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In reaction between phenol and bromine water, the equivalent weight of phenol is obtained by dividing the molecular weight of phenol by:
A.3
B.4
C.5
D.6

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Answer
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Hint: To calculate the equivalent weight of phenol we need to write the reaction of phenol with bromine. The number of atoms of bromine required for the reaction with phenol gives a number of equivalents to be divided with.

Complete step-by-step answer:
Bromine water is basically bromine gas dissolved in water. When phenol reacts with bromine water then 3 moles of bromine reacts with one mole of phenol to form one mole of tri-substituted phenol and 3 moles of hydrogen bromide. The reaction is as follow:
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One molecule of bromine contains 2 atoms of bromines, so the number of atoms that are getting reacted are 6. So we have to divide the molecular mass of phenol with 6 to obtain the equivalent mass.

Additional information: Equivalent weight is the mass of 1 equivalent, which means it is the mass of a given substance that reacts with or combines with or displaces a fixed quantity of another substance. Equivalent weight is the ratio of molecular weight to the n factor, which is also known as valency. The definition of n-factor changes according to the type of compound. For example, in an acid n-factor is the number of protons it gives, for a salt the total number of ions it gives.

Hence the correct option is D.

Note: The n-factor in the above reaction is 6. The molecular mass of phenol is 94 and hence its equivalent weight will be \[15.6{\text{ g e}}{{\text{q}}^ - }\]. The equivalent mass will change if n factor changes for some other reaction.