Answer
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Hint: To solve this question, we need to know the conversion factor of Celsius and Kelvin. After we get to know the conversion factor, we can convert the given temperature to kelvin by using a simple one step conversion.
Formula Used:
We will use the following conversion factor to solve the given stated question.
\[{{1}^{\circ }}C=273.15 K\]
Complete step-by-step answer:According to the question, it is stated that the melting point of silver is $962^{\circ} \text{C}$.
We need to convert the given temperature in Celsius to temperature in kelvin
As stated in the formula, we know that \[{{1}^{\circ }}C\] is equal to \[273.15 K\]
So, we need to find $962^{\circ} \text{C}$ in kelvin.
That can be done as following:
\[{{962}^{\circ }}C=962+273.15=1235.15 K\]
Hence, $962^{\circ} \text{C}$ is equivalent to \[1235.15 K\]
Additional Information:
By international agreement, the centigrade temperature scale is defined in terms of two fixed points; the ice point and the stream point. The temperature is defined as \[{{0}^{\circ }}\]Celsius for the ice point and \[{{100}^{\circ }}\]Celsius for the stream point.
The thermodynamic temperature of the triple point of water fraction \[\dfrac{1}{273.16}\] is the definition of Kelvin. The Kelvin unit is called the Kelvin, or the thermodynamic temperature scale.
Note:Based on thermodynamic principles, Lord Kelvin defined a scale that does not depend on the properties of any particular substance. The interval between ice and steam points was split into \[100\]divisions by Kelvin, so that one kelvin represents the same temperature interval as one degree Celsius. The boiling point on the kelvin scale is \[373 K\], because the Celsius scale was designed so that \[{{100}^{\circ }}C\] is the boiling point of pure water.
Formula Used:
We will use the following conversion factor to solve the given stated question.
\[{{1}^{\circ }}C=273.15 K\]
Complete step-by-step answer:According to the question, it is stated that the melting point of silver is $962^{\circ} \text{C}$.
We need to convert the given temperature in Celsius to temperature in kelvin
As stated in the formula, we know that \[{{1}^{\circ }}C\] is equal to \[273.15 K\]
So, we need to find $962^{\circ} \text{C}$ in kelvin.
That can be done as following:
\[{{962}^{\circ }}C=962+273.15=1235.15 K\]
Hence, $962^{\circ} \text{C}$ is equivalent to \[1235.15 K\]
Additional Information:
By international agreement, the centigrade temperature scale is defined in terms of two fixed points; the ice point and the stream point. The temperature is defined as \[{{0}^{\circ }}\]Celsius for the ice point and \[{{100}^{\circ }}\]Celsius for the stream point.
The thermodynamic temperature of the triple point of water fraction \[\dfrac{1}{273.16}\] is the definition of Kelvin. The Kelvin unit is called the Kelvin, or the thermodynamic temperature scale.
Note:Based on thermodynamic principles, Lord Kelvin defined a scale that does not depend on the properties of any particular substance. The interval between ice and steam points was split into \[100\]divisions by Kelvin, so that one kelvin represents the same temperature interval as one degree Celsius. The boiling point on the kelvin scale is \[373 K\], because the Celsius scale was designed so that \[{{100}^{\circ }}C\] is the boiling point of pure water.
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