In halogenation of aromatic hydrocarbon, a halogen carrier is used which is generally a Lewis acid. The main function of this species is to generate the species:
[A] X
[B] ${{X}^{-}}$
[C] ${{X}^{+}}$
[D] $X\centerdot $
Answer
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Hint: To answer this, think about chlorination or bromination of benzene or other benzene derived species. Remember that the reaction proceeds via aromatic electrophilic substitution mechanism. Also, remember that Lewis acids are electron deficient species.
Complete answer:
To answer this, firstly let us discuss the reaction mechanism of halogenation of aromatic hydrocarbons.
Halogenation of aromatic hydrocarbons proceeds through an electrophilic substitution pathway and since it includes aromatic hydrocarbons, the reaction is known as electrophilic aromatic substitution.
For reactive hydrocarbons like phenol, no catalyst is needed but for less reactive benzene derivatives we use a Lewis acid catalyst like $AlC{{l}_{3}},FeC{{l}_{3}},AgB{{r}_{3}}\text{ and ZnC}{{\text{l}}_{3}}$. The use of these catalysts is the formation of highly electrophilic complexes which are attacked by the benzene ring and leads to halogenation.
We know that electrophiles are electron deficient species i.e. they can accept a pair of electrons readily.
Let us see the reaction mechanism to understand it better.
We can understand from the above discussion that the Lewis acid is responsible for the formation of the electrophilic species.
Therefore, the correct answer is option [C] ${{X}^{+}}$
Note:
The Lewis theory states that “Lewis acid is a species which can accept a pair of electrons to form a coordinate covalent bond. Lewis base is a species which can donate a pair of electrons to form a coordinate covalent bond.”
We can describe the characteristics of species which are Lewis acid as-
(i) Molecules containing an atom with incomplete valence shell like $B{{F}_{3}}$.
(ii) Metal atoms or cations having empty or partially filled orbitals like nickel or silver etc.
(iii) The molecule or ion capable of accepting electron pairs by rearrangement of its valence electrons.
(iv) The central atom or some molecule may expand its octet to accommodate electron pairs for example $Si{{F}_{4}}$.
Complete answer:
To answer this, firstly let us discuss the reaction mechanism of halogenation of aromatic hydrocarbons.
Halogenation of aromatic hydrocarbons proceeds through an electrophilic substitution pathway and since it includes aromatic hydrocarbons, the reaction is known as electrophilic aromatic substitution.
For reactive hydrocarbons like phenol, no catalyst is needed but for less reactive benzene derivatives we use a Lewis acid catalyst like $AlC{{l}_{3}},FeC{{l}_{3}},AgB{{r}_{3}}\text{ and ZnC}{{\text{l}}_{3}}$. The use of these catalysts is the formation of highly electrophilic complexes which are attacked by the benzene ring and leads to halogenation.
We know that electrophiles are electron deficient species i.e. they can accept a pair of electrons readily.
Let us see the reaction mechanism to understand it better.
We can understand from the above discussion that the Lewis acid is responsible for the formation of the electrophilic species.
Therefore, the correct answer is option [C] ${{X}^{+}}$
Note:
The Lewis theory states that “Lewis acid is a species which can accept a pair of electrons to form a coordinate covalent bond. Lewis base is a species which can donate a pair of electrons to form a coordinate covalent bond.”
We can describe the characteristics of species which are Lewis acid as-
(i) Molecules containing an atom with incomplete valence shell like $B{{F}_{3}}$.
(ii) Metal atoms or cations having empty or partially filled orbitals like nickel or silver etc.
(iii) The molecule or ion capable of accepting electron pairs by rearrangement of its valence electrons.
(iv) The central atom or some molecule may expand its octet to accommodate electron pairs for example $Si{{F}_{4}}$.
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