odd numbers to solve this question correctly. An even number is divisible by 2 and an odd number is not.
Complete step-by-step answer:
This is the required figure in which OP is the spinning arrow.
10 is only one number from 1 to 12.
Hence, the number of favourable cases is 1 and the total number of cases is 12.
Therefore,
$\begin{align}
& P=\dfrac{\text{number of favourable case}}{\text{total number of case}} \\
& =\dfrac{1}{12} \\
\end{align}$
Hence, the answer is $\dfrac{1}{12}$
Let’s solve part (b),
The odd numbers from 1 to 12 are: 1, 3, 5, 7, 9, 11.
Hence, the number of favourable cases is 6 and total number of cases is 12.
Therefore,
$\begin{align}
& P=\dfrac{\text{number of favourable case}}{\text{total number of case}} \\
& =\dfrac{6}{12} \\
& =\dfrac{1}{2} \\
\end{align}$
Hence, the answer is $\dfrac{1}{2}$
Let’s solve part (c),
The numbers which are multiple of 3 from 1 to 12 are: 3, 6, 9, 12.
Hence, the number of favourable cases is 4 and total number of cases is 12.
Therefore,
$\begin{align}
& P=\dfrac{\text{number of favourable case}}{\text{total number of case}} \\
& =\dfrac{4}{12} \\
& =\dfrac{1}{3} \\
\end{align}$
Hence, the answer is $\dfrac{1}{3}$
Let’s solve part (d),
The even numbers from 1 to 12 are: 2, 4, 6, 8, 10, 12.
Hence, the number of favourable cases is 6 and total number of cases is 12.
Therefore,
$\begin{align}
& P=\dfrac{\text{number of favourable case}}{\text{total number of case}} \\
& =\dfrac{6}{12} \\
& =\dfrac{1}{2} \\
\end{align}$
Hence, the answer is $\dfrac{1}{2}$
Note: The formula $P=\dfrac{\text{number of favourable case}}{\text{total number of case}}$ for finding probability can be used in any case. One should know the meaning of even and odd numbers to solve this question correctly. An even number is divisible by 2 and an odd number is not.
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