Answer
Verified
430.5k+ views
Hint: We need to find the work function. This can be done from Einstein’s equation which is given by $K{E_{\max }} = \dfrac{{hc}}{\lambda } - \phi $. This is a concept of modern physics.
Formula used: By Planck- Einstein relation:
$K{E_{\max }} = \dfrac{{hc}}{\lambda } - \phi $
Here,
$K{E_{\max }}$ is the maximum kinetic energy
$h$ is the Planck’s constant
$c$is the speed of light
$\phi $ is the work function
$\lambda $ is the wavelength
Complete step by step answer:
We already know from the above formula,
We just need to put the values:
For the situation when wavelength is $\lambda $,
$K{E_{\max }} = \dfrac{{hc}}{\lambda } - \phi $
And for the second case when wavelength is half the initial,
$K{E_{\max 2}} = \dfrac{{2hc}}{\lambda } - \phi $
But as given in the question:
$K{E_{\max 2}} = 3K{E_{\max 1}}$
So, \[\dfrac{{2hc}}{\lambda } - \phi = 3\left( {\dfrac{{hc}}{\lambda } - \phi } \right)\]
On solving further,
\[3\phi - \phi = \dfrac{{3hc}}{\lambda } - \dfrac{{2hc}}{\lambda }\]
\[\phi = \dfrac{{hc}}{{2\lambda }}\]
Hence, we obtain the work function to be $\dfrac{{hc}}{{2\lambda }}$.
We need to select the correct option.
The correct option is B.
Additional Note: Photon energy is the energy carried by a single photon. The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency the higher is its energy.
Note: It should be kept in mind that Einstein's photo-electric equation is important. Photon energy is the energy carried by a single photon. The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. This equation is known as the Planck-Einstein relation.
Since light is bundled up into photons, Einstein theorized that when a photon falls on the surface of a metal, the entire photon’s energy is transferred to the electron.
A part of this energy is used to remove the electron from the metal atom’s grasp and the rest is given to the ejected electron as kinetic energy. Electrons emitted from underneath the metal surface lose some kinetic energy during the collision. But the surface electrons carry all the kinetic energy imparted by the photon and have the maximum kinetic energy.
Formula used: By Planck- Einstein relation:
$K{E_{\max }} = \dfrac{{hc}}{\lambda } - \phi $
Here,
$K{E_{\max }}$ is the maximum kinetic energy
$h$ is the Planck’s constant
$c$is the speed of light
$\phi $ is the work function
$\lambda $ is the wavelength
Complete step by step answer:
We already know from the above formula,
We just need to put the values:
For the situation when wavelength is $\lambda $,
$K{E_{\max }} = \dfrac{{hc}}{\lambda } - \phi $
And for the second case when wavelength is half the initial,
$K{E_{\max 2}} = \dfrac{{2hc}}{\lambda } - \phi $
But as given in the question:
$K{E_{\max 2}} = 3K{E_{\max 1}}$
So, \[\dfrac{{2hc}}{\lambda } - \phi = 3\left( {\dfrac{{hc}}{\lambda } - \phi } \right)\]
On solving further,
\[3\phi - \phi = \dfrac{{3hc}}{\lambda } - \dfrac{{2hc}}{\lambda }\]
\[\phi = \dfrac{{hc}}{{2\lambda }}\]
Hence, we obtain the work function to be $\dfrac{{hc}}{{2\lambda }}$.
We need to select the correct option.
The correct option is B.
Additional Note: Photon energy is the energy carried by a single photon. The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency the higher is its energy.
Note: It should be kept in mind that Einstein's photo-electric equation is important. Photon energy is the energy carried by a single photon. The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. This equation is known as the Planck-Einstein relation.
Since light is bundled up into photons, Einstein theorized that when a photon falls on the surface of a metal, the entire photon’s energy is transferred to the electron.
A part of this energy is used to remove the electron from the metal atom’s grasp and the rest is given to the ejected electron as kinetic energy. Electrons emitted from underneath the metal surface lose some kinetic energy during the collision. But the surface electrons carry all the kinetic energy imparted by the photon and have the maximum kinetic energy.
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Which are the Top 10 Largest Countries of the World?
Which is the longest day and shortest night in the class 11 sst CBSE
What is the definite integral of zero a constant b class 12 maths CBSE
Name five important trees found in the tropical evergreen class 10 social studies CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Students Also Read