![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
How do you graph \[y = \sqrt {x - 1} - 3\]?
Answer
385.8k+ views
Hint: To graph \[y = \sqrt {x - 1} - 3\], we know that the parent function of the functions of the form \[f(x) = \sqrt {x - a} + b\] is \[f(x) = \sqrt x \]. So, we will start with the graph of \[y = \sqrt x \]. Then change \[x\] to \[x - 1\] to obtain \[y = \sqrt {x - 1} \]. Then we will translate the graph \[3\] units down to obtain the graph of \[y = \sqrt {x - 1} - 3\].
Complete step by step answer:
We have to graph \[y = \sqrt {x - 1} - 3\]. We can also write this as \[y - \left( { - 3} \right) = \sqrt {x - 1} \].
The parent function of the functions of the form \[f(x) = \sqrt {x - a} + b\] is \[f(x) = \sqrt x \].
Here, the domain of \[f(x) = \sqrt x \] is \[x \geqslant 0\] and the range is \[y \geqslant 0\].
We can graph \[y = \sqrt x \] as follows:
Now we will move the graph of \[y = \sqrt x \] by \[1\] unit to the right to obtain the graph of \[y = \sqrt {x - 1} \].
So, the graph of \[y = \sqrt {x - 1} \] is given as follows:
Now we will move the graph of \[y = \sqrt {x - 1} \] by \[3\] units down to obtain the graph of \[y = \sqrt {x - 1} - 3\].
Therefore, above graph is the required graph of \[y = \sqrt {x - 1} - 3\].
Here, the domain of \[y = \sqrt {x - 1} - 3\] is \[x \geqslant 1\] and range is \[y \geqslant - 3\].
Note:
Some rules to transform the given graph of a function that we should keep in mind are as follows:
\[(1)\] \[f(x + a)\] horizontally shifts the graph of \[f(x)\] to the left by \[a\] units.
\[(2)\] \[f(x - a)\] horizontally shifts the graph of \[f(x)\] to right by \[a\] units.
\[(3)\] \[f(x) + a\] vertically shifts the graph of \[f(x)\] upward by \[a\] units.
\[(4)\] \[f(x) - a\] vertically shifts the graph of \[f(x)\] downward by \[a\] units.
\[(5)\] \[af(x)\] vertically stretches the graph of \[f(x)\] by a factor of \[a\] units.
\[(6)\] \[\dfrac{{f(x)}}{a}\] vertically shrinks the graph of \[f(x)\] by a factor of \[a\] units.
\[(7)\] \[f(ax)\] horizontally shrinks the graph of \[f(x)\] by a factor of \[a\] units.
\[(8)\] \[f(ax)\] horizontally stretches the graph of \[f(x)\] by a factor of \[a\] units.
Complete step by step answer:
We have to graph \[y = \sqrt {x - 1} - 3\]. We can also write this as \[y - \left( { - 3} \right) = \sqrt {x - 1} \].
The parent function of the functions of the form \[f(x) = \sqrt {x - a} + b\] is \[f(x) = \sqrt x \].
Here, the domain of \[f(x) = \sqrt x \] is \[x \geqslant 0\] and the range is \[y \geqslant 0\].
We can graph \[y = \sqrt x \] as follows:
![seo images](https://www.vedantu.com/question-sets/007ec665-d53d-41e9-9497-d69ff2ee7f411061474442574541108.png)
Now we will move the graph of \[y = \sqrt x \] by \[1\] unit to the right to obtain the graph of \[y = \sqrt {x - 1} \].
So, the graph of \[y = \sqrt {x - 1} \] is given as follows:
![seo images](https://www.vedantu.com/question-sets/f051b799-a3d8-450e-b0eb-da1c39bcc6c78435771163101087862.png)
Now we will move the graph of \[y = \sqrt {x - 1} \] by \[3\] units down to obtain the graph of \[y = \sqrt {x - 1} - 3\].
![seo images](https://www.vedantu.com/question-sets/81e794e0-d7c7-4cc6-bde3-29370445d7e2530384239277513275.png)
Therefore, above graph is the required graph of \[y = \sqrt {x - 1} - 3\].
Here, the domain of \[y = \sqrt {x - 1} - 3\] is \[x \geqslant 1\] and range is \[y \geqslant - 3\].
Note:
Some rules to transform the given graph of a function that we should keep in mind are as follows:
\[(1)\] \[f(x + a)\] horizontally shifts the graph of \[f(x)\] to the left by \[a\] units.
\[(2)\] \[f(x - a)\] horizontally shifts the graph of \[f(x)\] to right by \[a\] units.
\[(3)\] \[f(x) + a\] vertically shifts the graph of \[f(x)\] upward by \[a\] units.
\[(4)\] \[f(x) - a\] vertically shifts the graph of \[f(x)\] downward by \[a\] units.
\[(5)\] \[af(x)\] vertically stretches the graph of \[f(x)\] by a factor of \[a\] units.
\[(6)\] \[\dfrac{{f(x)}}{a}\] vertically shrinks the graph of \[f(x)\] by a factor of \[a\] units.
\[(7)\] \[f(ax)\] horizontally shrinks the graph of \[f(x)\] by a factor of \[a\] units.
\[(8)\] \[f(ax)\] horizontally stretches the graph of \[f(x)\] by a factor of \[a\] units.
Recently Updated Pages
What percentage of the area in India is covered by class 10 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of a 6m wide road outside a garden in all class 10 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the electric flux through a cube of side 1 class 10 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If one root of x2 x k 0 maybe the square of the other class 10 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The radius and height of a cylinder are in the ratio class 10 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
An almirah is sold for 5400 Rs after allowing a discount class 10 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why is there a time difference of about 5 hours between class 10 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What constitutes the central nervous system How are class 10 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Explain the Treaty of Vienna of 1815 class 10 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)