Answer
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Hint : In this question, we find the wavelength of light which is required to break the two chlorine atoms in a chlorine molecule. Firstly we calculate the energy required to break $\text{Cl-Cl}$ the bond after that we calculate the required wavelength.
Complete step by step answer: We calculate the energy required to break the $\text{Cl-Cl}$ bond and then calculate the wavelength required to break the $\text{Cl-Cl}$ bond.
Given:
\[Cl-Cl\text{ }bonding\text{ }energy=243kJmol{{e}^{-1}}\text{ }\]
Here \[h\] is Planck’s constant
\[h=6.6\times {{10}^{-34}}Js\]
Here \[c\] is the speed of light
\[c=3\times {{10}^{8}}m{{s}^{-1}}\]
\[Avogadros\text{ }number=6.023\times {{10}^{23}}mol{{e}^{-1}}\]
The energy required to break one $\text{Cl-Cl}$ bond,
$=\dfrac{Bond\text{ }energy\text{ }per\text{ }mole}{Avogadros\text{ }number}$
Now we put the value in the formula,
$\Rightarrow \dfrac{243\times {{10}^{3}}}{6.023\times {{10}^{23}}}J$
$\Rightarrow 40.36\times {{10}^{-20}}J$
Let the wavelength of the photon required to break one $\text{Cl-Cl}$ bond be$\lambda $.
\[E=h\nu =h\dfrac{c}{\lambda }\]
After solving we get,
\[\lambda =\dfrac{hc}{E}\]
Now we put the value in the above equation,
$\lambda =\dfrac{(6.6\times {{10}^{-34}}Js)(3\times {{10}^{8}}m{{s}^{-1}})}{40.36\times {{10}^{-20}}J}$
After solving we get,
$\lambda =4.91\times {{10}^{-7}}m$
Here we get the wavelength of light to require to break the bond between two chlorine atoms in a chlorine molecule is$\lambda =4.91\times {{10}^{-7}}m$.
So the correct option is A.
Note: To understand this question we have to study the bond energy. How much energy is required to break the bond $\text{Cl-Cl}$, and the formula is used to find the required energy to break the bond. This question is using the formula \[\lambda =\dfrac{hc}{E}\] to find out the wavelength of light.
Complete step by step answer: We calculate the energy required to break the $\text{Cl-Cl}$ bond and then calculate the wavelength required to break the $\text{Cl-Cl}$ bond.
Given:
\[Cl-Cl\text{ }bonding\text{ }energy=243kJmol{{e}^{-1}}\text{ }\]
Here \[h\] is Planck’s constant
\[h=6.6\times {{10}^{-34}}Js\]
Here \[c\] is the speed of light
\[c=3\times {{10}^{8}}m{{s}^{-1}}\]
\[Avogadros\text{ }number=6.023\times {{10}^{23}}mol{{e}^{-1}}\]
The energy required to break one $\text{Cl-Cl}$ bond,
$=\dfrac{Bond\text{ }energy\text{ }per\text{ }mole}{Avogadros\text{ }number}$
Now we put the value in the formula,
$\Rightarrow \dfrac{243\times {{10}^{3}}}{6.023\times {{10}^{23}}}J$
$\Rightarrow 40.36\times {{10}^{-20}}J$
Let the wavelength of the photon required to break one $\text{Cl-Cl}$ bond be$\lambda $.
\[E=h\nu =h\dfrac{c}{\lambda }\]
After solving we get,
\[\lambda =\dfrac{hc}{E}\]
Now we put the value in the above equation,
$\lambda =\dfrac{(6.6\times {{10}^{-34}}Js)(3\times {{10}^{8}}m{{s}^{-1}})}{40.36\times {{10}^{-20}}J}$
After solving we get,
$\lambda =4.91\times {{10}^{-7}}m$
Here we get the wavelength of light to require to break the bond between two chlorine atoms in a chlorine molecule is$\lambda =4.91\times {{10}^{-7}}m$.
So the correct option is A.
Note: To understand this question we have to study the bond energy. How much energy is required to break the bond $\text{Cl-Cl}$, and the formula is used to find the required energy to break the bond. This question is using the formula \[\lambda =\dfrac{hc}{E}\] to find out the wavelength of light.
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