![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
Fluid is flowing with velocity 4m/s in a cylinder of diameter 8 cm. It is connected to a pipe with its end tip of diameter 2 cm. Calculate the velocity of the fluid at this free end.
A. 4m/s
B. 8m/s
C. 32m/s
D. 64m/s
Answer
474k+ views
Hint: When fluid is flowing through a pipe, the volume has to be conserved per unit time. This means the rate of volume entering must be equal to the rate of exiting. This result is called the equation of continuity which is a very important result of a principle known as Bernoulli’s principle.
Formula used: $\dfrac{dV}{dt} = A_1 v_1 = A_2 v_2$
Complete step-by-step solution
As shown in the above diagram, we have the fluid getting enter in the thicker tube and getting exit from the narrow tube. Now, according to the equation of continuity, $A_1v_1 = A_2v_2$
Given: $d_1 = 8cm \implies A_1 = \dfrac{\pi}{4}(8)^2$
And $d_2 = 2cm \implies A_2 = \dfrac{\pi}{4}(2)^2$
Also $v_1 = 4 m/s$
Hence putting these values in equation $A_1v_1 = A_2v_2$, we get;
$\dfrac{\pi}{4} \times 8^2 \times 4 = \dfrac{\pi}{4} \times 2^2 \times v_2$
$\implies v_2 = 8^2 = 64 m/s$.
Thus, option D. is correct.
Additional information: The term$\dfrac{dV}{dt}$represents the rate of flow of fluid. It means the total volume of fluid flow per unit time. Hence we can calculate this term if we know the variation of volume with time. Equation of continuity plays a very important role in fluid mechanics. Even in the case of varying cross-sectional areas, we could get the point to point relation between area and velocity of the fluid molecule at that point. The measuring area of cross-section is an easier task, compared to the velocity. Hence using this equation, we can analyze the complex situation of the velocity behavior of the fluid.
Note: There are certain assumptions that Bernoulli assumed while deriving this theorem. This includes that fluid must be incompressible and the flow of fluid must be laminar flow. This type of fluid is called an ideal fluid. But practically, it’s very difficult for fluid to behave like an ideal fluid.
Formula used: $\dfrac{dV}{dt} = A_1 v_1 = A_2 v_2$
Complete step-by-step solution
![seo images](https://www.vedantu.com/question-sets/83994d33-c473-468b-88b3-49b3de5db4177265038163260709341.png)
As shown in the above diagram, we have the fluid getting enter in the thicker tube and getting exit from the narrow tube. Now, according to the equation of continuity, $A_1v_1 = A_2v_2$
Given: $d_1 = 8cm \implies A_1 = \dfrac{\pi}{4}(8)^2$
And $d_2 = 2cm \implies A_2 = \dfrac{\pi}{4}(2)^2$
Also $v_1 = 4 m/s$
Hence putting these values in equation $A_1v_1 = A_2v_2$, we get;
$\dfrac{\pi}{4} \times 8^2 \times 4 = \dfrac{\pi}{4} \times 2^2 \times v_2$
$\implies v_2 = 8^2 = 64 m/s$.
Thus, option D. is correct.
Additional information: The term$\dfrac{dV}{dt}$represents the rate of flow of fluid. It means the total volume of fluid flow per unit time. Hence we can calculate this term if we know the variation of volume with time. Equation of continuity plays a very important role in fluid mechanics. Even in the case of varying cross-sectional areas, we could get the point to point relation between area and velocity of the fluid molecule at that point. The measuring area of cross-section is an easier task, compared to the velocity. Hence using this equation, we can analyze the complex situation of the velocity behavior of the fluid.
Note: There are certain assumptions that Bernoulli assumed while deriving this theorem. This includes that fluid must be incompressible and the flow of fluid must be laminar flow. This type of fluid is called an ideal fluid. But practically, it’s very difficult for fluid to behave like an ideal fluid.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the value of x if the mode of the following data class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Define least count of vernier callipers How do you class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The combining capacity of an element is known as i class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the image of the point 38 about the line x+3y class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Can anyone list 10 advantages and disadvantages of friction
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Distinguish between Mitosis and Meiosis class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)