Answer
Verified
452.7k+ views
Hint: According to the first law of thermodynamics, the amount of heat energy given to the system equals the summation of total change in internal energy and net work done by the system.
$\Delta H = \Delta U + \Delta W$
But in a cyclic process, the total change in the internal energy of the system is equal to zero.
Complete step-by-step answer:
We know that the heat energy given to the system is converted into the work done and also to increase the internal energy of the system, given by the formula
$\Delta H = \Delta U + \Delta W$
Where,
$\Delta H$= Amount of heat supplied
$\Delta U$= Change in internal energy
$\Delta W$= Net work done
In a cyclic process, the initial and the final state of the system are the same therefore the net change in the internal energy of the system is zero.
$\therefore $$\Delta H = \Delta U + \Delta W$
On putting the value of $\Delta U = 0$we get
$\Delta H = 0 + \Delta W$
$\Delta H = \Delta W$
Therefore the heat supplied to the system becomes equal to the net work done by the system on the surrounding.
Hence the correct option is B.
Note: The amount of heat energy supplied to the system is also equal to the area enclosed under the P-V graph in a thermodynamic cycle. If the cycle is clockwise then work done by the system and if it is counterclockwise then the work done on the system by the surrounding. The work done by the system is considered positive and work done on the system is considered negative.
$\Delta H = \Delta U + \Delta W$
But in a cyclic process, the total change in the internal energy of the system is equal to zero.
Complete step-by-step answer:
We know that the heat energy given to the system is converted into the work done and also to increase the internal energy of the system, given by the formula
$\Delta H = \Delta U + \Delta W$
Where,
$\Delta H$= Amount of heat supplied
$\Delta U$= Change in internal energy
$\Delta W$= Net work done
In a cyclic process, the initial and the final state of the system are the same therefore the net change in the internal energy of the system is zero.
$\therefore $$\Delta H = \Delta U + \Delta W$
On putting the value of $\Delta U = 0$we get
$\Delta H = 0 + \Delta W$
$\Delta H = \Delta W$
Therefore the heat supplied to the system becomes equal to the net work done by the system on the surrounding.
Hence the correct option is B.
Note: The amount of heat energy supplied to the system is also equal to the area enclosed under the P-V graph in a thermodynamic cycle. If the cycle is clockwise then work done by the system and if it is counterclockwise then the work done on the system by the surrounding. The work done by the system is considered positive and work done on the system is considered negative.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Difference Between Plant Cell and Animal Cell
Give 10 examples for herbs , shrubs , climbers , creepers
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Write a letter to the principal requesting him to grant class 10 english CBSE