Answer
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Hint: In a typical case of two object one pulling another with the rigid link in-between, the higher acceleration of the first result in a higher tension
Here is why
Assume the mass of the first (pulling) object is m1, the mass of the second (pulled) object m2. A solution of the system of two objects is \[ \propto \](The same for both objects in the link between them is rigid) the force moving the first object forward is F and the tension force in a link between two objects is T.
The force of tension acts on the first object against its moment it slows down the object.
Complete Step by Step solutions:
letter to force one acting on the pulling object and another acting on the pulled one, have opposite direction and the same absolute value let's choose the direction of the moment of the positive then the tension force acting on the first object is negative (-T) and the tension force acting on the second object is (T)
Force F, moving the first object forward in a positive sense is directed toward the direction of movement.
The combination of the force acting on the first body is +ve F and -Ve T, the resulting force equals therefore F - T.
F –T = \[{{\text{m}}_{\text{1}}}{\text{.a}}\]
The only force acting on the second object is T. so the second Newton's law gives:
T= \[{{\text{m}}_2}{\text{.a}}\]
Let's all the system equation for a & T assuming that mass \[{{\text{M}}_1}\] and \[{{\text{M}}_2}\] as well as the main force F
\[a = \dfrac{F}{{{m_1} + {m_2}}}\]
\[T = \dfrac{{F.{m_2}}}{{{m_1} + {m_2}}}\]
Additional information:
As we see acceleration is proportional to the force F as well as the tension increased acceleration May only be contributed to increased force F, which causes proportional increase of tension T.
Note:
The tension on an object is equal to the mass of the object × gravitational force plus/minus the mass X acceleration
Here is why
Assume the mass of the first (pulling) object is m1, the mass of the second (pulled) object m2. A solution of the system of two objects is \[ \propto \](The same for both objects in the link between them is rigid) the force moving the first object forward is F and the tension force in a link between two objects is T.
The force of tension acts on the first object against its moment it slows down the object.
Complete Step by Step solutions:
letter to force one acting on the pulling object and another acting on the pulled one, have opposite direction and the same absolute value let's choose the direction of the moment of the positive then the tension force acting on the first object is negative (-T) and the tension force acting on the second object is (T)
Force F, moving the first object forward in a positive sense is directed toward the direction of movement.
The combination of the force acting on the first body is +ve F and -Ve T, the resulting force equals therefore F - T.
F –T = \[{{\text{m}}_{\text{1}}}{\text{.a}}\]
The only force acting on the second object is T. so the second Newton's law gives:
T= \[{{\text{m}}_2}{\text{.a}}\]
Let's all the system equation for a & T assuming that mass \[{{\text{M}}_1}\] and \[{{\text{M}}_2}\] as well as the main force F
\[a = \dfrac{F}{{{m_1} + {m_2}}}\]
\[T = \dfrac{{F.{m_2}}}{{{m_1} + {m_2}}}\]
Additional information:
As we see acceleration is proportional to the force F as well as the tension increased acceleration May only be contributed to increased force F, which causes proportional increase of tension T.
Note:
The tension on an object is equal to the mass of the object × gravitational force plus/minus the mass X acceleration
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