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How many diagonals are there in a polygon with n sides.

Answer
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Hint: A polygon of n sides should also be having n vertices. By joining any two vertices of a polygon, we obtain either a side of that polygon or a diagonal of that polygon. So calculating with the help of permutation, by taking 2 points at a time, we get the number of lines joining all the points, then subtracting the number of edges we get the total number of diagonals.

Complete step by step answer:

We have to find the numbers of diagonals in the n-sided polygon.
The number of line segments obtained by joining the vertices of a n sided polygon taken two points at a time.
Now, applying the formula and using permutation as below stated.
The number of ways of selecting 2 points at a time from n number of points is given as nC2
As we have nCr=n!r!(nr)!
So we have
nC2 = n!2!(n - 2)!
On simplifying we get,
nC2 = n(n - 1)(n - 2)!2!(n - 2)!
n(n - 1)2

Hence, out of the total selections here n are the sides of the polygon so subtracting that from the total selections, we get,
n(n - 1)2n
On simplifying we get,
n(n - 1) - 2n2
On taking n common from both the terms we get,
n(n - 1 - 2)2n(n - 3)2
Hence , there are total n(n - 3)2 number of diagonals in an n sided polygon.

Note:: Don’t forget to subtract the number of sides while finding the number of diagonals. In geometry, a polygon is a plane figure that is described by a finite number of straight-line segments connected to form a closed polygonal chain or polygonal circuit. The solid plane region, the bounding circuit, or the two together, may be called a polygon. In geometry, a diagonal is a line segment joining two vertices of a polygon or polyhedron, when those vertices are not on the same edge. Informally, any sloping line is called diagonal.
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