Answer
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Hint: When a body moves in a circular motion it has two types of velocity one is linear velocity while the other is angular velocity. Here the body is moving with constant speed, the magnitude of the speed Also, there are two types of acceleration, one is linear while the other is angular.
Complete step by step answer:
We know centripetal acceleration is given by \[\dfrac{{{v}^{2}}}{r}\], where v is the linear velocity and r is the radius of the circular path.
Now, the acceleration becomes 5 times,
\[\Rightarrow \dfrac{5{{v}^{2}}}{r}\]
\[\therefore \]the new radius is one fifth of the initial one. But, if \[r=r'\]
The new speed is therefore, \[\sqrt{5}\sim2.23\]times the initial one.
So, the correct answer is “Option C”.
Note:
The force which pulls the body towards the centre is centripetal force and the acceleration is called centripetal acceleration. Since, the acceleration increased, either the speed gets increased or the radius gets decreased. There is no role of mass when it comes to speed and acceleration. The equation shows acceleration is independent of the mass.
Complete step by step answer:
We know centripetal acceleration is given by \[\dfrac{{{v}^{2}}}{r}\], where v is the linear velocity and r is the radius of the circular path.
Now, the acceleration becomes 5 times,
\[\Rightarrow \dfrac{5{{v}^{2}}}{r}\]
\[\therefore \]the new radius is one fifth of the initial one. But, if \[r=r'\]
The new speed is therefore, \[\sqrt{5}\sim2.23\]times the initial one.
So, the correct answer is “Option C”.
Note:
The force which pulls the body towards the centre is centripetal force and the acceleration is called centripetal acceleration. Since, the acceleration increased, either the speed gets increased or the radius gets decreased. There is no role of mass when it comes to speed and acceleration. The equation shows acceleration is independent of the mass.
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