Answer
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Hint: Three layers (ABCABC...) of hexagonally organised atoms make up a CCP structure. Since they contact six atoms in their layer, plus three atoms in the layer above and three atoms in the layer below, atoms in a CCP configuration have a coordination number of $ 12 $ .
Complete answer:
We know that Copper atoms ( $ Cu $ ) form a CCP (Cubic Close Packed) structure, which is equivalent to an FCC (Face Centered Cubic) arrangement, according to the question.
Amount of copper atoms in a unit cell
$ \Rightarrow \dfrac{1}{8}\left( {Number.of.corners} \right) + \dfrac{1}{2} \times 6 \\
\Rightarrow \dfrac{1}{8}\left( 8 \right) + \dfrac{1}{2} \times 6 \\
\Rightarrow 1 + 3 \\
\Rightarrow 4copper.atoms \\ $
The number of octahedral voids (spaces) equals the number of atoms in the FCC arrangement, which is $ 4 $ .
The Ag atoms appear to be at the centres of the cube's sides since the structure is oriented.
Since Ag has three atoms and a cube has eight corners, the fraction would be $ Ag $ has $ \dfrac{3}{8} $ tetrahedral voids and $ Au $ has $ \dfrac{1}{4} $ octahedral voids.
Hence, the correct option is B) $ Ag $ - $ \dfrac{3}{8} $ the tetrahedral voids; $ Au $ - $ \dfrac{1}{4} $ the octahedral voids.
Note:
Cubic Close Packed (CCP) or Face Centered Cubic (fcc) The same lattice is known by two different names. This cell is created by injecting another atom into each face of a simple cubic lattice, thus the term "face centred cubic."
Complete answer:
We know that Copper atoms ( $ Cu $ ) form a CCP (Cubic Close Packed) structure, which is equivalent to an FCC (Face Centered Cubic) arrangement, according to the question.
Amount of copper atoms in a unit cell
$ \Rightarrow \dfrac{1}{8}\left( {Number.of.corners} \right) + \dfrac{1}{2} \times 6 \\
\Rightarrow \dfrac{1}{8}\left( 8 \right) + \dfrac{1}{2} \times 6 \\
\Rightarrow 1 + 3 \\
\Rightarrow 4copper.atoms \\ $
The number of octahedral voids (spaces) equals the number of atoms in the FCC arrangement, which is $ 4 $ .
The Ag atoms appear to be at the centres of the cube's sides since the structure is oriented.
Since Ag has three atoms and a cube has eight corners, the fraction would be $ Ag $ has $ \dfrac{3}{8} $ tetrahedral voids and $ Au $ has $ \dfrac{1}{4} $ octahedral voids.
Hence, the correct option is B) $ Ag $ - $ \dfrac{3}{8} $ the tetrahedral voids; $ Au $ - $ \dfrac{1}{4} $ the octahedral voids.
Note:
Cubic Close Packed (CCP) or Face Centered Cubic (fcc) The same lattice is known by two different names. This cell is created by injecting another atom into each face of a simple cubic lattice, thus the term "face centred cubic."
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