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Hint:In the above question, some assertion o-hydroxybenzaldehyde and p-hydroxybenzaldehyde about is given. We are provided with the information about their melting point. We have to check which of the following options suits the best. The basic difference between o-hydroxybenzaldehyde and p-hydroxybenzaldehyde lies in the position of ${\text{ - OH}}$ group with respect to ${\text{ - CHO}}$ group which makes them differ in chemical characteristics as well.
Complete step-by-step answer:Both ortho-hydroxybenzaldehyde (o-hydroxybenzaldehyde) and para-hydroxy benzaldehyde (p-hydroxybenzaldehyde) are the isomers of hydroxyl benzaldehyde. And hence, the molecular weight of the two compounds are the same and both of them show H-bonding. So, the assertion is correct.
In o-hydroxybenzaldehyde, if the ${\text{ - CHO}}$ group is present at 1 location of the benzene ring then ${\text{ - OH}}$ group is present at 2 locations. Due to the presence of H-atoms closer to each other, they show intramolecular hydrogen bonding.
In p-hydroxybenzaldehyde, if the ${\text{ - CHO}}$ group is present at 1 location of the benzene ring then ${\text{ - OH}}$ group is present at 4 locations. Due to absence of H-atoms closer to each other, they show intermolecular hydrogen bonding.
Due to intermolecular hydrogen bonding or the bonding between adjacent molecules, the melting point of p-hydroxybenzaldehyde is more than o-benzaldehyde.
Since, both assertion and reason are correct but reason is not the correct explanation of the assertion.
b>Therefore, the correct option is option B.
Note:Although o-hydroxybenzaldehyde and p-hydroxy benzaldehyde have the same molecular mass and chemical formula, still they differ significantly due to difference in the type of their H-bonding. To answer any question related to ortho and para type question, answer with respect to intermolecular and intermolecular H-bonding.
Complete step-by-step answer:Both ortho-hydroxybenzaldehyde (o-hydroxybenzaldehyde) and para-hydroxy benzaldehyde (p-hydroxybenzaldehyde) are the isomers of hydroxyl benzaldehyde. And hence, the molecular weight of the two compounds are the same and both of them show H-bonding. So, the assertion is correct.
In o-hydroxybenzaldehyde, if the ${\text{ - CHO}}$ group is present at 1 location of the benzene ring then ${\text{ - OH}}$ group is present at 2 locations. Due to the presence of H-atoms closer to each other, they show intramolecular hydrogen bonding.
In p-hydroxybenzaldehyde, if the ${\text{ - CHO}}$ group is present at 1 location of the benzene ring then ${\text{ - OH}}$ group is present at 4 locations. Due to absence of H-atoms closer to each other, they show intermolecular hydrogen bonding.
Due to intermolecular hydrogen bonding or the bonding between adjacent molecules, the melting point of p-hydroxybenzaldehyde is more than o-benzaldehyde.
Since, both assertion and reason are correct but reason is not the correct explanation of the assertion.
b>Therefore, the correct option is option B.
Note:Although o-hydroxybenzaldehyde and p-hydroxy benzaldehyde have the same molecular mass and chemical formula, still they differ significantly due to difference in the type of their H-bonding. To answer any question related to ortho and para type question, answer with respect to intermolecular and intermolecular H-bonding.
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