
Calculate the entropy change when the Ar at 25 \[^\circ C\] and 1 atm in a container at V = 0.50 \[d{m^3}\] is allowed to expand to 100 \[d{m^3}\] simultaneously heated at 100 \[^\circ C\].
Answer
558.6k+ views
Hint: In order to calculate the entropy change of the given Argon gas, we must first have an idea about what an entropy is. Entropy is said to be the measure of disorderliness or randomness present in a molecule of a system.
Complete step by step answer:
Let us understand about entropy. Entropy is referred to as the measure of disorderliness or randomness present in a molecule of a system. Entropy is also said to be a thermodynamic function. It is also a state function that depends on the state of the system and not on the path it followed. Entropy is usually represented by the symbol S, but entropy in the standard state is represented by the symbol \[S^\circ \]. The SI unit of the entropy is found to be \[J{K^{ - 1}}mo{l^{ - 1}}\]. Entropy is said to be an extensive property.
- Let us move onto the problem given. Argon is one of the noble gases and it is a monatomic gas. We can find the entropy change by the following formula:
\[\Delta S = n{C_V}\ln \dfrac{{{T_2}}}{{{T_1}}} + nR\ln \dfrac{{{V_2}}}{{{V_1}}}\]……... (1)
where \[{C_V} = \dfrac{3}{2}R\]
$\rightarrow$ \[{T_1} = 25^\circ C = 298K\]
$\rightarrow$ \[{T_2} = 100^\circ C = 373K\]
$\rightarrow$ \[{V_1} = 0.50d{m^3}\]
$\rightarrow$ \[{V_2} = 100d{m^3}\]
n = 1
Therefore, we can write the equation (1) as
\[\Delta S = 1 \times \dfrac{3}{2}R\ln \dfrac{{373}}{{298}} + 1 \times R\ln \dfrac{{100}}{{0.50}}\]
$\rightarrow$ \[\Delta S = \dfrac{3}{2}R \times 0.224 + R \times 5.298\]
$\rightarrow$ \[\Delta S = 0.336R + 5.298R = 5.634R\]
$\rightarrow$ \[\Delta S = 5.634 \times 8.3J{K^{ - 1}}mo{l^{ - 1}}\]
$\rightarrow$ \[\Delta S = 46.84J{K^{ - 1}}mo{l^{ - 1}}\]
Therefore, the entropy change was found to be \[46.84J{K^{ - 1}}mo{l^{ - 1}}\].
Note: We have to remember that when there is greater disorder or randomness then the entropy will increase. Therefore, gases have greater randomness compared to liquid and solid hence the entropy is greater in gases.
The order of entropy is given as
Gas > liquid > Solid
Complete step by step answer:
Let us understand about entropy. Entropy is referred to as the measure of disorderliness or randomness present in a molecule of a system. Entropy is also said to be a thermodynamic function. It is also a state function that depends on the state of the system and not on the path it followed. Entropy is usually represented by the symbol S, but entropy in the standard state is represented by the symbol \[S^\circ \]. The SI unit of the entropy is found to be \[J{K^{ - 1}}mo{l^{ - 1}}\]. Entropy is said to be an extensive property.
- Let us move onto the problem given. Argon is one of the noble gases and it is a monatomic gas. We can find the entropy change by the following formula:
\[\Delta S = n{C_V}\ln \dfrac{{{T_2}}}{{{T_1}}} + nR\ln \dfrac{{{V_2}}}{{{V_1}}}\]……... (1)
where \[{C_V} = \dfrac{3}{2}R\]
$\rightarrow$ \[{T_1} = 25^\circ C = 298K\]
$\rightarrow$ \[{T_2} = 100^\circ C = 373K\]
$\rightarrow$ \[{V_1} = 0.50d{m^3}\]
$\rightarrow$ \[{V_2} = 100d{m^3}\]
n = 1
Therefore, we can write the equation (1) as
\[\Delta S = 1 \times \dfrac{3}{2}R\ln \dfrac{{373}}{{298}} + 1 \times R\ln \dfrac{{100}}{{0.50}}\]
$\rightarrow$ \[\Delta S = \dfrac{3}{2}R \times 0.224 + R \times 5.298\]
$\rightarrow$ \[\Delta S = 0.336R + 5.298R = 5.634R\]
$\rightarrow$ \[\Delta S = 5.634 \times 8.3J{K^{ - 1}}mo{l^{ - 1}}\]
$\rightarrow$ \[\Delta S = 46.84J{K^{ - 1}}mo{l^{ - 1}}\]
Therefore, the entropy change was found to be \[46.84J{K^{ - 1}}mo{l^{ - 1}}\].
Note: We have to remember that when there is greater disorder or randomness then the entropy will increase. Therefore, gases have greater randomness compared to liquid and solid hence the entropy is greater in gases.
The order of entropy is given as
Gas > liquid > Solid
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

