Answer
Verified
359.7k+ views
Hint: Here we are asked to find the harmonic mean of the roots of the given equation. The harmonic mean of the given values is nothing but the reciprocal of the arithmetic mean of the given values. First, we will find the roots of the given equation since the given equation is a quadratic equation it will have two roots. Then we will find the harmonic equation of those roots using the formula.
Formula Used: If \[\alpha \]and \[\beta \] are the roots then the quadratic equation can be written as\[{x^2} - (\alpha + \beta )x + \alpha \beta = 0\].
The harmonic mean of \[a\]and \[b\]\[ = \dfrac{{2(ab)}}{{a + b}}\]
Complete step-by-step solution:
The given quadratic equation is \[{x^2} - 10x + 11 = 0\] we aim to find the harmonic mean of this equation. For that, we need to first find the roots of this equation. We know that if \[\alpha \]and \[\beta \]are the roots then the quadratic equation can be written as \[{x^2} - (\alpha + \beta )x + \alpha \beta = 0\] . On comparing the given equation with the general equation, we get the sum of the roots \[\alpha + \beta = 10\]and the product of the root\[\alpha \beta = 11\].
And we know that the formula for harmonic mean is \[\dfrac{{2(ab)}}{{a + b}}\], here we need to find the HM of the roots of the given equation that is \[\alpha \]and \[\beta \].
Thus, HM of \[\alpha \]and \[\beta \]\[ = \dfrac{{2(\alpha \beta )}}{{\alpha + \beta }}\]
We already know the values of \[\alpha \beta \] and\[\alpha + \beta \] . Substituting these in the formula we get
HM of \[\alpha \]and \[\beta \] \[ = \dfrac{{2(11)}}{{10}}\]
On simplifying the above, we get
HM of \[\alpha \]and \[ = \dfrac{{11}}{5}\]
Thus, we have found the value of the harmonic mean of the roots of the given equation. Now let’s see the options to find the correct answer.
Option (a) \[\dfrac{1}{5}\] is an incorrect option as we got the HM as \[\dfrac{{11}}{5}\] in or calculation.
Option (b) \[\dfrac{5}{{21}}\] is an incorrect option as we got the HM as \[\dfrac{{11}}{5}\] in or calculation.
Option (c) \[\dfrac{{21}}{{20}}\] is an incorrect option as we got the HM as \[\dfrac{{11}}{5}\] in or calculation.
Option (d) \[\dfrac{{11}}{5}\] is the correct option as we got the same value in our calculation.
Hence, option (d) \[\dfrac{{11}}{5}\] is the correct answer.
Note:We can also find the sum of roots and product of roots of a quadratic equation using the following method: If \[a{x^2} + bx + c = 0\] is a quadratic equation then the sum of its roots \[ = \dfrac{{ - b}}{a}\] and product of its root \[ = \dfrac{c}{a}\].
Formula Used: If \[\alpha \]and \[\beta \] are the roots then the quadratic equation can be written as\[{x^2} - (\alpha + \beta )x + \alpha \beta = 0\].
The harmonic mean of \[a\]and \[b\]\[ = \dfrac{{2(ab)}}{{a + b}}\]
Complete step-by-step solution:
The given quadratic equation is \[{x^2} - 10x + 11 = 0\] we aim to find the harmonic mean of this equation. For that, we need to first find the roots of this equation. We know that if \[\alpha \]and \[\beta \]are the roots then the quadratic equation can be written as \[{x^2} - (\alpha + \beta )x + \alpha \beta = 0\] . On comparing the given equation with the general equation, we get the sum of the roots \[\alpha + \beta = 10\]and the product of the root\[\alpha \beta = 11\].
And we know that the formula for harmonic mean is \[\dfrac{{2(ab)}}{{a + b}}\], here we need to find the HM of the roots of the given equation that is \[\alpha \]and \[\beta \].
Thus, HM of \[\alpha \]and \[\beta \]\[ = \dfrac{{2(\alpha \beta )}}{{\alpha + \beta }}\]
We already know the values of \[\alpha \beta \] and\[\alpha + \beta \] . Substituting these in the formula we get
HM of \[\alpha \]and \[\beta \] \[ = \dfrac{{2(11)}}{{10}}\]
On simplifying the above, we get
HM of \[\alpha \]and \[ = \dfrac{{11}}{5}\]
Thus, we have found the value of the harmonic mean of the roots of the given equation. Now let’s see the options to find the correct answer.
Option (a) \[\dfrac{1}{5}\] is an incorrect option as we got the HM as \[\dfrac{{11}}{5}\] in or calculation.
Option (b) \[\dfrac{5}{{21}}\] is an incorrect option as we got the HM as \[\dfrac{{11}}{5}\] in or calculation.
Option (c) \[\dfrac{{21}}{{20}}\] is an incorrect option as we got the HM as \[\dfrac{{11}}{5}\] in or calculation.
Option (d) \[\dfrac{{11}}{5}\] is the correct option as we got the same value in our calculation.
Hence, option (d) \[\dfrac{{11}}{5}\] is the correct answer.
Note:We can also find the sum of roots and product of roots of a quadratic equation using the following method: If \[a{x^2} + bx + c = 0\] is a quadratic equation then the sum of its roots \[ = \dfrac{{ - b}}{a}\] and product of its root \[ = \dfrac{c}{a}\].
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Which are the Top 10 Largest Countries of the World?
One cusec is equal to how many liters class 8 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
The mountain range which stretches from Gujarat in class 10 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths