Question

Reaction of aniline with acetyl chloride in the presence of $$\mathrm{N}\mathrm{a}\mathrm{O}\mathrm{H}$$ gives:
A) acetanilide
B) P-chloroaniline
C) a red eye
D) aniline hydrochloride

Answer 1

Hint: It is known that the nucleophilic reaction of the nitrogen of aromatic amines which bears a lone pair of electrons with haloalkanes and with the acid chlorides is regarded as the nucleophilic substitution reaction.

Complete answer:
Generally, we know that $${\mathrm{S}}_{\mathrm{N}}1$$ and $${\mathrm{S}}_{\mathrm{N}}2$$ are the mechanisms for the nucleophilic substitution reaction in which the bond breaking of the carbon with leaving group and the formation of a new bond with a nucleophile. $${\mathrm{S}}_{\mathrm{N}}1$$ mechanism is a unimolecular reaction where it involves one species in the rate defining step, whereas $${\mathrm{S}}_{\mathrm{N}}2$$ is a bimolecular reaction, it involves two species.
We know that aniline is the primary aromatic amine. The reaction in which aniline reacts with acid chlorides, the final product of the reaction will be N-substituted amine.
Therefore, when we treat aniline with acetyl chloride in the presence of $$\mathrm{N}\mathrm{a}\mathrm{O}\mathrm{H}$$, the formation of acetanilide takes place.
We can write the chemical equation for the reaction carried as follows.

Hence, we can conclude that the correct option is A.

Note: It is known that the reaction of aromatic amine with aliphatic acid chloride or the aliphatic acid anhydride results in the formation of amides. The acetylation reaction is best carried out with acetic anhydride rather than acetyl chloride.