Question

In each pair of triangles in the following figure, parts bearing identical marks are congruent .State the test and correspondence of vertices by which triangles in each pair are congruent
 $$(a)$$

 $$(b)$$

 $$(c)$$

 $$(d)$$

 $$(e)$$

 $$(f)$$

Answer 1

Hint: In this question we need to check the conditions of two triangles to be congruent. Basically there are five conditions for two triangles to be congruent they are $$\text{SSS(side side side)}$$ , $$\text{SAS(side angle side)}$$ , $$\text{ASA(angle side angle)}$$ , $$\text{AAS(angle angle side)}$$ and $$\text{RHS(right angle-hypotenuse-side)}$$ .

Complete answer:
 The triangles are said to be congruent if they are of the same shape and size. We may represent the congruence by the symbol $$\widetilde{\text{=}}$$ . If the two triangles are congruent then their parameters and areas are equal.
 $$\text{(a)}$$

In the above figure in the given $$△ABC$$ and $$△PQR$$
 $$\text{AB=PQ}$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
 $$\text{AC=QR}$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
 $$\text{QC=PR}$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
Here all the corresponding sides are equal in length. Hence it follows $$\text{SSS (side side side)}$$ property.
THUS, we can say that $$△ABC\widetilde{=}△PQR$$
 $$\text{(b)}$$

In the above figure in the given $$△XYZ$$ and $$△LMN$$
 $$\mathrm{\angle }\text{Y=}\mathrm{\angle }\text{M}$$ $$\text{(}$$ corresponding angles are equal $$\text{)}$$
 $$XY=LM$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
 $$YZ=MN$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
Here all the corresponding sides are equal in length. Hence it follows $$\text{SAS ( side angle side)}$$ property.
THUS, we can say that $$△\text{XYZ}\widetilde{=}△LMN$$
 $$\text{(c)}$$

In the above figure in $$△PQR$$ and $$△STU$$
 $$△\text{QPR=}△T\text{SU}$$ $$\text{(}$$ corresponding angles are equal $$\text{)}$$
 $$\text{PR=ST}$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
 $$△\text{QRP=}△T\text{US}$$ $$\text{(}$$ corresponding angles are equal $$\text{)}$$
Here all the corresponding sides are equal in length. Hence it follows $$\text{ASA (angle side angle)}$$ property.
THUS, we can say that $$△PQR\widetilde{=}△STU$$
 $$\text{(d)}$$

In the above figure in the given $$△BAC$$ and $$△PQR$$
 $$△BAC=△PQR$$ $$\text{(}$$ corresponding angles are right angle $$\text{)}$$
 $$\text{AB=PQ}$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
 $$\text{BC=PR}$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
Here all the corresponding sides are equal in length. Hence it follows $$\text{RHS (right angle- hypotenuse side)}$$ property.
Thus, we can say that $$△BAC\widetilde{=}△PQR$$
 $$\text{(e)}$$

In the above figure in the given $$△DAB$$ and $$△DCB$$
 $$△DAB=△DCB$$ $$\text{(}$$ corresponding angles are equal $$\text{)}$$
 $$△ABD\text{=}△BCD$$ $$\text{(}$$ corresponding angles are equal $$\text{)}$$
 $$\text{BD=BD}$$ $$\text{(}$$ common lines $$\text{)}$$
Here all the corresponding sides are equal in length. Hence it follows $$\text{ASA (angle side angle)}$$ property.
Thus, we can say that $$△DAB\widetilde{=}△DCB$$
 $$\text{(f)}$$

In the above figure in the given $$△LMN\widetilde{=}△PNM$$
 $$\text{LM=PN}$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
 $$\text{LN=PM}$$ $$\text{(}$$ corresponding sides are equal $$\text{)}$$
 $$\text{MN=MN}$$ $$\text{(}$$ common line $$\text{)}$$
Here all the corresponding sides are equal in length. Hence it follows $$\text{SSS (side side side)}$$ property.
THUS, we can say that $$△LMN\widetilde{=}△PNM$$ .

Note:
$$\text{SSA(side side angle) }$$ does not follow congruence property because the unknown side could be located in two different places and $$\text{AAA(angle angle angle)}$$ also not follows the congruence property as both the triangles may be similar but they are not congruent.