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A heap of wheat is in the form of a cone whose diameter is 10.5m and the height is 3m.Find its volume. The heap is to be covered by canvas to protect it from rain. Find the area of canvas required.

Answer
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Hint- The heap is enclosed as a conic section which is cone in this case. Volume of heap can easily be calculated using the direct formula of volume of cone. The area of the canvas required to protect the heap will be the curved surface area of the cone.
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The diameter of the cone, D=10.5m thus
Radius of cone, r = D2=10.52=5.25m
Height of cone, H = 3m
The volume of cones is given as 13πr2H…………………………. (1)
Putting the values in equation (1)
Volume = 13π×5.252×3
Volume = (13×227×82.68)
Volume = 86.625 m3
Now the heap is covered by a canvas to protect it from rain, thus the area of the canvas that we will be using for the conic section (cone) will be the curved surface area of that conic section.
Curved surface area of the cone is πrl where r is radius and l is the slant height……………. (2)
Now slant height can be calculated using Pythagoras theorem which is hypotenus2=perpendicular2+base2
In triangle ABC
AC2=AB2+BC2…………………… (3)
Now AC = l (slant height), BC= r (radius of base), AB = h (height)
So using the above figure l2=h2+r2

Putting the values we get
l2=32+(5.25)2
Hence l2=9+27.5625=36.5625
Hence l=6.0467 m
Now using equation (2)
Curved surface area = πrl
Curved surface area = 227×5.25×6.0467
On solving curved surface area = 99.77 m2

Note – Whenever we face such problems the key concept that we need to recall that whenever being asked about the area associated with a cone, then always we have to find the curved surface area. Another note point is the height, radius of base and the slant height of a cone forms a right angle triangle.