What annual installment will discharge a debt of $Rs.420$ due in $5$ years at $10\% $ SI?
$A)Rs.60$
$B)Rs.70$
$C)Rs.800$
$D)Rs.900$
Answer
Verified
384.9k+ views
Hint: First, assume the annual installment to be $x$ and with the given number of years and rate of interest we can find the amount using a simple interest formula and the sum of the amount after each year gives the debt and solving the $x$ we get the required annual installment.
Complete step-by-step solution:
Since we assume the annual installment to be $x$ . we are given that the debt as $Rs.420$. The number of years is given as $5$
The rate of the given interest is $10\% $
Hence, we know the simple interest formula that is $\dfrac{{pnr}}{{100}}$ where p is the principal amount, n is the time taken and r is the rate of interest.
Hence the amount is given by $p + \dfrac{{pnr}}{{100}}$
Hence the sum of the years from one to five can be calculated using the end of each year with the amount $Rs.420$ and annual installment to be $x$
Thus, we have the sum as $(x + \dfrac{{x \times 1 \times 10}}{{100}}) + (x + \dfrac{{x \times 2 \times 10}}{{100}}) + (x + \dfrac{{x \times 3 \times 10}}{{100}}) + (x + \dfrac{{x \times 4 \times 10}}{{100}}) + x = 420$
At the end of fifth year we don’t have to pay any interest, that's why we have not added the interest for the fifth year. Further solving we have $(x + \dfrac{x}{{10}}) + (x + \dfrac{{2x}}{{10}}) + (x + \dfrac{{3x}}{{10}}) + (x + \dfrac{{4x}}{{10}}) + x = 420$
$(\dfrac{{11x}}{{10}}) + (\dfrac{{12x}}{{10}}) + (\dfrac{{13x}}{{10}}) + (\dfrac{{14x}}{{10}}) + x = 420$
Now cross multiplying we have $\dfrac{{11x + 12x + 13x + 14x + 10x}}{{10}} = 420 \Rightarrow \dfrac{{60x}}{{10}} = 420$
Further solving we have $6x = 420 \Rightarrow x = 70$ (by division operation)
Hence the annual installment is $Rs.70$
Therefore, the option $B)Rs.70$ is correct.
Note: Simple interest is the quickest and easy method of calculating the interest charge on a loan. Simple interest can be determined by multiplying the daily interest rate by the principal by the number of days that elapse between payments.
Annual installments mean a series of amounts to be paid annually over a predetermined period of years in the substantially equal periodic payments, except to the extent any increase in the amount reflects reasonable earnings though the date amount is paid.
Complete step-by-step solution:
Since we assume the annual installment to be $x$ . we are given that the debt as $Rs.420$. The number of years is given as $5$
The rate of the given interest is $10\% $
Hence, we know the simple interest formula that is $\dfrac{{pnr}}{{100}}$ where p is the principal amount, n is the time taken and r is the rate of interest.
Hence the amount is given by $p + \dfrac{{pnr}}{{100}}$
Hence the sum of the years from one to five can be calculated using the end of each year with the amount $Rs.420$ and annual installment to be $x$
Thus, we have the sum as $(x + \dfrac{{x \times 1 \times 10}}{{100}}) + (x + \dfrac{{x \times 2 \times 10}}{{100}}) + (x + \dfrac{{x \times 3 \times 10}}{{100}}) + (x + \dfrac{{x \times 4 \times 10}}{{100}}) + x = 420$
At the end of fifth year we don’t have to pay any interest, that's why we have not added the interest for the fifth year. Further solving we have $(x + \dfrac{x}{{10}}) + (x + \dfrac{{2x}}{{10}}) + (x + \dfrac{{3x}}{{10}}) + (x + \dfrac{{4x}}{{10}}) + x = 420$
$(\dfrac{{11x}}{{10}}) + (\dfrac{{12x}}{{10}}) + (\dfrac{{13x}}{{10}}) + (\dfrac{{14x}}{{10}}) + x = 420$
Now cross multiplying we have $\dfrac{{11x + 12x + 13x + 14x + 10x}}{{10}} = 420 \Rightarrow \dfrac{{60x}}{{10}} = 420$
Further solving we have $6x = 420 \Rightarrow x = 70$ (by division operation)
Hence the annual installment is $Rs.70$
Therefore, the option $B)Rs.70$ is correct.
Note: Simple interest is the quickest and easy method of calculating the interest charge on a loan. Simple interest can be determined by multiplying the daily interest rate by the principal by the number of days that elapse between payments.
Annual installments mean a series of amounts to be paid annually over a predetermined period of years in the substantially equal periodic payments, except to the extent any increase in the amount reflects reasonable earnings though the date amount is paid.
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