Answer
Verified
454.8k+ views
- Hint: First we will learn about Newton's third law. It states that for every action in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.
Complete step-by-step solution -
In the question it is given that the particle is stationary initially. Momentum of a particle is defined as the mass of the particle times its velocity. The particle’s initial velocity is 0. Hence, momentum will be zero. The explosion of the particle follows conservation of linear momentum principle. This states that, since no external force is acting on the particle, the momentum of the particle remains constant.
This means, after explosion, the total momentum is zero. The total momentum after explosion is given by,
$m_{1}{{v}_{1}}=m_{2}{{v}_{2}}$ . Here, the negative symbol is because the masses travel in opposite directions after the explosion. From, conservation of momentum, we can conclude that,
\[\begin{align}
& m _{1}{{v}_{1}}=m_{2}{{v}_{2}} \\
& \dfrac{{{m}_{1}}}{{{m}_{2}}}=\dfrac{{{v}_{2}}}{{{v}_{1}}}
\end{align}\] … (1)
The kinetic energy of a particle is defined by the energy that a particle contains due to its motion. The kinetic energy of a particle with mass m and velocity v is given by $\dfrac{1}{2}m{{v}^{2}}$.
The ratio of kinetic energies of masses ${{m}_{1}}$ and ${{m}_{2}}$,
\[\dfrac{{{E}_{1}}}{{{E}_{2}}}=\dfrac{\dfrac{1}{2}{{m}_{1}}{{v}_{1}}^{2}}{\dfrac{1}{2}{{m}_{2}}{{v}_{2}}^{2}}=\dfrac{{{m}_{1}}{{v}_{1}}}{{{m}_{2}}{{v}_{2}}}\dfrac{{{v}_{1}}}{{{v}_{2}}}=\dfrac{{{v}_{1}}}{{{v}_{2}}}=\dfrac{{{m}_{2}}}{{{m}_{1}}}\]
In the above equation, \[\dfrac{{{m}_{1}}{{v}_{1}}}{{{m}_{2}}{{v}_{2}}}=1\] from equation (1).
Thus, the correct answer is D.
Note: This problem is solved using conservation of momentum principle which is a modification of Newton's third law. This is the main principle used in sending rockets to space.
Complete step-by-step solution -
In the question it is given that the particle is stationary initially. Momentum of a particle is defined as the mass of the particle times its velocity. The particle’s initial velocity is 0. Hence, momentum will be zero. The explosion of the particle follows conservation of linear momentum principle. This states that, since no external force is acting on the particle, the momentum of the particle remains constant.
This means, after explosion, the total momentum is zero. The total momentum after explosion is given by,
$m_{1}{{v}_{1}}=m_{2}{{v}_{2}}$ . Here, the negative symbol is because the masses travel in opposite directions after the explosion. From, conservation of momentum, we can conclude that,
\[\begin{align}
& m _{1}{{v}_{1}}=m_{2}{{v}_{2}} \\
& \dfrac{{{m}_{1}}}{{{m}_{2}}}=\dfrac{{{v}_{2}}}{{{v}_{1}}}
\end{align}\] … (1)
The kinetic energy of a particle is defined by the energy that a particle contains due to its motion. The kinetic energy of a particle with mass m and velocity v is given by $\dfrac{1}{2}m{{v}^{2}}$.
The ratio of kinetic energies of masses ${{m}_{1}}$ and ${{m}_{2}}$,
\[\dfrac{{{E}_{1}}}{{{E}_{2}}}=\dfrac{\dfrac{1}{2}{{m}_{1}}{{v}_{1}}^{2}}{\dfrac{1}{2}{{m}_{2}}{{v}_{2}}^{2}}=\dfrac{{{m}_{1}}{{v}_{1}}}{{{m}_{2}}{{v}_{2}}}\dfrac{{{v}_{1}}}{{{v}_{2}}}=\dfrac{{{v}_{1}}}{{{v}_{2}}}=\dfrac{{{m}_{2}}}{{{m}_{1}}}\]
In the above equation, \[\dfrac{{{m}_{1}}{{v}_{1}}}{{{m}_{2}}{{v}_{2}}}=1\] from equation (1).
Thus, the correct answer is D.
Note: This problem is solved using conservation of momentum principle which is a modification of Newton's third law. This is the main principle used in sending rockets to space.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
Give 10 examples for herbs , shrubs , climbers , creepers
10 examples of evaporation in daily life with explanations
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Why is there a time difference of about 5 hours between class 10 social science CBSE