Answer
Verified
303.9k+ views
Hint: Here, we are given three coplanar lines and having a common intersecting point O. We are given two angles and the remaining four angles need to be found out. Also, we will use one property i.e. vertically opposite angles are equal. And, all the angles on the same line (i.e. on a straight line) have angles equal to 180 degree. So, using all these, we will get our final output.
Complete step by step answer:
Given that, point O is the intersection point of the three coplanar lines.
Also, from the given figure, it is given that,
\[\angle BOD = {90^ \circ }\] and \[\angle DOF = {50^ \circ }\]
We know that, the lines that lie on the same plane are called coplanar lines. Since, we know that, vertically opposite angles are equal.
This means,
1)\[\angle BOD = {90^ \circ }\]
\[ \Rightarrow \angle BOD = \angle AOC\] (Both are vertically opposite angles)
\[ \Rightarrow \angle AOC = z = {90^ \circ }\]
And,
2)\[\angle DOF = {50^ \circ }\]
\[ \Rightarrow \angle DOF = \angle COE\] (Both are vertically opposite angles)
\[ \Rightarrow \angle COE = y = {50^ \circ }\]
Next, according to the given figure, COD is a line, then
\[ \Rightarrow \angle COF + \angle AOF + \angle FOD = {180^ \circ }\] (As they are linear pair)
Substituting the variables, we will get,
\[ \Rightarrow z + u + \angle FOD = {180^ \circ }\]
Putting the values we know, we will get,
\[ \Rightarrow {90^ \circ } + u + {50^ \circ } = {180^ \circ }\]
On simplifying this, we will get,
\[ \Rightarrow {140^ \circ } + u = {180^ \circ }\]
By using transposing method, we will move the term from LHS to RHS, we will get,
\[ \Rightarrow u = {180^ \circ } - {140^ \circ }\]
\[ \Rightarrow u = {40^ \circ }\]
Last, from figure, we can see that, AOB is a line, then,
\[ \Rightarrow \angle BOE + \angle EOC + \angle COA = {180^ \circ }\]
Substitute this values, we will get,
\[ \Rightarrow x + y + z = {180^ \circ }\]
Using the same way, we will get the value of x.
Another Method:
Since, angle AOF = angle EOB
So, \[u = x = {40^ \circ }\]
Hence, the values of all are: \[x = {40^ \circ }\] , \[y = {50^ \circ }\] , \[z = {90^ \circ }\] and \[u = {40^ \circ }\].
Note: Here, students should remember that, x + y + z+ u + 50° + 90° = 360° and so with this, we can check the answers. Also, we know that vertically opposite angles are equal. In short, any two intersecting lines must lie in the same plane, and therefore be coplanar.
Complete step by step answer:
Given that, point O is the intersection point of the three coplanar lines.
Also, from the given figure, it is given that,
\[\angle BOD = {90^ \circ }\] and \[\angle DOF = {50^ \circ }\]
We know that, the lines that lie on the same plane are called coplanar lines. Since, we know that, vertically opposite angles are equal.
This means,
1)\[\angle BOD = {90^ \circ }\]
\[ \Rightarrow \angle BOD = \angle AOC\] (Both are vertically opposite angles)
\[ \Rightarrow \angle AOC = z = {90^ \circ }\]
And,
2)\[\angle DOF = {50^ \circ }\]
\[ \Rightarrow \angle DOF = \angle COE\] (Both are vertically opposite angles)
\[ \Rightarrow \angle COE = y = {50^ \circ }\]
Next, according to the given figure, COD is a line, then
\[ \Rightarrow \angle COF + \angle AOF + \angle FOD = {180^ \circ }\] (As they are linear pair)
Substituting the variables, we will get,
\[ \Rightarrow z + u + \angle FOD = {180^ \circ }\]
Putting the values we know, we will get,
\[ \Rightarrow {90^ \circ } + u + {50^ \circ } = {180^ \circ }\]
On simplifying this, we will get,
\[ \Rightarrow {140^ \circ } + u = {180^ \circ }\]
By using transposing method, we will move the term from LHS to RHS, we will get,
\[ \Rightarrow u = {180^ \circ } - {140^ \circ }\]
\[ \Rightarrow u = {40^ \circ }\]
Last, from figure, we can see that, AOB is a line, then,
\[ \Rightarrow \angle BOE + \angle EOC + \angle COA = {180^ \circ }\]
Substitute this values, we will get,
\[ \Rightarrow x + y + z = {180^ \circ }\]
Using the same way, we will get the value of x.
Another Method:
Since, angle AOF = angle EOB
So, \[u = x = {40^ \circ }\]
Hence, the values of all are: \[x = {40^ \circ }\] , \[y = {50^ \circ }\] , \[z = {90^ \circ }\] and \[u = {40^ \circ }\].
Note: Here, students should remember that, x + y + z+ u + 50° + 90° = 360° and so with this, we can check the answers. Also, we know that vertically opposite angles are equal. In short, any two intersecting lines must lie in the same plane, and therefore be coplanar.
Recently Updated Pages
In a flask the weight ratio of CH4g and SO2g at 298 class 11 chemistry CBSE
In a flask colourless N2O4 is in equilibrium with brown class 11 chemistry CBSE
In a first order reaction the concentration of the class 11 chemistry CBSE
In a first order reaction the concentration of the class 11 chemistry CBSE
In a fermentation tank molasses solution is mixed with class 11 chemistry CBSE
In a face centred cubic unit cell what is the volume class 11 chemistry CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Difference Between Plant Cell and Animal Cell
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Write a letter to the principal requesting him to grant class 10 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Fill the blanks with proper collective nouns 1 A of class 10 english CBSE
Name 10 Living and Non living things class 9 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE