Question

Why is it experimentally difficult to detect neutrinos in nuclear \ [\beta \] - decay?

Answer 1

Hint:Beta decay ( \[\beta \] - decay) in nuclear physics is a method of radioactive decay in the atomic nucleus, converting the initial nuclide into an isobar through the release through beta particles (fast energetic electrons or positrons). For instance, by emission of a neutron followed by an antineutrino, a neutron’s beta decay converts it to a proton, or by emission of a positron with a neutrino in the so-called positron emission a proton is converted to a neutron.

Complete step by Step Solution:
None of the beta or the corresponding (anti-)neutrino are present before beta-decay in the nucleus, but they are produced by decay. In this process, unstable atoms attain a more stable proton-neutron ratio. A nuclear-binding energy determines the possibility of a nuclear decay caused by beta and other modes of decay. The binding energies of all nuclear arms form a band or equilibrium valley
It is impossible to locate neutrinos in \ [\beta \] - decay experimental, since they have no charge with near to zero weight and therefore don't readily interact with something.

Note:Beta decay is a result of the comparatively long decay periods defined by the low force. Nucleons consist of quarks and quarks up and down, and through emission of W boson, a quark may alter its taste through forming an electron / antineutrino or a positron / neutrino pair. For starters, a neutron, composed of two quarks and a quark, decays into a proton consisting of a quark and two quarks.
Electron capture is often referred to as beta decay, as the underlying nuclear mechanism mediated by the weak force is similar. An internal atomic electron is trapped in the electron trap, converted into a neutron by a proton in the nucleus and emitted into an electron neutrino.