Question

How do you graph $y=-\sqrt{4-x^2}$ ?

Answer 1

Hint: A graph of a function f is the set of ordered pairs; the equation of graph is generally represented as $y=f\left(x\right)$ , where x and f(x) are real numbers. We substitute the value of x and we determine the value of y and then we mark the points in the graph and we join the points.

Complete step by step solution:
Here in this question, we have to plot the graph for the given function. A graph of a function is set of ordered pairs and it is represented as $y=f\left(x\right)$ , where x and f(x) are real numbers. These pairs are in the form of cartesian form and the graph is the two-dimensional graph.
First, we have to find the value of y by using the graph equation $y=-\sqrt{4-x^2}$ . Let we substitute the value of x as $0$ , $2$ , and $-2$ .
Now we consider the value of x as $0$ , the value of y is
 $\Rightarrow y=-\sqrt{4-0^2}$
 $\Rightarrow y=-\sqrt{4}=-2$
Now we consider the value of x as $2$ , the value of y is
 $\Rightarrow y=-\sqrt{4-2^2}$
 $\Rightarrow y=0$
Now we consider the value of x as $-2$ , the value of y is
 $\Rightarrow y=-\sqrt{4-{\left(-2\right)}^2}$
 $\Rightarrow y=0$
Now we draw a table for these values we have

x	$0$	$-2$	$2$
y	$-2$	$0$	$0$

The graph plotted for these point is represented below:

Note: The graph plotted is of two dimensional. The graph is plotted in x-axis versus y axis. By the equation of a graph, we can plot the graph by assuming the value of x. We can’t assume the value of y because the value of y depends on the value of x.