
For the line \[\dfrac{{{\text{x - 1}}}}{{\text{1}}}{\text{ = }}\dfrac{{{\text{y - 2}}}}{{\text{2}}}{\text{ = }}\dfrac{{{\text{z - 3}}}}{{\text{3}}}\], which one of the following is incorrect ?
A) The line lies on the plane \[{\text{x - 2y + z = 0}}\]
B) The line is same as \[\dfrac{{\text{x}}}{{\text{1}}}{\text{ = }}\dfrac{{\text{y}}}{{\text{2}}}{\text{ = }}\dfrac{{\text{z}}}{{\text{3}}}\]
C) The line passes through \[{\text{(2,3,5)}}\]
D) The line is parallel to the plane \[{\text{x - 2y + z - 6 = 0}}\]
Answer
493.8k+ views
Hint: First of all, split the given equation of the line and also calculate it’s parametric points so that we can satisfy those points in given equation of plane and verify it. Hence, proceed for the solution by checking out each and every option individually.
Complete step by step solution: Given equation of line \[\dfrac{{{\text{x - 1}}}}{{\text{1}}}{\text{ = }}\dfrac{{{\text{y - 2}}}}{{\text{2}}}{\text{ = }}\dfrac{{{\text{z - 3}}}}{{\text{3}}}\]
Let the given equation of line be represented as \[\dfrac{{{\text{x - 1}}}}{{\text{1}}}{\text{ = }}\dfrac{{{\text{y - 2}}}}{{\text{2}}}{\text{ = }}\dfrac{{{\text{z - 3}}}}{{\text{3}}}{\text{ = k}}\]
Now, simplifying the points (x, y, z) \[{\text{ = (k + 1,2k + 2,3k + 3)}}\]
Now, substitute the value of point in the given equation of plane, for option (a) , we get,
\[
{\text{x - 2y + z = 0}} \\
\Rightarrow {\text{k + 1 - 2(2k + 2) + 3k + 3 = 0}} \\
\Rightarrow {\text{0 = 0}} \\
\]
Hence option (a) is correct.
For option (b) , rearranging the equation of given line
\[\dfrac{{\text{x}}}{{\text{1}}}{\text{ - 1 = }}\dfrac{{\text{y}}}{{\text{2}}}{\text{ - 1 = }}\dfrac{{\text{z}}}{{\text{3}}}{\text{ - 1}}\]
Hence the equation can be presented as , \[\dfrac{{\text{x}}}{{\text{1}}}{\text{ = }}\dfrac{{\text{y}}}{{\text{2}}}{\text{ = }}\dfrac{{\text{z}}}{{\text{3}}}\]
So option (b) is also correct.
Now, for option (c) as ,
\[{\text{(2,3,5)}} \ne {\text{(k + 1,2k + 2,3k + 3)}}\]for any value of k
So option (c) is incorrect .
So, option (c) is our required answer.
Note: A line is a collection of points in space which satisfy an equation. A (geometric) vector can be thought of as "a direction and a magnitude", and can be represented by a single point in space.
Complete step by step solution: Given equation of line \[\dfrac{{{\text{x - 1}}}}{{\text{1}}}{\text{ = }}\dfrac{{{\text{y - 2}}}}{{\text{2}}}{\text{ = }}\dfrac{{{\text{z - 3}}}}{{\text{3}}}\]
Let the given equation of line be represented as \[\dfrac{{{\text{x - 1}}}}{{\text{1}}}{\text{ = }}\dfrac{{{\text{y - 2}}}}{{\text{2}}}{\text{ = }}\dfrac{{{\text{z - 3}}}}{{\text{3}}}{\text{ = k}}\]
Now, simplifying the points (x, y, z) \[{\text{ = (k + 1,2k + 2,3k + 3)}}\]
Now, substitute the value of point in the given equation of plane, for option (a) , we get,
\[
{\text{x - 2y + z = 0}} \\
\Rightarrow {\text{k + 1 - 2(2k + 2) + 3k + 3 = 0}} \\
\Rightarrow {\text{0 = 0}} \\
\]
Hence option (a) is correct.
For option (b) , rearranging the equation of given line
\[\dfrac{{\text{x}}}{{\text{1}}}{\text{ - 1 = }}\dfrac{{\text{y}}}{{\text{2}}}{\text{ - 1 = }}\dfrac{{\text{z}}}{{\text{3}}}{\text{ - 1}}\]
Hence the equation can be presented as , \[\dfrac{{\text{x}}}{{\text{1}}}{\text{ = }}\dfrac{{\text{y}}}{{\text{2}}}{\text{ = }}\dfrac{{\text{z}}}{{\text{3}}}\]
So option (b) is also correct.
Now, for option (c) as ,
\[{\text{(2,3,5)}} \ne {\text{(k + 1,2k + 2,3k + 3)}}\]for any value of k
So option (c) is incorrect .
So, option (c) is our required answer.
Note: A line is a collection of points in space which satisfy an equation. A (geometric) vector can be thought of as "a direction and a magnitude", and can be represented by a single point in space.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Trending doubts
Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Which of the following properties of a proton can change class 12 physics CBSE

What is a transformer Explain the principle construction class 12 physics CBSE

Why is the cell called the structural and functional class 12 biology CBSE
