Answer
Verified
449.7k+ views
Hint: We know that, temperature coefficient of a reaction describes the effect of temperature on the reaction rate. It is defined as the ratio of rate constants of two temperatures differ by \[10^\circ {\rm{C}}\].
Complete step by step solution:
We know that, temperature coefficient expression is,
$\dfrac{{k’}_{1}}{k_1}$ = $\dfrac{{{E_a}}}{{2.303\,R}}\left[ {\dfrac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right]$
…… (1)
Here, $\dfrac{{k’}_{1}}{k_1}$is temperature coefficient, ${E_a}$ is activation energy, ${T_2}$
is final temperature, ${T_1}$ is initial temperature and R is gas constant.
For 1st reaction, activation energy is ${E_{{a_1}}}$ and temperature coefficient is $T{C_1}$. Using equation (1), temperature coefficient equation is,
$T{C_1} = \dfrac{{{E_{{a_1}}}}}{{2.303\,R}}\left[ {\dfrac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right]$ …… (2)
For 2nd reaction, activation energy is ${E_{{a_2}}}$ and temperature coefficient is $T{C_2}$. Using equation (1), temperature coefficient equation is,
$T{C_2} = \dfrac{{{E_{{a_2}}}}}{{2.303\,R}}\left[ {\dfrac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right]$ …… (3)
Now, we have to divide equation (2) and (3). We get the following equation on division.
$\dfrac{{T{C_1}}}{{T{C_2}}} = \dfrac{{{E_{{a_1}}}}}{{{E_{{a_2}}}}}$ …… (4)
In the question, it is given that ${E_{{a_1}}} > {E_{{a_2}}}$. So, from equation (4), we can say that $T{C_1} > T{C_2}$.
So, the correct answer is Option 1.
Additional Information:
Let’s learn about the rate of a chemical reaction. Rate or speed of a chemical reaction is the change in concentration of product or reactant in unit time. There are two ways of expressing rate, such as, decreasing of reactant concentration and increase of concentration of product. There are many factors on which rate of a chemical reaction depends, such as temperature, presence of catalyst, concentration of reactant etc.
Note: Rate of a chemical reaction is dependent on the temperature. When the temperature of a chemical reaction is increased by $10^\circ {\rm{C}}$, the rate constant doubles nearly. The dependence of temperature on the rate of reaction is explained by Arrhenius equation.
$k = A{e^{ - {E_a}/RT}}$
Here, k is rate constant, A is Arrhenius factor, ${E_a}$ is activation energy, R is rate constant and T is temperature.
Complete step by step solution:
We know that, temperature coefficient expression is,
$\dfrac{{k’}_{1}}{k_1}$ = $\dfrac{{{E_a}}}{{2.303\,R}}\left[ {\dfrac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right]$
…… (1)
Here, $\dfrac{{k’}_{1}}{k_1}$is temperature coefficient, ${E_a}$ is activation energy, ${T_2}$
is final temperature, ${T_1}$ is initial temperature and R is gas constant.
For 1st reaction, activation energy is ${E_{{a_1}}}$ and temperature coefficient is $T{C_1}$. Using equation (1), temperature coefficient equation is,
$T{C_1} = \dfrac{{{E_{{a_1}}}}}{{2.303\,R}}\left[ {\dfrac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right]$ …… (2)
For 2nd reaction, activation energy is ${E_{{a_2}}}$ and temperature coefficient is $T{C_2}$. Using equation (1), temperature coefficient equation is,
$T{C_2} = \dfrac{{{E_{{a_2}}}}}{{2.303\,R}}\left[ {\dfrac{{{T_2} - {T_1}}}{{{T_1}{T_2}}}} \right]$ …… (3)
Now, we have to divide equation (2) and (3). We get the following equation on division.
$\dfrac{{T{C_1}}}{{T{C_2}}} = \dfrac{{{E_{{a_1}}}}}{{{E_{{a_2}}}}}$ …… (4)
In the question, it is given that ${E_{{a_1}}} > {E_{{a_2}}}$. So, from equation (4), we can say that $T{C_1} > T{C_2}$.
So, the correct answer is Option 1.
Additional Information:
Let’s learn about the rate of a chemical reaction. Rate or speed of a chemical reaction is the change in concentration of product or reactant in unit time. There are two ways of expressing rate, such as, decreasing of reactant concentration and increase of concentration of product. There are many factors on which rate of a chemical reaction depends, such as temperature, presence of catalyst, concentration of reactant etc.
Note: Rate of a chemical reaction is dependent on the temperature. When the temperature of a chemical reaction is increased by $10^\circ {\rm{C}}$, the rate constant doubles nearly. The dependence of temperature on the rate of reaction is explained by Arrhenius equation.
$k = A{e^{ - {E_a}/RT}}$
Here, k is rate constant, A is Arrhenius factor, ${E_a}$ is activation energy, R is rate constant and T is temperature.
Recently Updated Pages
10 Examples of Evaporation in Daily Life with Explanations
10 Examples of Diffusion in Everyday Life
1 g of dry green algae absorb 47 times 10 3 moles of class 11 chemistry CBSE
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
What is the meaning of celestial class 10 social science CBSE
What causes groundwater depletion How can it be re class 10 chemistry CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In the tincture of iodine which is solute and solv class 11 chemistry CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE