Answer
Verified
461.1k+ views
Hint:- Power of any engine or application is defined as the rate of doing work , or tells about the energy consumption or production per unit of time . For finding the power first we find the value of force and after that we multiply it to the velocity of flowing fluid.
Complete step-by-step solution:-
Power of an engine / pump is defined as how much water it sucks and with what speed it delivers .
Power of a pump is defined in terms of force and velocity as
\[ \Rightarrow P = F.v\]
Where F = force applied & v = velocity of flowing fluid / water.
We know that force is defined as change in momentum (p) per unit time , hence force in terms of mass (m), velocity (v) and time (t) is written as…
\[ \Rightarrow F = \dfrac{{\Delta p}}{{\Delta t}} = \frac{{mv}}{t}\]
Putting the value of force \[F = \dfrac{{mv}}{t}\] , in the the relation \[P = F.v\]
\[ \Rightarrow P = \dfrac{{m{v^2}}}{t}\]; now putting the values of m = 200kg , & v = 2m/s
\[ \Rightarrow P = \dfrac{{m{v^2}}}{t} = \dfrac{{2.100{{(2)}^2}}}{1}\]
Now further solving the relation we get ,
\[ \Rightarrow P = \dfrac{{200.(4)}}{1}\]
Simplifying for the power (P) of the engine ,
\[ \Rightarrow P = 800\;W\]
Since, the power of the engine is 800 W
Hence option (A) is the correct answer.
Note:- If in this case it is said that , engine sucks water from a well eight metre deep and then delivers with the velocity 2m/s and the same amount of water then the rise in potential energy of water is also accounted in power of the engine as this is the engine due to which there is a rise in potential energy of the water.
Complete step-by-step solution:-
Power of an engine / pump is defined as how much water it sucks and with what speed it delivers .
Power of a pump is defined in terms of force and velocity as
\[ \Rightarrow P = F.v\]
Where F = force applied & v = velocity of flowing fluid / water.
We know that force is defined as change in momentum (p) per unit time , hence force in terms of mass (m), velocity (v) and time (t) is written as…
\[ \Rightarrow F = \dfrac{{\Delta p}}{{\Delta t}} = \frac{{mv}}{t}\]
Putting the value of force \[F = \dfrac{{mv}}{t}\] , in the the relation \[P = F.v\]
\[ \Rightarrow P = \dfrac{{m{v^2}}}{t}\]; now putting the values of m = 200kg , & v = 2m/s
\[ \Rightarrow P = \dfrac{{m{v^2}}}{t} = \dfrac{{2.100{{(2)}^2}}}{1}\]
Now further solving the relation we get ,
\[ \Rightarrow P = \dfrac{{200.(4)}}{1}\]
Simplifying for the power (P) of the engine ,
\[ \Rightarrow P = 800\;W\]
Since, the power of the engine is 800 W
Hence option (A) is the correct answer.
Note:- If in this case it is said that , engine sucks water from a well eight metre deep and then delivers with the velocity 2m/s and the same amount of water then the rise in potential energy of water is also accounted in power of the engine as this is the engine due to which there is a rise in potential energy of the water.
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Define the term system surroundings open system closed class 11 chemistry CBSE
Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE