
The force acting on a point charge due to an electric dipole depends upon:
(a) \[F \propto \dfrac{1}{r}\]
(b) \[F \propto \dfrac{1}{{{2^2}}}\]
(c) \[F \propto \dfrac{1}{{{r^3}}}\]
(d) \[F \propto \dfrac{1}{{{r^4}}}\]
Answer
134.1k+ views
Hint: We are asked to find the relation between the force acting on a point charge due to a dipole and the its relation with the dipole. We can start by writing down the formula for the electric field due to an electric dipole and use the relation between electric field and electric force and establish a relation between electric force and distance to find our solution.
Formulas used:
1. The electric field due to an electric dipole is given by the formula,
\[E \propto \dfrac{1}{{{r^3}}}\]
We use this formula as there are two ways of finding the electric field due to an electric dipole. They are along the axis of the electric dipole and perpendicular to it. to the dipole. In either of the cases the end result of proportionality is the same.
2. The relation between electric field and electric force is given by the formula,
\[F = Eq\]
Where \[q\] is the charge
Complete answer:
Let us start by writing down the relation between electric field due to an electric dipole. Which is given by,
\[E \propto \dfrac{1}{{{r^3}}}\]
Now the relation between electric field and electric force is to be noted and it is given by,
\[F = Eq\]
From the two equations above we can conclude that,
\[\dfrac{F}{q} \propto \dfrac{1}{{{r^3}}}\]
Since the charge is also a constant in an electric dipole, we can rewrite the above equation as follows,
\[F \propto \dfrac{1}{{{r^3}}}\]
Which implies that the correct answer is option (c) \[F \propto \dfrac{1}{{{r^3}}}\].
Note: An electric dipole is an arrangement of two charges of equal but opposite magnitudes separated by a distance. An example of an electric dipole is shown below where ‘q’ is the charge.

Formulas used:
1. The electric field due to an electric dipole is given by the formula,
\[E \propto \dfrac{1}{{{r^3}}}\]
We use this formula as there are two ways of finding the electric field due to an electric dipole. They are along the axis of the electric dipole and perpendicular to it. to the dipole. In either of the cases the end result of proportionality is the same.
2. The relation between electric field and electric force is given by the formula,
\[F = Eq\]
Where \[q\] is the charge
Complete answer:
Let us start by writing down the relation between electric field due to an electric dipole. Which is given by,
\[E \propto \dfrac{1}{{{r^3}}}\]
Now the relation between electric field and electric force is to be noted and it is given by,
\[F = Eq\]
From the two equations above we can conclude that,
\[\dfrac{F}{q} \propto \dfrac{1}{{{r^3}}}\]
Since the charge is also a constant in an electric dipole, we can rewrite the above equation as follows,
\[F \propto \dfrac{1}{{{r^3}}}\]
Which implies that the correct answer is option (c) \[F \propto \dfrac{1}{{{r^3}}}\].
Note: An electric dipole is an arrangement of two charges of equal but opposite magnitudes separated by a distance. An example of an electric dipole is shown below where ‘q’ is the charge.

Recently Updated Pages
JEE Main 2025 Session 2 Form Correction (Closed) – What Can Be Edited

What are examples of Chemical Properties class 10 chemistry JEE_Main

JEE Main 2025 Session 2 Schedule Released – Check Important Details Here!

JEE Main 2025 Session 2 Admit Card – Release Date & Direct Download Link

JEE Main 2025 Session 2 Registration (Closed) - Link, Last Date & Fees

JEE Mains Result 2025 NTA NIC – Check Your Score Now!

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Wheatstone Bridge for JEE Main Physics 2025

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Diffraction of Light - Young’s Single Slit Experiment

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

JEE Advanced 2024 Syllabus Weightage

JEE Main Chemistry Question Paper with Answer Keys and Solutions
