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How do you find the x and y-intercept of 4x+8y=12?

Answer
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Hint: This is a linear equation of the first order. In this question, a linear equation is given. We will convert this equation into the form of a straight-line equation. Then put the value of x is equal to 0 to find the y-intercept. Then convert this equation in terms of x. And put the value of y is equal to 0 to find the x-intercept.

Complete step-by-step answer:
In this question, the linear equation is
4x+8y=12
Let us take out 4 as a common factor from both sides.
Therefore,
x+2y=3
Let us subtract x on both sides.
xx+2y=3x
Therefore,
2y=3x
Now, let us divide both sides by 2.
y=3x2
Let us split the denominator.
y=x2+32 ...(1)
Now, to find the value of y-intercept we will put the value of x is 0 in equation (1).
y=02+32
So, the y-intercept is,
y=32
Now, to find the value of x-intercept we will put the value of y as 0 in equation (1).
0=x2+32
Now, find the least common multiple of the denominator on the right-hand side.
 0=x+32
Let us multiply both sides by 2.
0×2=x+32×2
That is equal to
0=x+3
Now, let us add x on both sides.
0+x=x+x+3
So,
x=3

Hence, the value of x-intercept is 3 and the value of y-intercept is32.

Note:
The x-intercept is where a line crosses the x-axis, and the y-intercept is the point where the line crosses the y-axis. In the question, we can say that the value of x-intercept is 3. So, the point on the x-axis is (3,0). And the value of y-intercept is 32. So, the point on the y-axis is (0,32).
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